I guess if you're in an IMO competition that's the way they want you to do it. But in the real world, I see no reason to break the 48 down. Just stop at a = log(48) / (2*log(4)) And if you need a numerical approximation R or a calculator or whatever can give it to you easily enough: > a=log(48)/(2*log(4)) > a [1] 1.396241 (verify) (4**a) * (4**a) [1] 48
Excelente, meus parabéns
4^2a=48
2a=log48/log4
2a=2+log3/2log2
a=1+log3/4log2
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🎉🎉 very nice @MATHS TUTORIAL ( BL SAHU)
Excelente explicación!! Gracias
You're welcome! I'm glad you found it helpful.
😊
Brilliant, you are deserved to have 10³ likes🙋♂️👍😍
Thank you ♥️🎉
4^a+a=48
4^2a=48
log4^2a=log48=log16×3
log4^2a=log4^2+log3
2a=2log4/log4+log3/log4
a=2/2+log3/2log4
a=1+log3/4log2
a = ????? 1, 2, 3, 5, 8, 10 , 1.5 ???? Mennyi ?
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48=(4^a)(4^a)=(4^a)^2
48=(4^2)^a=16^a
a = log48(base16) ≈ 1.396
Правильна відповідь а= 1+ log ( 3 ) - професор забув скоротити 4 (четвірки)
2
Are you an electrical engineer?
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I guess if you're in an IMO competition that's the way they want you to do it. But in the real world, I see no reason to break the 48 down. Just stop at a = log(48) / (2*log(4))
And if you need a numerical approximation R or a calculator or whatever can give it to you easily enough:
> a=log(48)/(2*log(4))
> a
[1] 1.396241
(verify)
(4**a) * (4**a)
[1] 48
You can also solved it without Log thanks
👌
Jaj nem tudom leírni a problémámat. Azt értem hogy 16 x 3 = 48 DE !! 16 X 16 > 48 Érti mi az én problémám ?
a=1.380