From x=1 at t=1 to x=1 at t=3 ...only two scenarios are possible. 1) x =2 at t =2, (right step, probability p) and then x =1 at t=3, (left step, probability 1-p ) ... Total prob for this case = p(1-p) ....... For scenario 2) x =0 at t =2, (left step, probability 1-p) and then x =1 at t=3, (right step, probability 1-p)...Total prob for this case (1-p)²= p²-2p+1 ... Hence total prob combined both the scenarios= p(1-p) + p² -2p+1 = 1-p
What coulf be the cut off for ews category ,sir ?
What about the question 21 and 54
and for obc sir
80.375 obc category, any chance for jrf
Where can I find Official answer key??
Sir please make a video on questions that can be challenged. Doubt in 705062
Yes, i am also in doubt, its answer should be 2p(1-p)
Hmm
Afterall it is 5 marks question, important
From x=1 at t=1 to x=1 at t=3 ...only two scenarios are possible. 1) x =2 at t =2, (right step, probability p) and then x =1 at t=3, (left step, probability 1-p ) ... Total prob for this case = p(1-p) ....... For scenario 2) x =0 at t =2, (left step, probability 1-p) and then x =1 at t=3, (right step, probability 1-p)...Total prob for this case (1-p)²= p²-2p+1 ... Hence total prob combined both the scenarios= p(1-p) + p² -2p+1 = 1-p
@@zeno_opyt2824not agree,koi book ka reference ho to btaiye
also sir,discuss please que. id 705067 & 705068
How to know accepted answers by CSIR??
@@AmanKumar-mh2vh jb aap que. challenge krne ke option pr jaoge to whan already filled kuch options honge,whin ans. key hai
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