You know it's a great explanation when it makes you feel like you could have figured it yourself even without having studied the topic. Great job, keep it up :)
Thank you!!! The most cleared explanation to me! This is exactly the same way my professor solved in class and you covered everything he didn’t. Really appreciate
dude my teacher said that i will never understand this if i didnt took the class, i didnt took the class and i still understand this(MA). Sharing my gratitude is the only thing i can do for u lol...
What if the boundary condition u(0,t)=0, but u(L,t) = T? This occurs when one end is held at 0 degrees and the other end is held at a non-zero temperature. Because of this change, all of the cases for X(x) becomes non-trivial, or so I see.
Hey, you have a mistake in your explanation and solution, but you ended up with the correct answer. Correction: when you were integrating to find An, you needed a summation over m sign on the lefthand side, and a double summation over n and m on the right. Only hen can you have the need to say that the integral of sin(..mx)sin(...nx) for m!=n.
The question I'm about to ask doesn't exactly matter, but it's marginally relevant. One of your initial conditions was: u(x, 0) = f(x) I understood that u(x, t) = f(x)g(t) So, shouldn't u(x, 0) = f(x)g(0) = f(x) => g(0) = 1? And, if g(0) = 1, then g(0) = Cn(e^(0)) = 1 => Cn = 1? However, you left Cn constant, and multiplied it by the second constant (Bn) to produce An. I know it doesn't make a difference whether or not your constant is An or Bn, but I do think we should be solving as much about the problem as possible so we have a better understanding of what's really going on...
I'm not too sure why you switched the conditions of the k for the third case but definitely the solution is right so i can't complain. For both of the first 2 cases we had positive lambda but you put -ve lambda for the third case which is very odd without a clear explanation.
10:00 I've taken an ODE class and dont really understand how you got the solution to that ODE, like I dont understand where the cos and sine come from with just a homogeneous with constant coefficients
When you got a solution for T(t) , You could have solved for B_n constant with boundary conditions T(0) = F(x), this would have resulted in B_n = f(x) , Then solution would have been T(t) = f(x)e^(-kn^2pi^2/L^2)t. why didn't you do it.?
accept the Lord Jesus Christ who has not accepted yet because He is coming back ... sanctify more and more inside and outside ... doing works worthy of repentance and leaving worldliness ... leaving the vanities the tinctures, earrings, makeup, enamels , the fashions of hair and clothes, the short and tight clothes because the Lord is Holy and we must be holy in all our way of living "1 Peter 1: 15,16"
The part when he says "Great! so, now I have solved the half of my solution..."
You know it's a great explanation when it makes you feel like you could have figured it yourself even without having studied the topic. Great job, keep it up :)
Thank you!!! The most cleared explanation to me! This is exactly the same way my professor solved in class and you covered everything he didn’t. Really appreciate
Finally, someone explained all the cases of the constant's sign and talked about the Fourier-series-related part!
I wish my teacher made this look so simple weeks ago. Midterm in 4 hours thank you!
After 5 years of my PDE course today I've understood this❤️ Thanks sir.
i thought u were going to copy paste the definition of An based on the fourier series but u fking proved it. you got my like sir
What is the concept if we write condition as Ux(0,t) and Ux(l,t)
??????????
@@besthighlights1093 The ends of the rod are insulated and the flux is zero
@@OM-wl7qe That sounds like an EE answer. In general it's just boundary conditions, could be applied to many different situations.
Thank you, you helped me understand what my professors messy notes could not
By far the best explanation. Thanks a million!
Great explanation of the heat equation. Short, simple, and to the point.
your explanation on how to solve for "An" is much better than the explanation my textbook given, thank you so much for this great video!
Thank you, this really helped me understand the concept and logic of the solution. Very clean video 👌
That was a surprisingly complicated solution.
Okay l can't be the only one who heard 'cup of tea ' here @2:51 .
good work, sir.
Thank you very much, exactly what I was looking for, great for my final year math undergrad exams
Every point is well explained, so helpful
-A student from India.
dude my teacher said that i will never understand this if i didnt took the class, i didnt took the class and i still understand this(MA). Sharing my gratitude is the only thing i can do for u lol...
Praise The Sun glad it was helpful!
this was so, SO well explained, thank you so so much!!!!
The best explanation ever.
This was soo helpful thank you. Just learnt this concept today
Do you have to do the integration to find An or can you just leave it as An in your final answer?
Thank you best explanation, so this concept explain real times in our life for me
Thanks heaps, really helped me a lot
Couldn't have explained this any better sir!
Thanks, a good tutorial, very helpful
Great video! Was stumped on my homework until I saw this!
understood the entire concept just by looking at it once :)
Amazing explanation! Thank you so much!
excellent video I have ever watched
how would you solve for Cn if f(x) is a constant like 14
What is the meaning if we write condition as Ux(0,t) and Ux(x,l)
??????????????
phenomenal explanation
What if the boundary condition u(0,t)=0, but u(L,t) = T?
