Also, can friction coefficient be greater than 1? Counter example regarding the about question: *angle subtended by slope surface of a pile of sand and ground may be greater than 45 deg, along with the condition that, a grain of sand on the surface remains in static equilibrium* vid: ruclips.net/video/7UM5R-oMBHc/видео.html Exactly @ 1:33
highest value of friction coefficient observed is in the range from 2 to 3 in practical conditions... there is no such point of µ can be equal or more than 1 or not...
Also, this may not be a doubt regarding this video but, this is a question I saw in HCV... but the printed answer was unsatisfactory... A 2kg block is held firm with a force 40N against a rough wall. Another horizontal force 15N parallel to the wall and on the block. In which direction will the block move? if it doesn't move, what is the net frictional force on the block? take u=0.5 (friction coefficient) Also, is friction coefficient a tensor?
1. Friction coefficient is a constant parameter not a tensor. 2. answer of hcv to that que is correct what I can recall... because net sliding force on the block is √(15²+20²) and normal reaction on wall is 40N so the net sliding force is acting on body in direction 53° to the horizontal...
But, the body shouldn't feel a tendency to move in the direction of horizontal force of 15N as this is less than the limiting value right? but they said that the block moves in the direction 53 deg. to the horizontal...
you are wrong ! the applied force should be always less than the friction of the body ! In this case Sir said their is no external force was acting on the body the body was having an force which was applied by ground or mgsin(theta) and this is why the block will slightly move ! if it crosses the or equal to the limiting friction
It has been mentioned in the video that, *angle of repose is that angle of inclination of the wedge block at which the block STARTS sliding down the inclined plane*. So, the friction coefficient that is being referred to in the context of angle of repose (4:35) is the *kinetic friction coefficient* ? *if YES*, then, considering the mentioned note on angle of friction,i.e., *angle between total reaction force and normal force vectors when the body is in the VERGE OF SLIDING*, is it true that the magnitude of angle of friction isn't necessarily equal to the magnitude of angle of repose?
Thank you so much sir , the video was excellent , all my doubts are clear now
Also, can friction coefficient be greater than 1?
Counter example regarding the about question:
*angle subtended by slope surface of a pile of sand and ground may be greater than 45 deg, along with the condition that, a grain of sand on the surface remains in static equilibrium*
vid: ruclips.net/video/7UM5R-oMBHc/видео.html
Exactly @ 1:33
highest value of friction coefficient observed is in the range from 2 to 3 in practical conditions... there is no such point of µ can be equal or more than 1 or not...
Also, this may not be a doubt regarding this video but, this is a question I saw in HCV... but the printed answer was unsatisfactory...
A 2kg block is held firm with a force 40N against a rough wall. Another horizontal force 15N parallel to the wall and on the block. In which direction will the block move? if it doesn't move, what is the net frictional force on the block? take u=0.5 (friction coefficient)
Also, is friction coefficient a tensor?
1. Friction coefficient is a constant parameter not a tensor.
2. answer of hcv to that que is correct what I can recall... because net sliding force on the block is √(15²+20²) and normal reaction on wall is 40N so the net sliding force is acting on body in direction 53° to the horizontal...
But, the body shouldn't feel a tendency to move in the direction of horizontal force of 15N as this is less than the limiting value right? but they said that the block moves in the direction 53 deg. to the horizontal...
+SaiKrishna KVMB (eskp) friction will act due to its weight of 20newton
awesome lectures
thanks! got a quick revision.
Superb,awesome , excellent video
kaisa gya jee?
Amazing Explanation Sir
Sir, if the force is applied at some angle with the horizontal then also it's value is tan inverse u
sir i just want to conform that tan invese u is angle friction or lamda is angle of friction
in above case both are same... at the point of sliding...
Happy teachers day sir thanks for saving me !!!!!!!
good lecture
Thank sir❤
good explanation sir .... thanks for the help
Excellent video! Thnx a lot.
Is this enough for competitive?
3:35 unless "it" will exceed the limiting friction, what is "it"
it stands for the friction acting on the block...
Physics Galaxy but limiting friction is Max right? So it definitely has to be the downward force mgsinθ
Wonderfully explained. Thanks.
it is just a superb video
Still enjoying for fresh my mind .You are amazing . God bless you sir
how the block will be at rest if f = mg sin (theta) ? as you have told in previous classes ......for the block be at rest mg sin (theta) < f
you are wrong ! the applied force should be always less than the friction of the body !
In this case Sir said their is no external force was acting on the body the body was having an force which was applied by ground or mgsin(theta) and this is why the block will slightly move ! if it crosses the or equal to the limiting friction
Tqsm sir
It has been mentioned in the video that, *angle of repose is that angle of inclination of the wedge block at which the block STARTS sliding down the inclined plane*.
So, the friction coefficient that is being referred to in the context of angle of repose (4:35) is the *kinetic friction coefficient* ?
*if YES*, then, considering the mentioned note on angle of friction,i.e., *angle between total reaction force and normal force vectors when the body is in the VERGE OF SLIDING*, is it true that the magnitude of angle of friction isn't necessarily equal to the magnitude of angle of repose?
the friction coefficient mentioned in angle of repose is the limiting friction coefficient...
ok! thanks sir
Excelent Thanks!
Excellent
Nice explanation
Sir u r great.
gr8
thanks sir..9/6/24
Hi how's prep going?
sir please introduce 2.5 speed
bruh what was ur rank plz reply???
@@shivamshaw_07 what was yours?
@@varshaa_ Mains 98.5+ percentile
Adv baaki hai abhi
@@shivamshaw_07 20k rank mil gaya
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Sir that f=meuu*n how as come???
Sir pls tell me how to download physics galaxy book pdf in online
Sir I couldn't understand why u took theta equal to angle between mg and mgcostheta so can u please tell as early as possible.🙏🙏🙏
extend the line of mg to the ground and in the right triangle formed check the angles... hope you get it...