At ~min 40, the expression for the refractive index (N=(1-wp2/w2)^1/2 should be given with a capital N. I used n in the video, which I typically reserve for the real part of N. Sorry!
Just a clarification, at 12: 35, you indicated that D = multiplication of the permeabilities plus polarization please let me know whether this is what you meant
At 58:29 shouldn't the complex conjugate be -iw -(tau)w^2? I think the result works, however, because there are sign changes in both numerator and denominator for both the real and imaginary part.
at 1:19:55 , Omega(naught) in this case is not due to restoring force, it is the energy absorbed by the 3d band electrons to transition to the higher energy orbital. in the case of silver it is around 3.9 ev. is that correct ?
My apologies, indeed, the figure shown at min 1:17:52 is incorrect. Generally, the topmost band is the (not completely occupied) conduction band. In the case of gold, it is a sp band. The lower energy band is the band formed by the d-orbitals. The interband transition excites such d electrons into the conduction band.
At ~min 40, the expression for the refractive index (N=(1-wp2/w2)^1/2 should be given with a capital N. I used n in the video, which I typically reserve for the real part of N. Sorry!
At Min 15:00, the acceleration should be m dr2/dt2. My apologies
You're so humble Sir. We, your viewers, sincerely accept your apology. Thank you for the lecture as well, Sir.
Man you are a legend!
Thank you very much! Your lessons are really helping me understand the Permittivity function :)
What the great lecture !
Very helpful!
Also can you provide something covering plasmon resonance. Any form of info would be helpful.
where is the lecture about dispersion relation???
Just a clarification, at 12: 35, you indicated that D = multiplication of the permeabilities plus polarization please let me know whether this is what you meant
From a text I see that d= permeability x E plus polarization
At 58:29 shouldn't the complex conjugate be -iw -(tau)w^2? I think the result works, however, because there are sign changes in both numerator and denominator for both the real and imaginary part.
at 1:19:55 , Omega(naught) in this case is not due to restoring force, it is the energy absorbed by the 3d band electrons to transition to the higher energy orbital. in the case of silver it is around 3.9 ev. is that correct ?
danke! :)
At the end, do you mean electrons can be promoted to the 4p orbitals? (Since 4s orbitals would already be occupied)
My apologies, indeed, the figure shown at min 1:17:52 is incorrect. Generally, the topmost band is the (not completely occupied) conduction band. In the case of gold, it is a sp band. The lower energy band is the band formed by the d-orbitals. The interband transition excites such d electrons into the conduction band.
52:47