just wasted 2 hours of my life in lectures listening to my teacher and i cant make out what they on about, 11mins with you just cleared it up to my understanding. thanks sir
honestly we need more people like you in the school systems. You get to how to go about doing the problems in a very direct and expect manor, thank you so much!
I have to thank you SO much for teaching the acid/base equations this way. It was incredibly helpful. With so many formulas to learn, this method puts everything into perspective and so much easier to understand. FINALLY the pH formulas make sense and are clicking! Thank you thank you!!
THANK YOU SO MUCH! My professor didn't explain this very well even though it will be a major portion of our final exam. I'm so grateful for this easy explanation. I just have to memorize the formulas and I will be golden for the exam. Thank you, thank you, thank you!
Thank you very much,you know I was just trying to understand what I wanted to and go offline but then something touched my heart to say thank you to the person who did this video,because it really helped. Thank you very much May God continue to bless you as you continue doing what you are doing to help others💕😊
Chelseay Helka Thanks for the kind words. Honestly, it takes a lot of practice and self reflection, to be able to figure out how to break this stuff down. I'm glad my method worked for you! Best wishes!
I know this is late, but I noticed there were SEVERAL of you that didn't understand Mr. Post's Step 4. I am right along with you. Seeing that he didn't answer any of the other posts, I took it upon myself to look it up and figure it out. Thought I would share because I know there will be others that are just as confused. Okay, so on step 4 we are also solving for the inverse, or antilog of 10x -11.6 (or maybe just 11.6) Still just a little confused....sigh... Hope this helps. Follow these steps. I have a TI30XIIS scientific calculator and solved it in this manner. 1. Press (2nd) 2. Press (Log) 3. Press (-) 4. Press 11.6 5. Press " ) " to close the parenthesis. 6. Press (=) or (Enter) That gives you the inverse or antilog of -11.6 which gives you 2.51 x10-12. The number of H+.
thank god... i was trying to calculate pH as per my online lecture describes it: pH= -log10(H+) I didn't understand that I didn't need to put in the "10". I spent 30 minutes trying to figure this out before finding you and seeing my error in 5 seconds.
Dear SciencePost: You have to emphasize that those Equations/Formulas are only valid IF and ONLY IF the Temperature is 25-degrees Celsius / Room Temperature, and those equations are not valid if the temperature of Water or Aqueous Solutions is not at 25 Celcius. Thanks for the Video, Sir !
You did a great job on this video. I'm not always sure how to use my T1-84 C Silver Plus calculator. So, why not buy one and do a whole video just on using that? I'm sure you would do an awesome job. Considering there isn't much out there on using the calculator, but you did a better job than most! Thanks. :) BTW, you cleared it all up on this topic. So thanks so much! M.
Mallory Durrick Merlino LOL. Great idea on the video, but I'm not familiar with that one. I literally use one like the screen showed. Check out my other vidson this topic if you need more help. Thanks for tuning in :)
Well, you got me there anyway. Also, the next day, the teacher showed everyone how to find the -log and antilog on their calculators but I learned from you so I didn't need the help. Passed the test too! Final is tomorrow.
KhaoticKlitoris Thanks for the kind words. I actually tried really hard to make that vid simple and thorough, which is not easy. Check these out for extra practice ruclips.net/p/PLNc_BreVXbmoXmonRH7IJAR2RqzKJcZM-
Thank you. This is better than my Science Teacher. Also watching your last video. You said "Dude" so much, I facepalmed everytime near the end of the video XD
how did you get 2.51 x 10-12 on the inverse log? I cant figure out how you calculated this. Can someone please explain this to me? This makes no sense. ;(
Hi, I was just wondering about your answer for [OH-] in the question "Calculate the pOH, [H+] and the [OH-] of a HCl solution with a pH of 3.2?" What I was wondering about, because I am taught to be very specific, is your final answer to [OH-], which you got as 1.58x10^-11 which shouldn't it have been 1.587301587x10^-11 => 1.59x10^-11 (3sf) ?
