Friction

[@rithizx]

HW : w= mg= N
2×10 = 20 N=> Nf
Coefficient of static friction(mu) =0.4
fs = (mu)s× N
= 0.4 × 20
= 8 N
But, even the 4N is acting on the object but the fsmax will cancel the force because it is Self Adjusting Force and the force is the less than fsmax ... 😊

[@AshaKontala]

You are correct

[@diaago9324]

👍👍👍

[@diaago9324]

your the best teacher i have ever listened to
thanks for your helpful teaching

[@ManochaAcademy]

For LIVE Classes, Concept Videos, Quizzes, Mock Tests & Revision Notes please see our Website/App
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[@MAdciTy-v3e]

I think the answer would be 8N because--
M= 2 KG
W= mg
= 2 KG*10 m/s²
= 20N
Coefficient of static friction= 0.4
therefore, 0.4*20N= 8N

[@aritra1183]

Wrong, this is limiting force or f max so to move the block you need more than 8N force the force applied on the block is 4N since friction force is self adjusting it will adjust itself to 4N and cancel the force applied
So the answer is 4N

[@niranjanninja1678]

Thank you sir for clear explanation about friction ❤

[@ManochaAcademy]

You are welcome

[@adebayoadekunle1251]

The frictional force is 8N.
Therefore the applied force, 4N, is not sufficient to move the box.

[@mgopal4927]

Your explanation,teaching is awesome sir. Thanks a lot and lot .....for your service sir.

[@ManochaAcademy]

Welcome

[@OmejeKingsley-vk3qz]

Thanks

[@priyankakotian2651]

I am really glad I found ur channel please keep making such videos now got friction into my head and heart
answer to last question 8N.

[@ManyuotMabor]

Hi I'm Solomon Manyuot Mabor, from south Sudan am so glad for the work you have done ✅✅✅👍👍🎉🎉🎉.

[@ManochaAcademy]

Thanks. Glad it helped you

[@rabiarazan2279]

Fs max is proportionate to weight not normal btw

[@benardbanks7938]

Hi,am benard from Uganda am happy to join you

[@ManochaAcademy]

Thanks Benard! Great to hear you like our videos! Do share it with your friends!

[@arslansattar351]

It's clay in generals. Language .

[@ItsJustAurora.]

This helped me a lot when I was doing exams, Thanks! ❤❤

[@soyaroy-x6u]

The way u taught ch friction now i don't have any doubt in this ch u r superb sirr thankyuu so muchh ❤

[@rohitshastry2007]

This is really a very helpful video. Concept is Crystal Clear.

[@ManochaAcademy]

Glad it was helpful!

[@FunmilayoBunmi]

Well understand thank you sir 👏👏👏

[@cholamwambula140]

This is most wonderful experience explanation, so I like it sir

[@ManochaAcademy]

Glad to hear that

[@ಅರ್ಪಿತಾ-ತ4ಷ]

Why we should not used cos theta instead of tan theta to calculate angle of friction. Sir

[@cubingprince8146]

Same doubt

[@TejashwiniMohankumar]

4 newton is the force of friction for the question sir

[@H.MAriyawathiH.MAriyawathi]

Thank you sir so so much 🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉😊😊😊😊😊😊😊😊😊

[@roshnigupta1306]

Bestt teacher 😊

[@somaarpitha5980]

How you have taken mgsin and mgcos directly,why we get like that please explain in detail

[@navaidsaquibshaikh2382]

Thanking you sir for your effective explanation.

[@ManochaAcademy]

You are most welcome

[@arslansattar351]

Its flight of consistent i air.Height:gravity +force presere iniciated and de inicisted on road and air. Two diodes . ILclined end.

