Calculate the pH of a Strong Acid and pOH, [H+] & [OH-]

Learn how to QUICKLY calculate the pH, pOH, [H+] and [OH-] of strong acids. A list of strong acids will be given as well as molecular modeling of the dissociation reaction for strong acids. Practice problems will be completed and formulas to solve these problems will be explained.

[@salmaaosman2829]

I haven't seen anyone explain this as simply as you have so THANK YOU

[@AnneSchmidt]

Thanks! Glad the video helped you 👍🏻

[@KumoGhum]

Thank you so much, your so good at explaining i wish my teacher was as good as u

[@AnneSchmidt]

Awww 🥰 thank you! Glad you are finding my videos helpful.

[@soniahshankoti6245]

Simple and straightforward
Easy to understand

[@AnneSchmidt]

Thank you 😊

[@asifulalamc]

Great video! Merry Christmas and Happy Holidays!

[@AnneSchmidt]

Thanks! Have a wonderful holiday season.

[@lallal7528]

Leaving a comment to appreciate the work and the creativity. Helped out

[@AnneSchmidt]

Much appreciated!

[@angeleerivera1690]

Super helpful! Loved the visuals, thank you so much!

[@AnneSchmidt]

Thanks 😊 Great to hear the video was helpful

[@lightdi-gw6gn]

You're so talented! Thx for this video :) 🥰

[@AnneSchmidt]

Aww ☺️ thank you for that!

[@Dodo-ym8cc]

I have a question for Anne Schmidt: What happens to the Kw water equilibrium when a strong acid fully dissociates and you get loads of H+, does it disturb the water Kw equilibrium, if so in what way? Thank you for your time.

[@AnneSchmidt]

Typically only a change in temperature alters the Kw value.

[@Dodo-ym8cc]

@@AnneSchmidt Could there perhaps be an implicit heat component in the Kw equilibrium like for example Kw= [H+] [OH-] / Heat? If you get an abundance of H+ which depletes OH- to the extent that there is "practically" no more OH- left for the abundant H+ to react with, could that increase the heat component thus increase the temperature thus change the Kw constant itself? I never took chemistry that is why i am asking. Thank you Anne for your reply.

[@ltac8194]

Your videos are a god send. Thank you so much. My question is for # 2 . I got log(2.51) = .399673721 and doesn't the ph=-.400 because 3 sig fig and the 9 rounds up?

[@AnneSchmidt]

Thanks! Log calcs have different sig fig rules I discuss in the video.

[@m.veyselakin]

thank you very much ! i liked the video

[@AnneSchmidt]

Glad you liked the video!

[@selwyntiongson70]

How about pkw pka ma'am and the general formula, how to derive it

[@AnneSchmidt]

pKa = - log Ka
10^-pKa = Ka
pKw = - log Kw
10^-pKw = Kw

[@martinakubuo3398]

Thanks a bunch.

[@AnneSchmidt]

You're welcome! ☺️

[@dnyyyyyx1036]

thankkk u so much!!

[@AnneSchmidt]

Great to hear the video was helpful ☺️

[@EmmettMarcet]

Thanks anne

[@AnneSchmidt]

Thank you for the comment. Happy to hear the video helped!

[@selwyntiongson70]

Pink calcu

[@shikamarunara2034]

?

[@charlieropesocks5793]

mister green