Hi everyone, I'm excited to announce that I now have posters available for the reaction schemes in this video: Aliphatic reactions: rdbl.co/47y5oAk Benzene reactions: rdbl.co/41W1qQM Phenol reactions: rdbl.co/3NZc8QE Perfect for learning organic chemistry (and supporting the channel at the same time!) 👨🔬
I really wanted to thank you for this clear and concise explanation. I have my O-chem exam in a couple of days and for the life of me i couldn't figure out how to piece together a molecoule from a specter and vice versa. I knew all the teoretical bits about stretching and HOMO and LUMO but this practical part really puzzled me. Thank you for your part in educating the future chemists of the world and keep up the good work!
Thanks a lot for these lessons! Trying to solve the last example instead of -CH2- I've initially assumed a =CH2 group at an end of the molecule and, after trying crazy (C2O2) heterocycle, I came to this: C2H5-C(=O)-C(=CH2)-O-CH3. Of course, I think, this molecule is much harder (if possible) to produce than hexane-2,4-diode and it does not explain abnormally small electron cloud density around the CH2 group.
This is a really good video and I like the explanation as to why TMS is used. Do you have any book recommendations for orgchem or qualitative chemical analysis?
İ solved every part of the structure except the carbonyl one, i was confused how to fit the 2 carbons and at the same time two 2 oxygen, i was pretty close.😅
I'm late to the party, but for the last problem, wouldn't a cyclopropanone with a methyl group and ethyl ether on one carbon also work? 6 carbons, 10 hydrogens, 2 oxygens, and the NMR matches, unless I'm wrong and the first singlet would be more shielded than a regular ketone due to the inductive effect of the ether group?
Great question and you're absolutely right. Well spotted! It's only like that because I was drawing these spectra manually, and they're quite fiddly to draw, but if I had more artistic ability, it would be split into 9 haha
It's quite hard to spot, but the two CH3 groups on the left hand side of the molecule are equivalent to each other. They're both CH3 groups coming from the same carbon atom, making them identical environments. That gives us 6 protons all in the same environment, which is why the peak on the spectrum for that environment has an intensity of 6.
Thank you so much for replying um I was actually asking about the beginning part of proton nmr where you said just like 13c nmr we can identify that there are 4 environments my question is how is it 4 environments? Is the molecule not an ester. I am kind of confused about which part of the molecule is an identical environment @@Chemistorian
The spectrum that shows at 13:02 is for isobutyl acetate. If you keep watching, I explain how to assign all the peaks in that spectrum. You can skip to 19:05 to see the final structure once I've gone through all the peaks, and I highlight the protons which are in identical environments to each other. Hopefully you'll be able to see that there are only 4 proton environments for this molecule.
Hi everyone, I'm excited to announce that I now have posters available for the reaction schemes in this video:
Aliphatic reactions: rdbl.co/47y5oAk
Benzene reactions: rdbl.co/41W1qQM
Phenol reactions: rdbl.co/3NZc8QE
Perfect for learning organic chemistry (and supporting the channel at the same time!) 👨🔬
I get your recommendation from Reddit and absolutely loved your Videos
Excellent video. Thanks to it I finally understand NMR. :)
Great to hear! Once you understand, looking at spectra can be kind of fun (in a very nerdy way). It's like solving a puzzle 🤓
Beautifully explained. I appreciate how you actually go into reasoning on why and how things work rather than just stating definitions. Cheers.
I can confidently say that you’ve saved my grade, thank you!
Incredibly well executed video! Thanks a bunch:)
This is actually sooo good, brother saved my grade for spectroscopy test !!!
Best explanation out there!!! Thank you endlessly
I really wanted to thank you for this clear and concise explanation. I have my O-chem exam in a couple of days and for the life of me i couldn't figure out how to piece together a molecoule from a specter and vice versa. I knew all the teoretical bits about stretching and HOMO and LUMO but this practical part really puzzled me. Thank you for your part in educating the future chemists of the world and keep up the good work!
