13.2 Colour of complex ions (HL)

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  • Опубликовано: 1 фев 2025

Комментарии • 63

  • @marioarchibald4712
    @marioarchibald4712 9 лет назад +19

    This video is amazing!!!!
    Reading this topic from a textbook made it so confusing but thanks to you I now have a much much better understanding.

    • @MSJChem
      @MSJChem  9 лет назад +3

      Thanks, I'm glad that you found the video helpful.

    • @shreyagupta7193
      @shreyagupta7193 4 года назад

      Brother you are in which class

  • @vasundarasur316
    @vasundarasur316 10 лет назад +6

    Your videos are amazing . I am a new IB chem teacher and I cannot thank you enough for the clarity and the depth of knowledge you have .
    Thanks for posting them.

    • @MSJChem
      @MSJChem  10 лет назад +1

      It's comments like this that make all the time and effort worthwhile, thanks!

  • @crow1999x
    @crow1999x 8 лет назад +19

    i have been trying to get this concept for awhile, this is a great video for really laying it out!! Awesome job!

    • @MSJChem
      @MSJChem  8 лет назад +1

      +Caleb Rowe Thanks for the feedback and I'm glad I could help.

  • @newtonsaha9406
    @newtonsaha9406 Год назад +1

    Thanks bro...to make the video clear understandable.I have searched many to understand the topics clearly but didn't. You have given all the answers what I had in mind in one video.

  • @bangtan-od6st
    @bangtan-od6st 7 лет назад +2

    your explanations are short and precise, really helped to break down the confusing parts of my chemistry textbook, thank you!:)

    • @MSJChem
      @MSJChem  7 лет назад +1

      Glad I could help.

  • @BigDaddyGuagg
    @BigDaddyGuagg 4 года назад +2

    thank so much for your videos, will be a great resource to go over before my chem tests :)

  • @brianyaw1215
    @brianyaw1215 9 лет назад

    Thanks a lot , you just saved my time of reading 5 pages of the textbook which can take more than 5minutes of understanding

    • @MSJChem
      @MSJChem  9 лет назад +2

      +Brian Yaw Thanks for the comment, I'm glad the video was helpful.

  • @fun4120
    @fun4120 3 года назад

    Love it!! They way you explained

  • @Priya-ps8mo
    @Priya-ps8mo 4 года назад +2

    thank you for this video!

  • @Amazing-ik2il
    @Amazing-ik2il 6 лет назад +4

    i love you man

  • @lenvintan98
    @lenvintan98 8 лет назад +2

    thank you so much for this video!! helped a lot with my understanding :)

    • @MSJChem
      @MSJChem  8 лет назад

      +lenvintan98 Glad I could help.

  • @manindersingh-cu2km
    @manindersingh-cu2km 4 года назад +1

    Thnk u sir.. Grt explanation.... Truely loved

    • @MSJChem
      @MSJChem  4 года назад +1

      Glad I could help.

  • @jczaban4195
    @jczaban4195 2 года назад +1

    YOU ARE A GOD

  • @TheChamp91100
    @TheChamp91100 6 лет назад +2

    This was amazing

  • @imamulmalikchowdhury7659
    @imamulmalikchowdhury7659 7 лет назад +1

    Amazing explanation !

  • @barathanurag
    @barathanurag 8 лет назад +4

    very nice video
    thanks a lot

  • @histeeiop7680
    @histeeiop7680 7 лет назад +23

    MSJ awesome
    MSJ sexy voice
    MSJ chem. god

  • @simonvutov7575
    @simonvutov7575 11 месяцев назад

    GOAT

  • @cameronpollett6206
    @cameronpollett6206 5 лет назад +2

    Thanks Mike

  • @laugiuliani7606
    @laugiuliani7606 7 лет назад +1

    Mike, I've got a question. An electron from one of the low energy d orbitals absorves a certain energy, a certain color, that males it "jump" to one of the high energy d orbitals. Now, what happens later on? Does the electron keep in that exited state, or does it jump down back to the low energy d orbitals, librating the same energy, the same color, it had taken before?

    • @MSJChem
      @MSJChem  7 лет назад

      When an electron transitions back down to a lower d orbital it will emit the same amount of energy that it absorbed in the first place.

