Thank you mam, I do petroleum engineering and u have helped me so much, I also recommend anyone who needs explanation here in university when they come to me,am frm Uganda
mam one great avantage given by you is there are many (i dont know their efficiency) because they teach in hindi which many of south indians dont know and also your explanation is good thank mam
As if you are good at everything🗿🗿 And also using a calculator doesn't mean that she don't know how to calculate. She's just making sure that you trust her by the calculation.
There is a correction for Ti she considered 3s^2 and 3p^6 as (n-1) but it is (n) so the ans is 1s^2 will be 2×1 2s^2 and 2p^6 will be 8×1 3s^2and 3p^6 will be8×0.35 3d^2 will become 3d^1 and it will give 1×0.35 4s^2 is cancel so will be zero 2×1+8×1+8×0.35+1×0.35+0 Will give 13.15 Zeff= 22-13.15=8.85
Mam but Ti me aap ne Sare ko 18 kyu kr diya 1(0.35) + 8(0.85) + 8 (1) + 2 (1) aata hai na mam because vo (n-1), (n-2) aese aata hai na mam (toh fir ye answer galat hoga na mam)
Maybe bcoz we have to calculate effective Z for one d subshell electron . So that particular electron will have no effect on Z effective. and the other one would have an effect.
Komali M mam I am the aspirant for coming NEET. I have complications in my mind about solving the MCQ's of stereo & optical isomerism please if you have any trick to solve them , please provide such supporting videos soon thanks mam 😃 Thanks Your wishes are like God gift for me ...........🙃😃😇👼
I think it depends on question in lithium we find for 2s1 e- so we take (n-1) and in boron we find for 2p1 so we leave it and take whole 2s1 and put values
Hi mam!!! I'm watching every vedios nd jst ur amazing with ur knowledge.. Thank you so much for ur efforts... 😊..., Mam i have a request, I can't understand this slaters rule tat hw ur neglecting some terms nd there is some confusion. Can u pls clarify with some more info mam?? 🙃
Excuse me mam, I have a question? In the Titanium one, is the 3d orbital together with 3s and 3p because in my book it says they are not together so if it was like that then the electron of 3d that remains is n, then 3s3p is n-1, which is a 0.85 and then the others are 1. I'm not sure, I have seen the correction below but it still confuses me because my book divides d and f orbitals from the p and s orbitals even if they have the same general quantic number (in the Ti case is 3) Could you please help? Thank you!
Mam literally when my sir explained this topic I was thinking where did that value has gone why im getting the different answer im just blank when explained this topic im all clear THANK YOU SO MUCH MA'AM 😊
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came after watching amitabh sir lecture and got confused.. u cleared my confusion.. thanks..
Sameee
Sameee problem
Thank you mam, I do petroleum engineering and u have helped me so much, I also recommend anyone who needs explanation here in university when they come to me,am frm Uganda
Others-studying this in colleauges
Indians- class 11 😅
@@PoojaSharma-rb1ve are u preparing for jee
Insta id?
@@haker57_ I'd:beware of girls
Uganda!!!😳😳
Here we 16 yrs old ppl studying this 💀
Thankyou so much. Mera kl exam hai muje bahut help mili ❤
mam one great avantage given by you is there are many (i dont know their efficiency) because they teach in hindi which many of south indians dont know and also your explanation is good thank mam
it helped me a lot for JEE preparation.Thank you for explaining clearly mam.
Did you clear JEE??
Amazing explanation mam , new buddies do watch the video she really taught very good 👍🙏🙏
👍👍👍👍nice explanation mam
But using calculator for adding 18+.35
😂😂 maths is too much weak 😂
Mam is for chemistry not for maths🎉😅
I was also thinking 😂 weak maths
Madam I had a doubt i.e why you took 1 d electron in Titanium. @ 8:34. please clarify it immediately mam.
I have the same doubt.
chemistry 🤯maths🤡
As if you are good at everything🗿🗿
And also using a calculator doesn't mean that she don't know how to calculate. She's just making sure that you trust her by the calculation.
Mam was using a calculator for taking less time...