Great Video! I will sent it to other Students who Need help With NMR. Your explanation is very good and understandable !
I'm soo proud of myself for solving the example correctly before you. Thanks a lot
Great work, glad I could help!
The questions I had on this topic are gone now because of this video. Author, thank you very much!
Amazingly Explained!! This video has helped me a lot!!! Thank You so much Sir!!
Really well explained. Very clear and helpful video. Thank you!
great video it made me understand nmr very easily thanks!
Thank you for this. Really informative!
Thanks a lot for these lessons!
Trying to solve the last example instead of -CH2- I've initially assumed a =CH2 group at an end of the molecule and, after trying crazy (C2O2) heterocycle, I came to this: C2H5-C(=O)-C(=CH2)-O-CH3. Of course, I think, this molecule is much harder (if possible) to produce than hexane-2,4-diode and it does not explain abnormally small electron cloud density around the CH2 group.
Best Explanation ever had
best nmr video out there
Thank you sir...this is really great animation for ur more clearly understanding..❤😊
This is great, subbed. I don't even do chemistry or whatever course this would be in just super interested. Cheers mate
Also want to say that part about heavy water at the end was super interesting. Did not understand it at all. Will have to rewatch the video 😂😂
Wonderful job bro!!!
Thanks for this video its so helpful 🙏
amazing video, thank you so much!
Amazing video
it is 23 minutes long, but I've used 3 hours to watch it. I am able to get the final structure, thanks!
This is a really good video and I like the explanation as to why TMS is used. Do you have any book recommendations for orgchem or qualitative chemical analysis?
its mind blowing
I actually solved it and I don't have it in my course, it took like 10 mins but I did it!
İ solved every part of the structure except the carbonyl one, i was confused how to fit the 2 carbons and at the same time two 2 oxygen, i was pretty close.😅
I'm late to the party, but for the last problem, wouldn't a cyclopropanone with a methyl group and ethyl ether on one carbon also work? 6 carbons, 10 hydrogens, 2 oxygens, and the NMR matches, unless I'm wrong and the first singlet would be more shielded than a regular ketone due to the inductive effect of the ether group?
At 17:36, could you please explain why the multiplet is a septet. Shouldn't it split to 9 peaks?
Great question and you're absolutely right. Well spotted! It's only like that because I was drawing these spectra manually, and they're quite fiddly to draw, but if I had more artistic ability, it would be split into 9 haha
@@Chemistorian don't mind it !! I appreciate your efforts!! Your channel is superb
Thanks for saying that, I'm happy to have helped!
WHERE YOU GOT THE NUMBER FROM WHICH IS ON THE TOP OF THE PEAK. PLEASE
This is computed using a software, that is the area under the curve of the slope of the graph.
hi, I have a question for the proton nmr at 13.02 how is it split into 4 environments when none of them are in identical environments?
It's quite hard to spot, but the two CH3 groups on the left hand side of the molecule are equivalent to each other. They're both CH3 groups coming from the same carbon atom, making them identical environments.
That gives us 6 protons all in the same environment, which is why the peak on the spectrum for that environment has an intensity of 6.
Thank you so much for replying
um I was actually asking about the beginning part of proton nmr where you said just like 13c nmr we can identify that there are 4 environments my question is how is it 4 environments? Is the molecule not an ester. I am kind of confused about which part of the molecule is an identical environment @@Chemistorian
The spectrum that shows at 13:02 is for isobutyl acetate. If you keep watching, I explain how to assign all the peaks in that spectrum. You can skip to 19:05 to see the final structure once I've gone through all the peaks, and I highlight the protons which are in identical environments to each other. Hopefully you'll be able to see that there are only 4 proton environments for this molecule.
thank you so much! i u nderstand now @@Chemistorian
Why nobody can make a simple software to figure it out?
huh??
With your non-rhotic accent, "NMR" sounds like "enema". lol