Man, I just found your videos and they are really good, you talk very clearly and show every step of the thinking behind the problem. I was searching for videos like that so I could see someone actually working on determining structures from spectra and it helped me a lot. About the UV, it's probably just confirming the existence of conjugation, I think. The more conjugated the molecule, the higher the max wavelength it absorbs in UV-VIS region. The spectra shows an absorption at 260 nm, so it must have some conjugation, but not too much as it falls in the UV region, not in the VIS.
1. I think the very first step should be measuring the degree of unsaturation. 2. For ensuring which one is e/f, you can go for chemical shift calculation.
That was pretty helpful. Though you can note that an odd electron ion or an even mass fragment (here it’s at m/z 122) formed through fragmentation of an even mass molecule would result from a rearrangement. This rearrangement here is McLafferty concerted rearrangement that would happen when a gamma sp3-hybridized carbon has a hydrogen atom that transfers to the heteroatom (here it’s the oxygen) with alpha-beta bond to the double bond being cleaved. Note that for an ester it’s a special case rearrangement considering the oxygen atom of the alcohol chain to be alpha with respect to the double bond. Hope this helps.
After the molecular ion undergoes the McLaferty rearangent, it forms the Cationic Radical fragment you have drawn, where the new OH formed is now bound to an sp3 carbon, whereas the ester oxygen ends up sp2 hybridized after the carbon atom it was originally bount to, breaks off to form a neutral fragment. What I learn here is that through the McLaferty rearrangent of the Molecular Cationic Radical, a smaller Cationic Radical fragment forms containing the rearranged gamma hydrogen. As this species is also a CATION RADICAL, it is detected by the MS detector. Thanks.
Hello sir I'm from Pakistan..I want to ask about the solving all the spectrum with concluding result..I mean I want to use iR,HNMR,CNMR and Mass spectrum to conclude structure
Are you referring to the carbon NMR? Since this is a DEPT experiment, only the carbons that have H's bonded to them are showing up. It is not a normal carbon NMR! Hopefully this answers your question?
![Structure Determination from Spectra (1) (H NMR, C NMR, IR) [Ketone, Ester, Carboxylic Acid]](/img/1.gif)
For a copy of the tables I use click here: drive.google.com/file/d/0BwOceMKQTVFxRTh1Szl4aTh0eE0/view
Thank you, how do I contact you directly
It says I require access to the folder can you please do that
Hello , I just need access to the folder
Man, I just found your videos and they are really good, you talk very clearly and show every step of the thinking behind the problem. I was searching for videos like that so I could see someone actually working on determining structures from spectra and it helped me a lot. About the UV, it's probably just confirming the existence of conjugation, I think. The more conjugated the molecule, the higher the max wavelength it absorbs in UV-VIS region. The spectra shows an absorption at 260 nm, so it must have some conjugation, but not too much as it falls in the UV region, not in the VIS.
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MMA
Aid
It doesn’t matter what it was good 😊 but I love ❤️ so you know me lol 😆 just let us keep
1. I think the very first step should be measuring the degree of unsaturation.
2. For ensuring which one is e/f, you can go for chemical shift calculation.
2:30 that’s something called “overtone” created from the carbonyl
The small peak at 3400 in IR is the overtone from the carbonyl.
This was really helpful thanks, maybe running through how to get the Molecular formula when you don't have it would be a plus
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This video was very helpful! Thank you for sharing your wisdom and time!
It's quite brilliant!!! Thank you for sharing. Regards from China
The peak at 122 on MS is called a McLafferty rearrangement and it includes a loss of a whole molecule ( a neutral molecule fragmented off). 😊
That was pretty helpful.
Though you can note that an odd electron ion or an even mass fragment (here it’s at m/z 122) formed through fragmentation of an even mass molecule would result from a rearrangement. This rearrangement here is McLafferty concerted rearrangement that would happen when a gamma sp3-hybridized carbon has a hydrogen atom that transfers to the heteroatom (here it’s the oxygen) with alpha-beta bond to the double bond being cleaved. Note that for an ester it’s a special case rearrangement considering the oxygen atom of the alcohol chain to be alpha with respect to the double bond. Hope this helps.
After the molecular ion undergoes the McLaferty rearangent, it forms the Cationic Radical fragment you have drawn, where the new OH formed is now bound to an sp3 carbon, whereas the ester oxygen ends up sp2 hybridized after the carbon atom it was originally bount to, breaks off to form a neutral fragment.
What I learn here is that through the McLaferty rearrangent of the Molecular Cationic Radical, a smaller Cationic Radical fragment forms containing the rearranged gamma hydrogen. As this species is also a CATION RADICAL, it is detected by the MS detector.
Thanks.
God bless you....I’m now loving organic chemistry 😊🎉❤
i have confusion about CH splitting ?? ....
My only criticism is that it would be nice to see the NMR data listed out....2H (triplet), etc. along with the actual chemical shift data.
thanks for your useful video. I will have an exam on friday, this video is awesome
Great! Glad to hear it and good luck on Friday!
Very helpful 😊😊😊I'm like Organic is my favorite right now 😊🔥🔥🔥💃💃💃
good young man , wish for you all the good
Matur nuwun nggih pak. Kula dados ngertos amargi panjenengan 😊
Thanks...good structure determination detective work...cheers
Really a great video!
Thanks!
Good explanation, thank you Sir
Sir i have an NMR data of my sample can you interpret it?.
The peak you are wared about around 3350 is the overtone of C=O
That is a very usefull video thanks from Türkiye💌💌💌
Thanks for sharing, it helped me a lot!!! regards from Spain!
This is really helpful thank you so much sir
Hello sir I'm from Pakistan..I want to ask about the solving all the spectrum with concluding result..I mean I want to use iR,HNMR,CNMR and Mass spectrum to conclude structure
You should apply double bond equivalent to proved double bond
It seems you did not assign the carbonyl carbon in C-NMR!
It was very nice lecture.
hi, it would be really useful if you could include pdf of those chart
hello
can I get you chart for IR and H NMR or all what you have ?
Hello! For a copy of the tables I typically use click here: drive.google.com/file/d/0BwOceMKQTVFxRTh1Szl4aTh0eE0/view
Sir also include CNMR spectrum with these two spectrums
I need some help, Is there anyway I could communicate with you Tony?
Hi Amal! You can email me at: Tony.ChemistryExplained@gmail.com
the aromatic region should show 4 lines instead of 3 ?! 1 more for the carbon connected to the ester carbonyl?!!!
Are you referring to the carbon NMR? Since this is a DEPT experiment, only the carbons that have H's bonded to them are showing up. It is not a normal carbon NMR! Hopefully this answers your question?
got it , thanks a lot i find your videos very helpful
This doesn’t explain why you think the ways that you do! During the video you should be explaining why you came to those assumptions
Thanks a lot, Sir
Thank you
Please solve on C14H15N
thanks from india
THANK YOU:D
Hi sir
This is Dipak from india
Please give examples on TOCSY AND COSEY Spectra
Thanks