Wrong Exercise !!! The drawing of your video corresponds to a particular case : a=6/2=3 m Particular case when the distance "a" of "overlapping sides" is equal to half of the side length of the squares. General Case : PS=(3*6)/sqrt(2)+(2*(6-a))/sqrt(2) PS=9*sqrt(2)+(6-a)*sqrt(2) PS=(15-a)*sqrt(2) is the answer. At 1:02, in your drawing, we see that : [bottom-right side of first left square] is on the same line (PR) that [top-left side of the third right square] This is a particular case when 6-a=a @MathandEngineering, you choose a particular case : a=6/2=3 m. Then, your answer is : PS=(15-3)*sqrt(2)=12*sqrt(2)=24*1/sqrt(2)=16,9706 m on average In reality, PS depends on the value of distance 'a" : 0 < a < 6 then : 9*sqrt(2) < PS < 15*sqrt(2)
Ok friend this is not a Wrong Exercise, it's actually correct, I agree with you if you meant to say, I didn't explicitly mention that a is half the length of the side of the square, but the figure is correct I did all the measurements, and I can assure you that a is half the side of the square. Your answer is perfect 💯 but it doesn't contradict the one in the video, you did the solving with out considering the value of a, PS = 16.9704 only validates 12.7279
Diagonal del cuadrado propuesto =d=6√2 → Si prolongamos los lados de los tres cuadrados hasta que corten a PS, vemos que PS=2*d =2*6√2 =12√2 ≈16,97 m. Buen puzle. Gracias y un saludo.
Rien ne prouve que a =3 😢
Wrong Exercise !!!
The drawing of your video corresponds to a particular case : a=6/2=3 m
Particular case when the distance "a" of "overlapping sides" is equal to half of the side length of the squares.
General Case :
PS=(3*6)/sqrt(2)+(2*(6-a))/sqrt(2)
PS=9*sqrt(2)+(6-a)*sqrt(2)
PS=(15-a)*sqrt(2) is the answer.
At 1:02, in your drawing, we see that :
[bottom-right side of first left square] is on the same line (PR) that [top-left side of the third right square]
This is a particular case when 6-a=a
@MathandEngineering, you choose a particular case : a=6/2=3 m. Then, your answer is :
PS=(15-3)*sqrt(2)=12*sqrt(2)=24*1/sqrt(2)=16,9706 m on average
In reality, PS depends on the value of distance 'a" :
0 < a < 6 then :
9*sqrt(2) < PS < 15*sqrt(2)
Ok friend this is not a Wrong Exercise, it's actually correct, I agree with you if you meant to say, I didn't explicitly mention that a is half the length of the side of the square, but the figure is correct I did all the measurements, and I can assure you that a is half the side of the square.
Your answer is perfect 💯 but it doesn't contradict the one in the video, you did the solving with out considering the value of a,
PS = 16.9704 only validates
12.7279
@@MathandEngineering
You should have explicitly mentioned that "a" is half the side length of the square : a=6/2=3 m
Ok friend thanks, I'll do that
Diagonal del cuadrado propuesto =d=6√2 → Si prolongamos los lados de los tres cuadrados hasta que corten a PS, vemos que PS=2*d =2*6√2 =12√2 ≈16,97 m.
Buen puzle. Gracias y un saludo.
Yes friend this is an excellent solution, thanks for sharing
L = 4*6*cos45° = 24/√2
L = 12√2 m ( Solved √ )
👌👌👌