[@arslansattar351]

2

[@sensei0001]

Sir , i am from mars , and your videos are just awesome 🎉❤

[@ShivanandBhandekari]

I am from pluto😂😂😂

[@ShivanandBhandekari]

I am from pluto😂😂😂😂😂

[@kamalrajkhadka123]

Hello sir your explanation is very well
Love from Nepal❣️

[@ManochaAcademy]

Thank you so much 😀

[@MaluitKherkun]

My best teacher

[@ayushmondal8514]

Really understood clearly the topic also enjoyed too....🤩🤩thanks sir for your support ❤❤❤

[@tileshwarkashyap909]

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[@tileshwarkashyap909]

Hello bhai ruclips.net/video/IeYS_FU71Uo/видео.htmlsi=G4DHMwZrzXWV9Ois

[@tileshwarkashyap909]

Hi

[@muhammadkhanmarwat3770]

Nice way of teaching

[@ManochaAcademy]

Thanks for liking

[@OrientMweemba-f2n]

You are a blessing to most students who watches you💯, I thank God that I am of your RUclips follower ❤❤❤❤

[@ManochaAcademy]

Thanks for liking

[@arslansattar351]

Law of flight inertia and clay friction is inverse to one other.

[@arslansattar351]

4

[@arslansattar351]

Bolts are pin apliers for race.break.clutch (pateren at control 14 feet )(28feet)$cale and compos (180 scale:1.3.0 compos:90 balance)

[@TThany]

I like it sir and I understand well the concept of friction. Thanks for you sir😂❤

[@Moviecollection2413]

0

[@_affiliate_animesh]

Bro static friction (fs) is variable means it depends upon the applied force(F) but we know their will be a fs max of a body
Let fs max = 10N
and F = 8 N
Since fs ( not fs max) is a variable force and is equal to applied force (F)
Therefore, fs=8N
i.e., 0

[@arslansattar351]

Batery and temptatire is rule of a moving obstecle .(/@w of movement)

[@arslansattar351]

1

[@GhatkuothBiel]

So wonderful topic

[@vijendran007]

Sir can you please upload vectors addition and subtraction.

[@ManochaAcademy]

We will definitely try to upload more videos soon!

[@vijendran007]

Thank you sir

[@ChiranjiviSanapathi-et7rb]

Thank s sir ❤😊

[@alinazari4356]

World best video ❤️

[@ayushericekka651]

Great Video!!!

[@ManochaAcademy]

Thanks!

[@sudhakarkashyap512]

Can you suggest me a good science book for class 8 and 9

[@FazilVijay-et9md]

Solution is here
Given
Ms=0.4
Mass=2kg
Applied force=4N
Find force of friction
Soln.
N=W
W=Mg
=2x10=20
Msmax=MsxN
=0.4x20
=8N
Hence we need to produce more than 8N.but the Applied force is only 4N ,thus the object can not be moved.And answer for question =8N

[@somtochukwutimothy]

❤

[@pneeharika9-b553]

Sir can you please make a video on tension

[@Wankmen-g1j]

Good morning sir

[@ashokmuthusamy7843]

Thank you

[@pintumukherjee5187]

Thanks a lot sir...ur way of explaining is inexpressible 🙏🙏.
Please bring courses for 11 and 12 sir 😭🙏

[@ManochaAcademy]

Your welcome! Courses for Class 11 are coming in the first week of January!

[@pintumukherjee5187]

@@ManochaAcademy for 12 sir?

[@pintumukherjee5187]

@@ManochaAcademy pls launch courses for 12 also🙏🙏😭

[@sanjeevpandey9251]

Hello sir thank you for explaining this topic i was trying to find this kind of vedio 😊

[@CynthiaObelu]

Why are you not replying people that solve the problem 😢 so that we can know the answer

[@BGgamer-00]

I like your technic fo telling sir

[@rhan9717]

thanks a lot for this amazing explanation! you deserve much respect!

[@dhanalakahmig823]

Kinetic friction is also called as dynamic friction yes or no 🧐🧐🧐

[@AchalaMagreatgoodness]

Please can I get a video of calculation on this

[@sunahangrai3601]

i like this teacher

[@ManochaAcademy]

Thanks

[@aladeyelumuyiwa6781]

Friction opposes motion, not the force.

