Inequalities using mean,median Upper half of element are biggerbthan median, the other half of elements are smaller than median Min < (median.n/2+min.n/2)/n < mean < (median. n/2 + max.n/2)/n < Max
I want to look more into the mathematical proof of going from the ratio of grap to ratio of numbers. I can memorize this procedure, but the concept is not clicking. What can I search up to learn more about this method, or more specifically, the proof of this method and why it works? Thank you!
To get the median for grouped data use cumulative frequencies to find the (n+1/2)th element
Inequalities using mean,median
Upper half of element are biggerbthan median, the other half of elements are smaller than median
Min < (median.n/2+min.n/2)/n < mean < (median. n/2 + max.n/2)/n < Max
I wish they could solve the algebra part of the second question. The solution was quite confusing 😢
The best!!!
❤️❤️❤️
please improve video quality .
I want to look more into the mathematical proof of going from the ratio of grap to ratio of numbers. I can memorize this procedure, but the concept is not clicking. What can I search up to learn more about this method, or more specifically, the proof of this method and why it works? Thank you!
for the problem @25:00
I am failing to understand the range part🥲, But good content in overal
Exactly man! That’s kind of confusing.