Heat Transfer - Chapter 6 - Introduction to Convection - Boundary Layers

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  • Опубликовано: 4 янв 2025

Комментарии • 10

  • @sujithmswamy2419
    @sujithmswamy2419 7 месяцев назад

    Very grateful for this explanation Mr Powell. Couldn't get any more convincing than this. 🙏🏽🙏🏽

  • @slightlyHy
    @slightlyHy 3 года назад +1

    Seriously appreciate all these!

  • @suprajasathyamurthy1464
    @suprajasathyamurthy1464 3 года назад

    Thank you so much sir for your crystal clear explanation. Saved my day

  • @Muffinaful
    @Muffinaful 4 года назад +2

    Thank you so much for your video! It is very very helpful and the way you explain it makes it easy to understand the topic :) Would you please share if possible the reference of your pictures? It would be helpful for my master thesis. Thanks!

  • @kaursingh637
    @kaursingh637 3 года назад

    my lord - very good -please solve simple problems

  • @CybekCusal
    @CybekCusal Год назад

    it seems as though there is no way to adjust for different types of fluids because the h is based on dT but the dT changes with different fluids that have different viscosities and conductivities and diffusivity. I'm very frustrated trying to figure this out. There doesn't seem to be any literature about it that I can find. every equation i can find, the dT is based on h and visa versa but i can't have two independent variables. Also there are no published convective heat transfer coefficients of (for example) a mixture of 70% water and 30% propylene glycol.

  • @hetalshah5692
    @hetalshah5692 3 года назад

    Great video

  • @nikan4now
    @nikan4now 4 года назад

    Thanks for the introductory lecture. I have a question: I'm wondering about convection within the flow across a surface. Is it mdot x enthalpy integrated over the surface or is it mdot x internal enegy (u) only? In mechanics normally we parse out the mdot x P/rho as part of the mechanical energy but it seems like in heat transfer we include that in the convective heat transfer term (mdot times enthalpy=mdotxu+mdotxP/ro).

  • @TheChim1000
    @TheChim1000 3 года назад

    thank you sir, great job

  • @kursatper
    @kursatper 2 года назад

    Thanks