You prolly dont care but if you're stoned like me atm you can stream pretty much all the new series on Instaflixxer. Been watching with my brother for the last couple of days :)
@@sushantaadhikari5929 naah I changed my field of study 😂😂 But I believe convolution of two signals does not leads to signal loss where as multiplication does..... I mean there are some questions where convolution of two signal is not equal to multiplication of two signals. But you are only going to deal with polynomial kind of questions and there multiplication of two signals just works fine Hope it's sufficient! I believe you are in second year electronics student?
Another method to calculate convolution is t^2. 2t. 1 t^2. 3t. 4 Multiply first row with each element by 2nd row each element just like 3t(t^2+2t+1) and lastly add them you'll get same
I'm pretty shocked that no one on the internet knows how to calculate convolution algebraically by just doing the integration. You just need to express your signals in terms of the unit step function do some algebra and bring the whole thing in a special form where you can break the integral into 2 parts (almost like integration by parts).
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Your awesome. You have no idea how long I stressed about this convolution material. Thanks for this.
The Best ever Method. God Bless you and thank you.
You prolly dont care but if you're stoned like me atm you can stream pretty much all the new series on Instaflixxer. Been watching with my brother for the last couple of days :)
@Tripp Davis definitely, I've been using InstaFlixxer for years myself :D
Is this not simple algebraic multiplication of the two signals ? What is the difference bet multplication and convolution?
Thanks a lot mam. This is very much beneficial and God bless you
You are utterly amazing.
Thank you. Isn't it just the multiplication of two polynomials? x(t).y(t) also gives the same result.
What is the difference mam ....
U have just multiplied those two functions....
Result is coming same only....
Brother it's one year now do you have the answer...if you have please provide the answer it would be helpful 🙏
@@suryakumararun5761 brother its one year now , do you get answer about this????
@@sushantaadhikari5929 naah I changed my field of study 😂😂
But I believe convolution of two signals does not leads to signal loss where as multiplication does.....
I mean there are some questions where convolution of two signal is not equal to multiplication of two signals.
But you are only going to deal with polynomial kind of questions and there multiplication of two signals just works fine
Hope it's sufficient!
I believe you are in second year electronics student?
@@suryakumararun5761 haha , no brother , 4th year engineering student from nepal🇳🇵🇳🇵🚩🚩 , its my back paper
@@sushantaadhikari5929 brother its about a year now do you get the answer about this???
Ma'am can you please explain the difference, I mean you just multiplied those 2 signals...then what's convultion?
I never done convolution that way, it interesting that I used the foil method and got the same thing.
Best method to cal convolution.... Thanks mam😊😊
thank you so much...
bestem best method. love from pakistan
Another method to calculate convolution is
t^2. 2t. 1
t^2. 3t. 4
Multiply first row with each element by 2nd row each element just like 3t(t^2+2t+1) and lastly add them you'll get same
you are bestttttt mam
Does this work for transcendental continuous functions?
👍👌this method is good
is this multiplication or convolution?????????
please reply on the doubt of your students!
thx
Very nice
Great
madam, please make a video on integral method
Ha mem
Why aren't we multiplying this? It is same as multiplication...
this is very good i wish you were my teacher wink wink lol
Mem. t^2-2t-1 Hoga to
sign leke chlenge
I'm pretty shocked that no one on the internet knows how to calculate convolution algebraically by just doing the integration. You just need to express your signals in terms of the unit step function do some algebra and bring the whole thing in a special form where you can break the integral into 2 parts (almost like integration by parts).
Hello,
Do you have a video for me where I can watch that ?
no need to draw these boxes, directkly mulitply every term with every term simple mulitplicatin
this method is wrong