Finding The Confidence Interval of a Population Proportion Using The Normal Distribution
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- Опубликовано: 9 сен 2024
- This statistics video tutorial explains how to find the confidence interval of a population proportion using the normal distribution. It also explains how to calculate the margin of error also known as the error bound for the true proportion. it discusses how to calculate the sample size using the margin of error and the z-score. It mentions how to calculate the sample proportion and error from a given confidence interval.
Introduction to Statistics:
• Introduction to Statis...
Introduction to Probability:
• Introduction to Probab...
Central Limit Theorem:
• Central Limit Theorem ...
Standard Error of The Mean:
• Standard Error of the ...
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Confidence Intervals & Margin of Error:
• How To Find The Z Scor...
Find The Z-Score Given Confidence Interval:
• How To Find The Z Scor...
How To Calculate The Sample Size:
• How To Calculate The S...
Student's T-Distribution:
• Student's T Distributi...
Confidence Interval-Population Proportion:
• Finding The Confidence...
Chebyshev's Theorem:
• Chebyshev's Theorem
_____________________________________
Hypothesis Testing - Null & Alternative:
• Hypothesis Testing - N...
Type I and Type II Errors:
• How To Identify Type I...
One Tailed and Two Tailed Tests:
• One Tailed and Two Tai...
Test Static For Means & Pop Proportions:
• Test Statistic For Mea...
Hypothesis Testing Problems:
• Hypothesis Testing Pro...
____________________________________
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Why can you reuse p hat for the last part? I thought since we were finding a new sample size, that p hat would change as the sample size is no longer the same.
How much videos do u make???
if anyone can help me i've been stuck on this problem for about 2 days now and what we learned in class is different that what we got for homework the problem is: The life in hours of a 75-watt light bulb is known to approximately normally distributed with
s = 25 hours. A random sample of 62 bulbs has a mean life X = 1014 hours. Construct a 98%
confidence interval for the true population mean of the light bulb. but yeah you see how its different its not the usual problem and the video helped a bit but still stuck
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Hey can you help me how to do this? "estimation of the proportion p for a 99% confidence with a sample size n= 60 and point estimate p^=0.8
yey yey thankyouuu so machh
thank you so much, but I still have one question, what if we have multiple options question in the survey, instead if Yes or No, we have Yes, Maybe and No, do we still use the same equations???
I think for that the question would provides more information that you would need to know
In my class we have been doing z-alpha/2 but here you are doing 1+CL/2 I don’t get it are they the same or do you use them differently?
I know it's probably too late to help you with your class, but I'm going to put this answer here so that other people can see it.
z-alpha/2 and 1+CL /2 are the same thing. If the confidence level is 95% and the interval is two-tailed, this means that the alpha is 0.05 and it needs to be split between each side. So, using a 95% confidence level, we are basically finding the values at 2.5% and 97.5%, a .025 alpha value taken from each side of the distribution. All of this is in service of finding the z value for the equation, which will be at -1.96 and 1.96, for this example.
1+CL /2 is discussing the same information, but from a different direction. You can find the z value with only the top value, and without considering the alpha value itself, by plugging it directly into this equation. Mathematically, (1+.95)/2 = .975, aka 97.5%, which can then be used to find the z values in the same method you would using z-alpha/2.
Hope this helps!
Goat❤
Is there a confidence interval sample proportion?
1:08 I thought we were estimating the binomial distribution with the normal distribution, not the other way around. Am I incorrect?
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Why do we need the Area to the left(97.5%) when it said 95% confidence?
I believe he made a mistake
I think, it works because of the symmetry. You can check the video URL given below. Explained by another person. Please do let know if you think this approach is wrong,
ruclips.net/video/rQsmAg72HDI/видео.html
If in a binomial distribution the variance is np(1-p), shouldn't the variable n (in our case 800) be included in the evaluation of the confidence interval?
I have the same question
thank u sm
What do we do if the lower interval comes out to be negative?
why is the EBP=sqrt(pq/n)? if the EBP is z s/sqrt(n) and in this case we need to find s from a binomial distribution that is sqrt(npq). if we substitute shouldn't it be EMP=z sqrt(pq)?
No, because we are trying the estimate the proportion. So, the proportion (p)
X~N(np,np)(1-p))
So, we are considering sample
Thus, np~N(np(hat),p(hat)*(1-p(hat))(Since the original distribution is normal
Dividing n by both sides
p~N(p(hat),p(hat)*(1-p(hat))
Thanks a lot :-)
How did he get .27 to calculate??
hey can i ask you what is np means?
Can population proportion be expressed as a %
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what happens when you are comparing a number of propotions say 4
Why do we need the Area to the left(97.5%) when it said 95% confidence? That is two side test, so why do you use 97.5%?
I think, it works because of the symmetry. You can check the video URL given below. Explained by another person. Please do let know if you think this approach is wrong,
ruclips.net/video/rQsmAg72HDI/видео.html
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Hi ,
Here is a question, If i test 1000 balls and only 41 leaked , please calculate 90% confidence interval around the estimated proportion conduct hypothesis test @10 % significant level compared to the previous model 5.4 population proportion. Can I email you my question, if so what is your email?