    • @laugiuliani7606
      @laugiuliani7606 7 лет назад +4

      Mike, thank you for answering. So, you sad that we see the colors that a complex ion reflects. But, according to your answer, shoudn't we also see the foton that the high energy electron emits when it jumps back to a low energy orbital?

  • @mahimapatel8706
    @mahimapatel8706 2 года назад +1

    thank you!

  • @radioactivecow5525
    @radioactivecow5525 5 лет назад +1

    Thanks mike!

  • @climax7260
    @climax7260 3 года назад +2

    Thank you sir.

  • @vinayseth1114
    @vinayseth1114 4 года назад

    One question though-why doesn't the light stop being emitted? What makes it get emitted perpetually?

    • @MSJChem
      @MSJChem  4 года назад

      As long as light is being absorbed, it will be transmitted. In other words, there must be light present for a solution of complex ions to be coloured.

  • @noah19123
    @noah19123 2 года назад +2

    Are you Copper and Tellurium??? Because you're CuTe :))), Mr Mike Sugiyama Jones. Ur videos are very informative 👍 ege

    • @MSJChem
      @MSJChem  2 года назад +2

      Glad I could help!

  • @Alexa3077
    @Alexa3077 3 года назад

    Sir, what happens to the electron that is excited ? How does it return to the ground state?

    • @MSJChem
      @MSJChem  3 года назад +1

      By emitting the energy that it absorbed in the first place.

    • @Alexa3077
      @Alexa3077 3 года назад

      @@MSJChem does it emit the same energy that it absorbed? And does it emit in the form of light? If so, wouldnt the color of that compound become white since it is emitting or reflecting all of the colors?

    • @MSJChem
      @MSJChem  3 года назад

      It will emit the same energy that it absorbed when it returns to the ground state (n=1).
      The energy emitted can be in the form of UV, visible light or IR. The hydrogen visible emission spectrum shows 4 different colours depending on the level to which the electrons transition to.

  • @sollinw
    @sollinw 4 года назад +1

    Wow!

  • @emilioestrada1860
    @emilioestrada1860 8 лет назад +1

    How is complementary colour transmitted?

    • @MSJChem
      @MSJChem  8 лет назад +3

      When light passes through a solution, certain wavelengths are absorbed and certain wavelengths are transmitted (pass through the solution). The wavelengths of light that are transmitted correspond to the complementary colour of the wavelengths of light that are absorbed.
      A more detailed explanation can be found here:
      www.wou.edu/las/physci/ch462/tmcolors.htm

  • @saurav8357
    @saurav8357 8 лет назад +1

    thanks...u r gr8....

    • @MSJChem
      @MSJChem  8 лет назад

      +Saurav Sinha Thanks for the feedback.

  • @kthreatsable
    @kthreatsable 7 лет назад +1

    Where is the link to the practice worksheet?

    • @MSJChem
      @MSJChem  7 лет назад +1

      +Smart&Loving www.msjchem.com

  • @safwanmt23
    @safwanmt23 2 года назад

    gr8

  • @BestofBuzzYT
    @BestofBuzzYT 5 лет назад

    how to make hexaaqua copper 2 ion in lab ? please help me !

    • @MSJChem
      @MSJChem  5 лет назад

      Dissolve copper(II) sulfate pentahydrate in water.

  • @milfing
    @milfing 4 года назад

    THANK YOUUUUUUU

    • @MSJChem
      @MSJChem  4 года назад

      Newer version here:
      ruclips.net/video/8lfc_1FLZnk/видео.html

    • @milfing
      @milfing 4 года назад +1

      @@MSJChem perfect. thank you again.

  • @kamaljeet4693
    @kamaljeet4693 5 лет назад

    Thanks

    • @MSJChem
      @MSJChem  5 лет назад

      You’re welcome.

  • @sfmy9554
    @sfmy9554 4 года назад

    sexy voice!

    • @MSJChem
      @MSJChem  4 года назад

      Well, I've been called a lot of things in my time, but never this!

    • @sfmy9554
      @sfmy9554 4 года назад

      @@MSJChem lol. are you sure? because of that i got addicted to watch and listen to your video! LoL

    • @MSJChem
      @MSJChem  4 года назад

      @@sfmy9554 Thanks hopefully, your chemistry grade will improve.