I wish you would have explained how you calculated step 4. makes no sense to me. im super confused and you dont explain how you calculated that number. i cant get that on my calculator. maybe you calculated wrong?
Omfg thank you so much this has explained everything what my class was talking about!! ;o Like this video have saved me lol cx from my quiz next class XD lol cx but thanks again for this video
![Calculating pH from [OH-] hydroxide Concentration - CLEAR & SIMPLE](http://i.ytimg.com/vi/gn1CgBzShps/mqdefault.jpg)
![Calculating pH from [OH-] hydroxide Concentration - CLEAR & SIMPLE](/img/tr.png)
![Calculating pH & pOH, [H+], [OH-], Acids & Bases CLEAR & SIMPLE](http://i.ytimg.com/vi/eoM1nzYFy8k/mqdefault.jpg)
![Calculations with pH, pOH, Kw, [H+], [OH-]](/img/1.gif)
just wasted 2 hours of my life in lectures listening to my teacher and i cant make out what they on about, 11mins with you just cleared it up to my understanding. thanks sir
Me too🤦🏾♀️
This video honestly saved me from failing my chemistry test! You were so easy to follow, unlike other videos! Thank you so much!!!!
Amber Smith Check out my other pH vids. Thanks for visiting!
You are truly a life saver man. learned more from you in 10 minutes that an hour and a half lecture.
Mark Jackson So cool to hear. Thanks bro.
honestly we need more people like you in the school systems. You get to how to go about doing the problems in a very direct and expect manor, thank you so much!
Learnt more here in 10 minutes than 2 hours at university!
Armend Sadiku university? we study this in school !
BeatWolf 998 Sophomore year we had to learn this for Regular Chemistry
Wait you learnt this in university? I learned it in school
I have to learn it at 8th grade wth
Dad oi
I've been freaking out about this concept for a test I have in an hour and this saved my life thank you so much!
I have a sub for 3 months who had no idea how to do chemistry and you sir have saved my life
I have to thank you SO much for teaching the acid/base equations this way. It was incredibly helpful. With so many formulas to learn, this method puts everything into perspective and so much easier to understand. FINALLY the pH formulas make sense and are clicking! Thank you thank you!!
bless your soul. i have a chem final in less than two hours and you, my sir, have saved my ass.
This was so incredibly helpful. How my teacher explained it made absolutely no sense. Thank you SO much!!!
Nice explanation! Now that we are online learning through zoom, RUclips has become my teacher. Thank you!
You're a blessing my friend!
Filipinogenetics Thanks dude.
hyjfohu
Huge help for a student studying in a foreign country. Cheers!
Thanks for the kind words bro. Best wishes in chem abroad.
Finally!! something easy to follow. Thank you!
Thank you so much for explaining what my teacher assumed was obvious. You explained this so much more clearly than he did.👏
You're helping me pass chemistry thanks dude, this is much appreciated
better explanation than my teacher and textbook!
This helped so much. When my teacher explained it, I felt like he was speaking Chinese or something. I get it now! Thank you!
You are an amazing teacher, I hope you are doing well in life wherever you are now!
THANK YOU SO MUCH you saved me I was so lost with the pH to H+ calculations and I finally know now how to input it into my calculator
wow..you are just awesome you are the kind of people we need in the world.keep it up..educate us we really appreciate it God bless you
THANK YOU SO MUCH! My professor didn't explain this very well even though it will be a major portion of our final exam. I'm so grateful for this easy explanation. I just have to memorize the formulas and I will be golden for the exam. Thank you, thank you, thank you!
It just makes sense all of a sudden. Thanks dude.
Thank you very much,you know I was just trying to understand what I wanted to and go offline but then something touched my heart to say thank you to the person who did this video,because it really helped.
Thank you very much
May God continue to bless you as you continue doing what you are doing to help others💕😊
This has saved me so much time. It was truly helpful. Thank you
Love these vids !! Helping last minute crams
omg thank you so much! Why can't teachers explain it this way...