This occurs when one end is held at 0 degrees and the other end is held at a non-zero temperature.
Because of this change, all of the cases for X(x) becomes non-trivial, or so I see.
Thank u sir I will pray for u.love from Pakistan
in minute 9:50, how do we know that the there's only one case where n=m when expanding the series?
Thank you really helpful. How do you solve if T'' instead of T'. I understand its the same method up to about 14 minutes of this video.
The fact that you did for case 1,2,3 looks like we need some pre-knowledge.
Thanks you sir ji,
Helped me alot.
Thank you very much, very helpful
Great Explanation Sir😇
Thank you, math god.
any one to say me why we take a Separable variable and there function equal to some constant.for example X'/x=T''/t=c (Constant)
Thanks....it's very helpful for me....
Very Clear. Thumbs up!
thank you very much, cannot understand it in the lecture but this video is very useful!!
Thank you so much for this video
Thank you so much! You are awesome!
Perfect! Thanks
Thanks professor
do you have videos on real analysis
I am confused...when do we need to use lambda or lambda square
Thank you
You are my savior
Hey, you have a mistake in your explanation and solution, but you ended up with the correct answer. Correction: when you were integrating to find An, you needed a summation over m sign on the lefthand side, and a double summation over n and m on the right. Only hen can you have the need to say that the integral of sin(..mx)sin(...nx) for m!=n.
Notice that what he got for An using orthogonality is how you find the sin fourier series for f(x)
great video!
after watching this i dont feel stupid anymore when looking at my PDE homework
17:42 “M for mother”.
Thanks alot .i really need wave equation can u explain it please
¡Thank you!
Why do the constants depend on n? Please help
It's just notation. These are subscripts.
for case 1: Are we allowed to use Cosh and Sinh instead of "e"?
yes, it is possible, cos, we can see why not in the definition of hyperbolic functions.
Perfect!!!! Thank you
Thank you very much
Thank you so much sir ❤️❤️❤️
what about solution for three dimensional equation
in the set of boundary conditions, will the solution change drastically if u(L,t)=T0, where T0 is some initial temperature ?
The question I'm about to ask doesn't exactly matter, but it's marginally relevant.
One of your initial conditions was: u(x, 0) = f(x)
I understood that u(x, t) = f(x)g(t)
So, shouldn't u(x, 0) = f(x)g(0) = f(x) => g(0) = 1?
And, if g(0) = 1, then g(0) = Cn(e^(0)) = 1 => Cn = 1?
However, you left Cn constant, and multiplied it by the second constant (Bn) to produce An.
I know it doesn't make a difference whether or not your constant is An or Bn, but I do think we should be solving as much about the problem as possible so we have a better understanding of what's really going on...
Thanks :)
Thanks a lot!
thank you
U are good teacher.
Not difficult with you.
Ut(x, t) - uxx(x, t) =ku??
I'm not too sure why you switched the conditions of the k for the third case but definitely the solution is right so i can't complain. For both of the first 2 cases we had positive lambda but you put -ve lambda for the third case which is very odd without a clear explanation.
I want him to read me Green Eggs and Ham to sleep
Thank you so much 🇩🇿💕
Thnks😙
10:00 I've taken an ODE class and dont really understand how you got the solution to that ODE, like I dont understand where the cos and sine come from with just a homogeneous with constant coefficients
He probably got imaginary numbers so you have to use euler's equation which becomes the cos and sin equation
Eurler expansion. (idk spelling) its very standard in most ode courses
This video only contains the Homogenous Dirichlet Boundary Condition. But, yes its quite helpful.
Thx
top class explanation
Sir wave equition with tree condition solution uplode kr dein please
big like
i love you
you saved me
case 1 , k>0
gotta say what lamda and u actually are
thanks, u made me hate calculus
4:54
how to solve it?
There's no hope on the battlefield )=
Memorize it at this point, they repeat often in this course. We were given a formula sheet with some ODE's solved for this course.
omg such beautiful hands
When you got a solution for T(t) , You could have solved for B_n constant with boundary conditions T(0) = F(x), this would have resulted in B_n = f(x) , Then solution would have been T(t) = f(x)e^(-kn^2pi^2/L^2)t. why didn't you do it.?
Because he got the solution anyways
accept the Lord Jesus Christ who has not accepted yet because He is coming back ... sanctify more and more inside and outside ... doing works worthy of repentance and leaving worldliness ... leaving the vanities the tinctures, earrings, makeup, enamels , the fashions of hair and clothes, the short and tight clothes because the Lord is Holy and we must be holy in all our way of living "1 Peter 1: 15,16"
K
Thank you