Patrick- Excellent video . I suggest googling 'wheatstone bridge' + 'strain guage' and also using a microcontroller with two A2D input pins that can be set to DIFFERENTIAL mode. Your results should improve. Good luck. I enjoy your videos. I'm subscribed. - Jim
hi there. i tried to use this to control a servomotor. i can command the motor as if i am using a potentiometer but if i am not flexing the sensor, the motor trembles. i wonder if it really does this or did i break the sensor. could i filter out the.tremors? thanks
shaider1982 no, you didn't break it. That's just normal noise. You'd get that from any sensor like a flex sensor. You will need to smooth it out in software (maybe take 5 readings and average them). A capacitor in parallel might also smooth it out..
Patrick Hood-Daniel No, I mean at @2:57 Vout is equal to the voltage drop on R2 ,If you are measuring the drop across flex sensor directly then Vout should be Vin - Vin * ( R1 / (R1+R2) ) because the reference was GND, As far as I understand, the supply voltage is divided into voltage across flex sensor and resistor R2 and by measuring voltage across R2 we determine the range of voltages that flex sensor outputs for various bending positions. To transform the voltage to our desired range we use potentiometers, op amps etc etc.Is my understanding correct ?
Your Pen or whatever it is...
It is simply amazing...
Patrick- Excellent video . I suggest googling 'wheatstone bridge' + 'strain guage' and also using a microcontroller with two A2D input pins that can be set to DIFFERENTIAL mode. Your results should improve.
Good luck. I enjoy your videos. I'm subscribed. - Jim
Does the sensing quality degrade over time as you bend it over and over for years?
I have not tested this item. The manufacturer should have that information in the datasheet for the product.
Will adding a potentiometer require a resistor in the circuit still?
hi there. i tried to use this to control a servomotor. i can command the motor as if i am using a potentiometer but if i am not flexing the sensor, the motor trembles. i wonder if it really does this or did i break the sensor. could i filter out the.tremors? thanks
shaider1982 no, you didn't break it. That's just normal noise. You'd get that from any sensor like a flex sensor. You will need to smooth it out in software (maybe take 5 readings and average them). A capacitor in parallel might also smooth it out..
Hi, can you share the link of Flex sensor, I want to buy it.
Here you go: www.newbiehack.com/categories/newbiehack-sensors-flex-sensor-spectra-symbol#prettyPhoto
@@PatrickHoodDaniel Thanks
what type of pen pencil is that?
you forgot to tell me to subscribe and smash the like button
Vout = Vin (R2 / R1+R2 ) right ?
Vout = Vin * ( R1 / (R1+R2) ) I add the parenthesis to show order of operation.
Patrick Hood-Daniel No, I mean at @2:57 Vout is equal to the voltage drop on R2 ,If you are measuring the drop across flex sensor directly then Vout should be Vin - Vin * ( R1 / (R1+R2) ) because the reference was GND, As far as I understand, the supply voltage is divided into voltage across flex sensor and resistor R2 and by measuring voltage across R2 we determine the range of voltages that flex sensor outputs for various bending positions. To transform the voltage to our desired range we use potentiometers, op amps etc etc.Is my understanding correct ?
Goutham Kolluru yeah, that's it. The formula in the video is wrong as-is.
Árpád Goretity You are all correct. I will correct the video. I used the formula from the datasheet for this flex sensor. Silly me.
No problem, thanks for the video anyway!
Where is possible to buy a flex sensor?
Amazon eddivanhallen
I am distracted by the pen
or just the way u write
God damn youtube commercials are getting out of hand. There is to many.