There is a correction for Ti she considered
3s^2 and 3p^6 as (n-1) but it is (n) so the ans is
1s^2 will be 2×1
2s^2 and 2p^6 will be 8×1 3s^2and 3p^6 will be8×0.35
3d^2 will become 3d^1 and it will give 1×0.35
4s^2 is cancel so will be zero
2×1+8×1+8×0.35+1×0.35+0
Will give 13.15
Zeff= 22-13.15=8.85
Hello. Her calculations are correct. I recommend you to watch her newer video: ruclips.net/video/CAhhKY9m8tQ/видео.htmlsi=anjs7-GyVh2a6FvH
You are right brother
I dont know how to thank u mam ... love from tamil nadu kanyakumari ❤
Mam but Ti me aap ne Sare ko 18 kyu kr diya 1(0.35) + 8(0.85) + 8 (1) + 2 (1) aata hai na mam because vo (n-1), (n-2) aese aata hai na mam (toh fir ye answer galat hoga na mam)
See the correct ans I have given in comment
And for d and fblock there is no 0.85
n=0.35
n-1=1
n-2=1
Because you are calculating for an electron which is in d orbital
Loved your teaching ! 🤩🤩🤩
🥺 thank youuuu mam finally I learn the correct explanation and it's not that complicated ❤❤
Thank you mam I am.doingmedical doctor your video help me so much I will recommend this to all
When I saw my notes I didn't get anything but this video helps me a lot because I have exam tomorrow ..thank you man 🙏
Harish barman Thank you and if possible share this video with your friends.
Us bhai😭
l 💕 u mam
Bro years gone 😂, how did your exam go? Do you even remember this day now?
God bless you, ma'am for making this so easy for me to understand. The textbook is as well complicated. Stay blessed and God bless you again.
Zion Faye Thanku 😍
My very pleasure! 😄🙏🏿
Thanks mam.
Very helpful for b.tech cse also✌️✌️
Ha
Mam your video is very beneficial..thankyou so much🙏
Ur explanation is so beautiful....Thank u .....komali gaaru
I have no any confusion mam all are clear... Thanks
Mam can u plz explain y 3d2 contributes only 1 electron
same question
We have to reduce 1 from the outermost electron.... e.g- for 4s2 we take 1 electron
For 2p6 we take 6-1=5 i.e 5 electron
@@mohdamir7704 why bro
@@harshitaupadhyay160 that is the part of rule..!!
@@harshitaupadhyay160 If n e are there only last 1 e is screened by remain (n-1)e,1e excluded.
Wow ma'am great explanation 👍
i had a dought at 8:34 i.e why mam took 3d orbital as only 1 electron
Bcoz always we have to take 1 electron less than the electrons present in the orbital....Hope u understood
@@anjanirawat107 BUT MAM took all electrons in previous questions i.e 2*0.85+2*0.35 plz respond...
@@gyana_marg for s or p orbitals, pairing does,so it's impossible to break,that y ,I think
Nice explanation mam my university exam had it for 4 mark and I could write because of you ☺️☺️
Thanks bro
Got it
Thank you so much ma'am, I was struggling in this topic since a very long time. You cleared all my doubts.
Kamali mam Aap bahut Accha study karati hai
Your handwriting and explanation is so good mam
Nice explanation madam... thank you 👍
Your teaching is very nice
I was so nervous but you made it easy.
Thank you 🤗
ur most welcome mam
Wonderfull great explanation mam
Thankyou mam it helps mi a lot💯😊😊😊😊😊😊😊😊🥰😍🤩😊😘😚😙
Thanku mam best explaination simpe h and easy 😊😊
Thanks a lot, mam. This helped me a lot.
Mam for Ti, why one of two d electrons contributes nothing? Plz tell me..at 8:05
Maybe bcoz we have to calculate effective Z for one d subshell electron . So that particular electron will have no effect on Z effective. and the other one would have an effect.
@@luciferx19 tq mam 😊
You are an amazing teacher....
Fabolous explanation thanks for the concept
11 th or 12
Your writing is so beautiful 💫
Nice explanation... I am hardly struggle in this type of questions.. thank you MAM😊😊😊😊😊😊😊🎈
Very short time you teach us very well
Thanks a lot mam for this easy explanation ❤😊
Mam the way you teach is awesome 😊😊
Ma'am really thanks a lot..
Very very bst explanation
amazing explanation mam thank you so much
Thank you mam so nicely explained
Nice teaching
Mam your handwriting is so good even if you write with your left hand
Sooooooooooooooooooo thank you mam .With this trick I got excellent marks
Thnku so much ma'am...it's really helpful 👍
How simply you explained it!!!!! Terrific and very loving voice with respect to students you have mam 😃 Thanks Thank you so much!!!!!😇🤓😻👼
Edu-rich personality ..God bless you..study well..
Komali M mam I am the aspirant for coming NEET. I have complications in my mind about solving the MCQ's of stereo & optical isomerism please if you have any trick to solve them , please provide such supporting videos soon thanks mam 😃 Thanks Your wishes are like God gift for me ...........🙃😃😇👼
I forgot to mention that isomerism in co-ordination compounds , not the instead others.....👼
It's very useful. Thanks Alot Mam 🙏🏼☺️
Tq so much for ur excellent trick mam
Nicely explained ma'am........
i had a dought at 8:34 i.e why mam took 3d orbital as only 1 electron
Same doubt..
