How to multiply matrices of ANY size -- the Kronecker product.

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  • Опубликовано: 16 дек 2022
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Комментарии • 55

  • @lewisbulled6764
    @lewisbulled6764 Год назад +110

    If anyone is interested in some applications of this, it is incredibly important in quantum mechanics, specifically quantum entanglement. For example, if we have a state consisting of two entangled qubits A and B (living in Hilbert spaces H_A and H_B respectively), then we can express the state as a tensor product of A and B. Then we can calculate various objects of interest (e.g. expectation) to find out information about the state.

    • @davidrubel309
      @davidrubel309 Год назад +5

      Doesn't entanglement mean that a composite state of A and B can't be written as a Kronecker product?

    • @jamiewalker329
      @jamiewalker329 Год назад

      I seem to remember outer products and commutation relations of Pauli matrices (when I studied this over a decade ago) - which feels like the same sort of idea...

    • @Nikolas_Davis
      @Nikolas_Davis Год назад +2

      Yep, my first thought when I saw this was "quantum state vectors". It's also very important in quantum field theory.
      It's weird that I'm *both* intimately familiar and completely ignorant of this matrix product; in the sense that I use it all the time in physics, but I never think of it as a matrix product :-)

    • @Nikolas_Davis
      @Nikolas_Davis Год назад +2

      The way I handle tensor products in physics is by the simple rule "each operator 'hits' the vectors in its own space". That, and operator linearity, is sufficient to disambiguate any tangled expression involving tensor products.
      I remember seeing a "proper" vector tensor product as an exercise in a quantum mechanics textbook, and it took me a while to parse it. It was a product from C^2 (2-dimensional complex space) times C^2 -> C^4, and it constructed the C^4 basis vectors in a straightforward way, i.e.:
      (1,0) x (1,0) -> (1,0,0,0)
      (1,0) x (0,1) -> (0,1,0,0)
      (0,1) x (1,0) -> (0,0,1,0)
      (0,1) x (0,1) -> (0,0,0,1)
      Really simple encoding, when you give it a little thought, but to me it was utter overkill; since the bases in different spaces never interact (so I reasoned), why not simply *keep* (1,0) x (1,0), etc., and act with the respective operators in the bra-ket notation? But now I appreciate the mathematician's way.

    • @tordjarv3802
      @tordjarv3802 Год назад +1

      The Kronecker product is also super important for many-body quantum mechanics. For example it pops up when computing total angular momentum of a multi Fermion system (also for bosons), if J=J1+J2 then J² = J1²+J2²+2J1x⊗J2x+2J1y⊗J2y+2J1z⊗J2z.

  • @synaestheziac
    @synaestheziac Год назад +11

    I don’t think it’s possible to have too many videos about tensors, tensor products, etc. - so definitely do more please!

  • @Blackmuhahah
    @Blackmuhahah Год назад +51

    I think the tensor product video would be great! Also I would really enjoy a more abstract extension further down the line (probably in the faaar future^^) to representation theory and irreducible representations of higher dimensionality from the tensor product for goups/algebras

  • @andreben6224
    @andreben6224 Год назад +18

    Tensor products can seem a bit intimidating, so videos going through the tensor algebra and its ramifications sounds AWESOME!

  • @ernestoherreralegorreta137
    @ernestoherreralegorreta137 Год назад +2

    Your channel is way underrated as per the current number of subscribers. There are about a dozen other invaluable math channels out there (that I am aware of), but if I had to pick only one to keep watching, it would undoubtedly be yours. The combination of your wide but wise choice of topics and your consistently fluent delivery without resorting to teatrical gimmicks are unparalled.
    Thank you so very much for your inmense contribution to the spread of highly interesting and beautiful mathematics.

  • @habermasnyc
    @habermasnyc Год назад +7

    I would enjoy seeing the follow-up video (tensor product of linear transformations).

  • @mMaximus56789
    @mMaximus56789 Год назад +6

    More videos about tensors would be amazing! Maybe even getting into tensor calculus

  • @lexinwonderland5741
    @lexinwonderland5741 Год назад +13

    Awesome!! Advanced math day is always my favorite day. Definitely want to see more about tensors, vector spaces, algebras, etc -- I'd defer to whatever you want to make, but I have also been really invested in representation theory (trying to understand the connection between the quantum zoo and representations at different "weights"/eigenvalues) and it would help greatly if you made some content on representation theory of Lie algebras/groups!!

  • @omerhalaby2337
    @omerhalaby2337 Год назад

    4:42 I think that might be fun to…make😂. Michael knows what he’s talking about.

  • @nothayley
    @nothayley Год назад +2

    This is so linked to the tensor product that I honestly didn't know it had a distinct name; in my mind it was just "the tensor product of matrices" which of course isn't really accurate, but was good enough for what I needed (QM, mostly)

  • @Radix.Strategy
    @Radix.Strategy Год назад +1

    You inspire me (nearly) every day! Thank you sir!

  • @zuzaaa1998
    @zuzaaa1998 Год назад +2

    Video about tensor product of linear transformations sounds great, I love your more abstract videos

  • @sinyud
    @sinyud Год назад +1

    Yes! please do more on tensor products

  • @MadocComadrin
    @MadocComadrin 10 месяцев назад

    A few months late, but another application for the Kronecker product is the ability to factorize the Discrete Fourier Transform into factors that correspond to Fast Forier Transforms.

  • @JS-to2ve
    @JS-to2ve Год назад +1

    It also features in my favorite Lemma involving the vec operator: vec(ABC)= (C' kron A) vec(B) which is incredibly useful in matrix diferential calculus.