Chelseay Helka Thanks for the kind words. Honestly, it takes a lot of practice and self reflection, to be able to figure out how to break this stuff down. I'm glad my method worked for you! Best wishes!
:) keep up the amazing work
Thanks sir cleared now
After watching lots of videos finally cleared.
Thank you so much for this video! Helped a lot for a student from New Zealand!
my teacher really fucked up...he left things out that i found here and understand soooooo much better. THANK YOU!!
A good help for the students. Very very thanks.
I know this is late, but I noticed there were SEVERAL of you that didn't understand Mr. Post's Step 4. I am right along with you. Seeing that he didn't answer any of the other posts, I took it upon myself to look it up and figure it out. Thought I would share because I know there will be others that are just as confused. Okay, so on step 4 we are also solving for the inverse, or antilog of 10x -11.6 (or maybe just 11.6) Still just a little confused....sigh... Hope this helps. Follow these steps.
I have a TI30XIIS scientific calculator and solved it in this manner. 1. Press (2nd) 2. Press (Log) 3. Press (-) 4. Press 11.6 5. Press " ) " to close the parenthesis. 6. Press (=) or (Enter) That gives you the inverse or antilog of -11.6 which gives you 2.51 x10-12. The number of H+.
He explained it starting from 6:33
what is 2nd? 😭
Wow. Thanks. I learned a lot. This is the best so far. MCAT is waving.
Thank you! You were a lifesaver with my homework!
That's great to hear! Best wishes keeping up the studies!
Very helpful! My textbook doesn't even have one simple example. THANK YOUUUUU!
thank god... i was trying to calculate pH as per my online lecture describes it: pH= -log10(H+)
I didn't understand that I didn't need to put in the "10". I spent 30 minutes trying to figure this out before finding you and seeing my error in 5 seconds.
So cool to hear. Keep up the studies
Dear SciencePost: You have to emphasize that those Equations/Formulas are only valid IF and ONLY IF the Temperature is 25-degrees Celsius / Room Temperature, and those equations are not valid if the temperature of Water or Aqueous Solutions is not at 25 Celcius. Thanks for the Video, Sir !
Wow, you’re a good teacher. That means I literally just suck at learning chemistry.
Ur awesome u helped me figure out 2 problems on my biology quiz thank u
Dear science post teacher, you are the bomb! Thank you....thank you.,
Thanks. Keep it up
thanks for that!! its more easier to learn this by watching this video
very useful video, which helped me to clear my doubts. many thanks sir I love the way you are talking.
Nuwan Gunawardana So glad that this video helped you. Best wishes in your continued studies.
THANK YOU SOOOOOOO MUCH. YOU ARE A LIFE SAVER
Thank you so much for this video. this was so much more clearer than my book!
modern day hero!
Thanks Steve. Best wishes learning!
great video! Just a heads up for the sig digs.. pH 3.2 is one significant digit so the [H+] should be 6*10^-4 and not 6.3 thanks
Thank you so much for the clear explanation.
You did a great job on this video. I'm not always sure how to use my T1-84 C Silver Plus calculator. So, why not buy one and do a whole video just on using that? I'm sure you would do an awesome job. Considering there isn't much out there on using the calculator, but you did a better job than most! Thanks. :) BTW, you cleared it all up on this topic. So thanks so much! M.
Mallory Durrick Merlino LOL. Great idea on the video, but I'm not familiar with that one. I literally use one like the screen showed. Check out my other vidson this topic if you need more help. Thanks for tuning in :)
Well, you got me there anyway. Also, the next day, the teacher showed everyone how to find the -log and antilog on their calculators but I learned from you so I didn't need the help. Passed the test too! Final is tomorrow.