@Abcdef Ijkl tq
Loved it mam lots of ❤️ you are great ❤️
Ok...i see , so my teacher taught me this in class😅
Thank you so much mam😊
nice explanation Mam ,Thanks a lot.
best way to teaching ..nice tricks and at last tanku so much mam for this video
Mam. for d orbital we should take electron(n-1) so than 1×0.35 + 18×1=18.45 ....❤
Very nice explanation mam
Thank you❤️
Thank you mam your video is so useful for me
Keep going we will support you
Thank you mam you cleared my doubts every time I watch ur videos if I get doubt
You made my day mam
Thnx for the trick
Komali mam your video is very helpful
Thank you very much mam. Our system confused me but you made it clear for me
What a method of teaching interesting
Very good explanation
Awesome trick mam...
Ur all videos has unique style with awesome trick...
Thankyousomuch...
Alwz Keep us helping from ur fantastic way of teaching
So helpful ...ur voice nd writing both r so clear nd beautiful
Thanku maam for clearing my doubts regarding this rule
Thank you so much mam. It helps a lot. Your video make me understand the EAN. I am so happy.😊
Thanks you mam very much please give like this short video and tips and tricks 😃😄 plzz
THANKS MAM FOR THIS EASY EXPLANATION 😀
The teaching is crystal clear
Even a no brainy guy can understand this in a jiffy
0.30 from the other electron in 1S orbital if the electron for which S is calculated.
Ma'am you forgot this point to include in this video
Mam really awesome 💯 im really confused about it but now im clear. Tysm
Nicely explained.
Mam........ Ur awesome
Thank you so much mam......
...
i had a doubt at 8:34 i.e why mam took 3d orbital as only 1 electron
@@gyana_marg doubt ke spelling toh seekh le
@@amorabvlogs thank you
@@gyana_marg 👍
Madam Slater rule I have doubt about lithium 1s2 you had taken n-1 but boron you had taken n for 1s2 why ? Please clarify
Yes l have also problem that think ........
Yes mujhe bhi ye dought h
@@Anxietyless easy h
@@ankushsinghsaini181😅
I think it depends on question in lithium we find for 2s1 e- so we take (n-1) and in boron we find for 2p1 so we leave it and take whole 2s1 and put values
Hi mam!!! I'm watching every vedios nd jst ur amazing with ur knowledge.. Thank you so much for ur efforts... 😊..., Mam i have a request, I can't understand this slaters rule tat hw ur neglecting some terms nd there is some confusion. Can u pls clarify with some more info mam?? 🙃
You're awesome ma'am and your writing is awesome... But why do you use calculator for such small calculations.. 😅🤔
Maths typing 😂 in chemistry 😂
Maam, y does the last orbital not contribute?I didn't understand can u plz explain
for Ti why you left 3s and 3p they are also in nTH orbital with 3d,,,,please explain
Same doubt...Try this for 3d electron of Zn also
Bro I have same doubt
Excuse me mam, I have a question? In the Titanium one, is the 3d orbital together with 3s and 3p because in my book it says they are not together so if it was like that then the electron of 3d that remains is n, then 3s3p is n-1, which is a 0.85 and then the others are 1. I'm not sure, I have seen the correction below but it still confuses me because my book divides d and f orbitals from the p and s orbitals even if they have the same general quantic number (in the Ti case is 3) Could you please help? Thank you!
Check description
You are correct
d seperate and rest others have 1
Thai video Helps me a lot
This is super trick to understand thank u Mam☺
Mam, thank's it's a very easy one, but I have not understand in class room. But by watching your video I am able to do this type of questions......
mam i am from bihar your explanation is good ,,,,hope it will help in my JEE exam
I have see in 2024😂😂😂
Mai bhai 😂
Thank u mam. Super ga cheptunnaru
Mam your teaching is good ❤but to be honest i didn't understand some concept
Mam literally when my sir explained this topic I was thinking where did that value has gone why im getting the different answer im just blank when explained this topic im all clear
THANK YOU SO MUCH MA'AM 😊
I understood nicely mam thank you for this
you calculate zeff for Ti in d orbital so n th position (9*0.35)+(10*1)=13.15 then zeff =22-13.5=8.85
How 9 in( 9×0.35)???
I am also having the same doubt
@@Sudhaaaaa_09hi!
Thank you Komali Mam
The description is quite contrasting with the table.
For s and p , (n-1) -> 0.85 and (n-2) -> 1.00 but it's written 1.00 for both n-1 and n-2
Look nicely bro
Thankyou mam.......u teach chemistry in the best way .......god bless uhh.....
👌Best video available for SLATER'S RULE..
THANKS to komali ma'am❤️..
outstanding mam..tysm..