  • @goodplacetostop2973
    @goodplacetostop2973 Год назад +4

    12:08

  • @jamiewalker329
    @jamiewalker329 Год назад +1

    Feels like some sort of representation of an outer product (which would be 4 dimensional) in 2D. Almost using the array of matrices for the first two indexed dimensions, and then locating within each matrix to pick up the extra two dimensions. Rather like a 3D image may be built up of a 1D (e.g. vertical axis) list of 2D cross sections, we have 2D cross sections which are "layered up" in a 2D manner.

  • @TronSAHeroXYZ
    @TronSAHeroXYZ Год назад

    Good stuff!

  • @ohno8774
    @ohno8774 Год назад

    Tensor products would be fascinating, your videos are brilliant

  • @Mahmood42978
    @Mahmood42978 Год назад

    I would also like to see the Kronecker product as a matrix representation of linear transformations.

  • @Thalesfreitas96
    @Thalesfreitas96 Год назад

    I just used the Kronecker product last week, to produce the matrices for the transverse Ising model

  • @abrahammekonnen
    @abrahammekonnen Год назад

    I'd watch a video on the tensor product. And great video!

  • @coreymonsta7505
    @coreymonsta7505 Год назад

    That was in my linear algebra qualify to show its mixed multiplication property, inverse property follows naturally after, and then show how the eigenvalues and eigenvectors relate to those of A and B

  • @lexinwonderland5741
    @lexinwonderland5741 Год назад +1

    Also, still waiting on the followup from the other tensor video, about relating tensors/notations among disciplines of STEM! (relativity w/ einstein notation, solid mechanics/engineering, pure math, etc). I hope there's enough engagement for it, but regardless that's the kind of content I subscribed for however many years ago and stay excited for!

  • @mrl9418
    @mrl9418 Год назад

    Wow the t-shirt. The lighting turns it Klein blue. But it's also very good on the unlit side.

  • @ekinigdr2030
    @ekinigdr2030 Год назад

    Graph tensor product is also defined in terms of kronecker product of adjacency matrices.
    You can represent any topology on a finite set as a unique reflexive and transitive graph.
    Guess what topological product of n such spaces can be represented as kroenecker product of adjecency matrices of those spaces.
    It also really plays nicely with vec : R^(nxn) -> R^(n*n) function

  • @pavelievlev9730
    @pavelievlev9730 Год назад +1

    Unlike matrix multiplication, Kronecker and Hadamard products preserve positive definiteness, which makes them useful for Gaussian processes.

  • @primosoma
    @primosoma Год назад

    yes, i would like to see a tensor product video. thanks

  • @magnumoppai159
    @magnumoppai159 10 месяцев назад

    I want to see a whole video about the tensor product

  • @riteshbalayan8514
    @riteshbalayan8514 Год назад

    Michal penn thank-you so much, our physics professors uses them but never clarify why they are true. You are blessing for us who what to actuallyunderstand physics and maths. And please video about mathematics in particle physics are always welcome.

  • @BrianCarloRivera
    @BrianCarloRivera Год назад

    Can you discuss the Jordan Canonical Form Michael?

  • @trueriver1950
    @trueriver1950 Год назад

    It's a Matrix of Matrices. That doesn't really look like a product, though it has some conceptual similarity with a cartesian product of sets.
    Having said that, the Kronecker product is important in quantum mechanics, so whatever term we use for it we physicists have borrowed it for our practical uses

  • @cameronspalding9792
    @cameronspalding9792 Год назад

    The determinant is a homomorphism between the set of invertible matrices and the set of non zero real numbers

  • @lorenzosaudito
    @lorenzosaudito Год назад

    Hey Michael, I've got a very nice problem for you :
    Find a closed form of the simple infinite continued fraction with 3 parameters
    u(a,b,c) = a + 1/(b+(1/(b+(1/...+1/(b+1/(2a+1/(b+1/(b+1/...+1/(b+1/(2a...)))))))))) where in every period (between 2a and the next 2a) the number b appears c times. This can be written in compact continued fraction notation as
    ____________
    u(a,b,c)= [a;b,b,b,...,b,2a]
    \ /
    \ /
    "b" appears c times here
    I should point out that here we assume that a, b and c are positives integers, and u(a,b,c) converges.
    Hint: try exploring with some fixed values for the number c, and then build some sort of recursion based on c :)

    • @lorenzosaudito
      @lorenzosaudito Год назад

      I think this is one of my greatest results and I'd be very happy to see you cover this

  • @ealejandrochavez
    @ealejandrochavez Год назад

    What is the tensor product?

  • @gaurangisinghal2074
    @gaurangisinghal2074 Год назад

    Amazing video...

  • @MrRyanroberson1
    @MrRyanroberson1 Год назад

    Already 0:40 this looks like multiplying A by B where B is treated as the scalar field of A

  • @TheBlueboyRuhan
    @TheBlueboyRuhan Год назад +1

    This feels like a cheat code

  • @terryendicott2939
    @terryendicott2939 Год назад

    Tensor products are my Achilles heel. Maybe I am too relaxed? But seriously I would very much like to see you do more on tensor products.

  • @christianimboden1058
    @christianimboden1058 Год назад

    Kronecker products are used in time series econometrics

  • @edwardlulofs444
    @edwardlulofs444 Год назад

    The only part that I am confused about is the difference, if any, between the Kronecker product, tensor product, and the direct product.

  • @noumanegaou3227
    @noumanegaou3227 Год назад

    we can prof d fact by polynominal

  • @frentz7
    @frentz7 Год назад

    better question, *why* to "multiply" (=combine)

  • @tomholroyd7519
    @tomholroyd7519 Год назад

    Too blue

  • @M.athematech
    @M.athematech Год назад +1

    More stuff like this instead of "an interesting problem from the 1969 Outer Mongolian Math Olympiad"

  • @michaelempeigne3519
    @michaelempeigne3519 Год назад

    no more video like above pl.