Heat Transfer (24) - Flat plate convection heat transfer coefficients

[Time stamps will be added in the future]
Note: This Heat Transfer lecture series (recorded in Spring 2020 & Spring 2022) will eventually replace the earlier Heat Transfer series (recorded in Fall 2015). The old lecture series had some errors and was lower quality.
Want to see more mechanical engineering instructional videos? Visit the Cal Poly Pomona Mechanical Engineering Department's video library, ME Online: www.cpp.edu/meo...
This lecture was recorded live at Cal Poly Pomona during Spring 2022. The textbook is "Fundamentals of Heat and Mass Transfer", Bergman et al., 8th Edition.

[@emt4921]

Thanks, CPP. I really hope that Dr Biddle finished this playlist before he retired. I'll be waiting for more videos.

[@CPPMechEngTutorials]

He did. The remaining videos will be released in the next couple weeks.

[@ZalanK77]

One step is very painfully missing from this otherwise excellent presentation. To calculate the turbulent heat transfer over the plate h(x)=k*Nu(x)/x is to be used and that needs to be integrated and divided by the length. So, it becomes the mysterious h_avg=0.037*Pr^(1/3)*k*(rho/mu*v_inf)^4/5*L^(-1/5). In this the Reynolds number was already substituted by Re(x)=v_inf/nu*x=rho*v_inf/mu*x as it is a function of x. nu is the greek letter for kinematic viscosity, rho is the density and mu is the dinamic viscosity. Nu(x) is the Nusselt number at location x, h(x) is the heat transfer coefficient the location x.

[@rzeeonthemic]

What is v infinite?

[@ZalanK77]

@@rzeeonthemic The velocity far away from the plate, so basically the velocity of the undisturbed fluid.

[@chichorro1000]

24/37 let´s go! thank for the content guys!

[@CPPMechEngTutorials]

Keep going!

[@vicentereiman368]

This professor is amazing! Thank you so much sir!!!

[@gajendrasingh_384]

Great lecture watching from India ❤❤

[@CPPMechEngTutorials]

Great comment! ❤

[@cathysunny1804]

Thank you for keep updating this series!

[@CPPMechEngTutorials]

You're welcome. Not even a pandemic could stop us from completing the series.

[@CarlMichaelAAdame]

Thank you very much, cpp

[@mohammadaiman4710]

what is eqn for hx for turbulent?? The lecturer didn't show in this video. Can somebody help me.

[@habibbolgiba8095]

I believe he derived it from the Nusselt number, by making hx the subject, therefore multiplying Nu by K and dividing by x. Not sure thou

[@willcolletti4357]

he kept referring to NU bar as h bar, is there a reason for that

[@vladislavbakovic279]

average over bar means average

[@isk3804]

Dr. Biddle is an excellent instructor, however cameraman ruins it a lot!!! :(

[@CPPMechEngTutorials]

The issue got fixed in future lectures.

[@jeffsmith7247]

@@CPPMechEngTutorials you always say that. lol, Here I am in future lectures..... :/

[@CPPMechEngTutorials]

@@jeffsmith7247 Hang in there... I swear it gets better.

[@jeffsmith7247]

@@CPPMechEngTutorials haha the last video better be a beauty

[@CPPMechEngTutorials]

@@jeffsmith7247 If it's not, you'll get a full refund.

[@Manuel-of7et]

Great lectures professor. However, the camera man needs to be drug tested.