[@pusparasaayilavan4235]

answer is 4N

[@annetyebale6166]

Wow so interesting

[@ManochaAcademy]

Glad you liked it

[@nilavantidhage1670]

But sir, Tan theta is p/b
P=N and B=limiting
Friction

[@nilavantidhage1670]

14:54

[@geometric3150]

nice video

[@ManochaAcademy]

Thanks

[@sarveshpatil1016]

you are best sir

[@MohammedZulkifilu]

The force of friction between the floor and the block is 8N

[@anitamore-i2e]

In rolling friction 0.02*10N/1m means in the we get it's unit as N/M but frictional force unit is N how is it possible I want to understand and send me the details of the same to attend the class
THANK YOU.

[@sriramulasreelekha2773]

In rolling friction 0.02 x10N/1m means in the final we get it's unit as N/m? But frictional force unit is N, how is it possible?

[@Salman_Hakro]

Sir want a video on exam preparation tips

[@odokenneth3712]

Thank you sir I would like you to make a practical lecture on physics and chemistry Thank you sir

[@ShadabRazi-cd9ip]

Sir , what is fluid friction ?

[@SreehaanChalla]

The answer is 8n

[@gangasakthivelu9979]

Thank you sir

[@syedaqadeerunnisa-q6u]

I understand friction Thank you

[@dinesha4525]

How to calculate coefficient of friction?

[@arslansattar351]

Force and mas remain gravited this state any build ups .

[@arslansattar351]

3 .

[@AshokKumar-ur2jf]

Very good sir

[@SaudaSalim-r4z]

Well teaching

[@VishnuS-ht5qf]

Thanks sir tor explanation😊😊😊😊😊

[@cubingprince8146]

Can you upload more videos for class 11 and 12? If possible, do it as soon as possible

[@Benjamin-d4q1j]

Sir, you are three much❤❤❤

[@ijeomatony7232]

Frictional force i.e the limiting friction is 8N

[@Learner_Pragya]

Thank you sir🙏❤

[@siddharth......]

I'm first manocha sir 😁

[@ManochaAcademy]

Thanks Siddharth!

[@___________________________u2v]

Thanks ☺️

[@Bint_e_islam-s]

Sir g please basic statistics 😢❤😢❤😢❤

[@Muslim__960]

Yes, please sir 😢😢😢😢😢😢

[@SantoshSharma-zr1kb]

Happy teacher's day

[@AbdulRasheed-jq4jt]

Sir please make videos on ch electricity with experiments

[@manojkhatri1245]

Thaank you ita was gajab explanation 😊😮

[@AshokKumar-ur2jf]

Sir class 9th also exampler book question answer and complite preparation (from bihar)

[@SudarshanamPutta-s5j]

Is it 8N

[@RajyalakshmiGollu]

Gud morning sir

[@ManochaAcademy]

Good morning

[@RajyalakshmiGollu]

How are you sir 😊

[@highvoltexplorer]

Nice friction😊

[@PVamnika]

Sir is it 8N

[@FUSHIDOZI]

5:06 hahah that sound

[@Aarush_789]

Is the answer to the last question 4N

[@sarithaMitta]

Hi sir

[@codewithaditya5857]

Sir question answer be 8 newton.

[@sumitjha-fh7zq]

8N is the answer sir.

[@eminentscholarsacademy0623]

The frictional force is 8.0N

[@ujwal181]

what is your name sir?

[@sriritwikshastry9603]

Amazing Video!
NO more friction to study this topic :)

[@ManochaAcademy]

Thanks

[@muhammedabdulaziz8921]

The answer is 8N

[@cubingprince8146]

Is the abs is 8N?

[@AbdulRasheed-jq4jt]

Sir I know you have made videos on the electricity but they are not enough they not have many things

[@Business_account12391]

Before exam 😅

[@AbelNiguse-j9u]

I am abraham from ethiopia

[@ManochaAcademy]

Hello

[@MBK_9ineT9]

I got 8N
Is it correct