Thank you! This was so much more simpler than all the other tutorials I watched :)
KhaoticKlitoris Thanks for the kind words. I actually tried really hard to make that vid simple and thorough, which is not easy. Check these out for extra practice ruclips.net/p/PLNc_BreVXbmoXmonRH7IJAR2RqzKJcZM-
finally a lesson i understand!! thanks so much
the spiciest taco Isn't it awesome when it clicks! Check out my acid base playlist ruclips.net/p/PLNc_BreVXbmpkccH08cqtt_67ysJrnT7o
This video helped me a lot...Thanks science post.
Very good and clearly presented
Awesome tutorial man, really cleared some things up for me. Cheers!
Thank you for the great video 🥳 I have been struggling with this, you broke it down perfectly 👌
Thank you. This is better than my Science Teacher. Also watching your last video. You said "Dude" so much, I facepalmed everytime near the end of the video XD
thank you this helped A LOT!!! I feel behind and you helped me get caught up
That's great to hear Chris. Keep up the studies!
OMG YOU ARE A LIFESAVER!!!!!!
May I ask what app you are using? My TI-83 calculator isn't giving me the options you're has. Thank you so much for making such a helpful video.
Procrast Nation Hey there. Thanks for tuning in. The calc your see there is a screenshot of my phone. Glad the video helped!
Holy fuck dude, ur honestly on par with Tyler Dewitt at explaining stuff. I learned more than my teacher does in an hour
how did you get 2.51 x 10-12 on the inverse log? I cant figure out how you calculated this. Can someone please explain this to me? This makes no sense. ;(
Hi, I was just wondering about your answer for [OH-] in the question "Calculate the pOH, [H+] and the [OH-] of a HCl solution with a pH of 3.2?" What I was wondering about, because I am taught to be very specific, is your final answer to [OH-], which you got as 1.58x10^-11 which shouldn't it have been 1.587301587x10^-11 => 1.59x10^-11 (3sf) ?
Thank you so much for clearing this up!
Great vid man thanks a lot ! I understand it !
This helped me a lot! Thank you!
Great video with great explanations!
Thanks u so much sir God bless you there . please sir increase the videos of the questions please sir really I appreciate you a lot sir
Some of the formulas are not used to this day does it still work using them
Thanks! Got an exam tomorrow and I didn't listen to this topic in class cause I hate calculating shits and numbers.
great video, really helped me
Super helpful video!
This really helped a lot, very clear. Thank you very much!
Thank you very much best teacher best video!!
Thanks so much man, I aced my quiz
So stoked to hear that!!!!!
NO ENTIENDO INGLES PERO PERO AUN ASI ME AYUDASTE MUCHISIMO.LOS NUMEROS SON UN IDIOMA UNIVERSAL.SALUDOS DESDE ARGENTINA trank you!
Thanks dude sir, that was really helpful
This has really helped so much thanks
Thank you very much, it served me a lot
wow finally, thank you so much
Thanks duuude. thats rad man
H2oDelirious spotted....
Thx alot btw dude! :D
Thank you Sir, you really helped me.
thanks men. you helped me a lot
can't say how good it feels to finally fucking get this! thank you!!
VERY HELPFULL THANK YOU AND GOD BLESS
wow this extremely helpful, Thank you!
thank you so much!!!! this video really help
Thx dude this helped me understand it
wow am glad with this video i just watched.its interesting
Thank you so much, very helpful.
Diana Rodriguez That is so cool to hear. Check out my other vids too. Best wishes in learning! Be awesome!
I wish you would have explained how you calculated step 4. makes no sense to me. im super confused and you dont explain how you calculated that number. i cant get that on my calculator. maybe you calculated wrong?
How did we get the negative 12 for the [H+] problem?
Very well explained
THANK YOU MY MAN
absolutely helpful
Omfg thank you so much this has explained everything what my class was talking about!! ;o Like this video have saved me lol cx from my quiz next class XD lol cx but thanks again for this video
Great video
This helped so much. Thank you. :)
you tell what buttons to press for step 4, but you dont tell what order to press them in. i cant figure this out. how do you do it? ;(
you just saved me !!!! Thanks
It’s God that sent me here I’m grateful Thankyou so much