Leah, I don’t know if you will see this but you are actually the best. I hated organic chemistry I , but I decided to start spending a lot of time reviewing for organic chemistry II. And your videos have helped TREMENDOUSLY. thank you for that. I love you.
Friendly tip for those who are solving with area: The area is a solved integral for under the peak of the graph. In order to find the number of hydrogens corresponding to that peak, just sum up the entire area of the graph, and then multiply by the integer for which you want to find out the number of hydrogens. Took me 6 hours and a lot of nerves of why i can't solve a simple H-NMR...
I took a electrodynamics physics course so this material came fast and easy to me. If you understand resonance and the effect on a magnetic field that a moving charge has in space, then the basic concept around nmr is only a "real world' application to said theory. However, the multiple examples that are present regarding functional groups and those that go against normal intuition are needed to be studied. You managed to put all those in a nice simple package. Thanks!
You're welcome and thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with this topic in the meantime, contact me through my website: leah4sci.com/contact
Thank you so much! I have watched all this playlist and found it extremely clear and helpful 😃 please make a playlist also on UV Vis, IR and other spectroscopic spectra😃
So glad it helped you! Regarding the playlist suggestion, thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with this topic in the meantime, contact me through my website: leah4sci.com/contact
That is information given to us by the instrument itself. The area under any given signal (integration) is proportional to the number of hydrogens which that signal represents.
The 6th carbon that I counted was represented by the signal farthest downfield on the spectrum. (You'll notice I was underlining the C's as I counted from right to left.) It is the CH carbon that ends up being directly bonded both to the oxygen and chlorine atoms in the final structure.
Mitch W is correct on this one. To find the number of hydrogens for each peak, you need to integrate under the curve. The intensity of the signal is directly proportional to the number of hydrogens that create the peak. Usually, this information is provided by your professor and not something you would find or calculate.
sorry i know this might be a dumb question, but its the only part im confused of.......the video at 5:13 says the only option is CH on one side and CH3 on the other because we dont see another CH2, so lets suppose if we dont have the H ratio here, then how are we suppose to know it have to be CH and CH3? thanks
Not a dumb question at all. Some professors will provide ratios, others will teach integration. In the case where you don't have either you have to use the clues within the peaks. For example if you know one carbon has 3 neighbors and the other has 2, if there is nothing else you assume they neighbor each other giving you a CH2 and CH3 (or CH4 and CH6 as a 2x ratio...)
For example if we have carbon 1 and carbon 2 carbon 1 three hydrogens and carbon 2 has three hydrogens so the hydrogen of carbon 1 do not affect the splitting of hydrogen of carbon one which are another???
The splitting of any given peak on an HNMR spectrum is attributed to the number of ‘neighboring’ hydrogen atoms. In your scenario, it would be the three hydrogens on carbon 2 that would affect the splitting of the signal for carbon 1.
Hello Mrs , i just wanted to to tell you that you saved my exam I am certain that I will do really good on it . Actually listening to 16 carriages by beyonce , she so cool i would also like to meet JAY-Z he seems fire. To be totally honest I have no idea to what I would do for the rest of my life , but I am confident in myself . I will become an actor or something like this i know I will make it. But anyway I am actually writing those few lines in pittsburgh. i am just a FOB can I just live lol , life is so out pocket. When life gives you lemon make a Mojito out of it. Sincerely Ismail Safy, Futur Emmy and Oscar winner I will make evryone proud AF. Kisses n Love
The yellow peak is referring to the proton on the carbon that is directly bonded to both the oxygen AND the chlorine. That's why we see its chemical shift a little farther downfield. The purple peak around 3.1 is referring to the proton on the carbon of the isopropyl group that is also directly bonded to oxygen but NOT to chlorine.
Hi can u made a vedio on how we determine steroids biosynthetic pathway in plants it's technique in lab practically.. and how we make sample and check in NmR spectroscopy
Thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with similar topics, contact me through my website: leah4sci.com/contact
I'm sorry, but I don't offer tutoring over social media. My free RUclips videos are shorter and less involved that what you'll find in my Study Hall. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
The number of H's for each signal are given to us by the instrument integrating under each peak and creating ratios between the total area of each signal. Only with integration can we determine the number of H's. It's usually something that will have to be given to you, and not something you're expected to find on your own.
They tell us the number of hydrogens in the molecule that are represented by those respective peaks. Those numbers are found by integration under the peak, and is information usually provided to you by your professor.
Great question! Unless the solvent protons are allowed to interfere, the number of hydrogens in the structure should match the number of hydrogens given by the integration of the peaks.
The integration (area under the curve) is a relative amount of how many H atoms are represented by a single peak. She just decided to give us the exact number in this case. Typically there would be a simpler graph showing the relative amount if the exact amount isnt given
That's given information from the chart. You don't have to figure out that that doublet has 6H. You just need to know where those H's go, and that it has one neighboring H group.
Thanks for your question! The hydrogens in the -CH2- group are depicted by another peak on the spectrum, the blue one right under 2 ppm. Remember, the splitting of the peak helps us identify how many neighboring hydrogens each group of equivalent hydrogens will have. Since the red peak was a triplet, we knew it would have 2 neighboring hydrogens.
I'm sorry, but I don't offer tutoring through RUclips comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Ok this isnt jiving with your previous hnmr videos. You taught in your previous videos a double has 1 neighbor so why does green section have 2 carbons with 3 hydrogens each meaning 6 neighbors
The green peak is representative of the 6 equivalent hydrogens that are also drawn in green. (Yes, those hydrogens are bonded to two separate carbons as CH3 groups. However, they are still equivalent.) Then, those 6 hydrogens in green have only 1 neighboring hydrogen, and you can see that drawn in gray as -CH.
The number of hydrogens written at the top of each peak tells us how many hydrogens are represented by that signal. The green peak represents the six hydrogens at the terminal end of the isopropyl group, and they split into a doublet as a result of having only a single hydrogen neighbor.
I'm sorry, but I don't offer tutoring over social media . For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
I don't offer tutoring over social media. For help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
I'm so sorry! For additional help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
![H-NMR Spectroscopy Basics [Livestream Recording] Organic Chemistry Review & Practice Session](http://i.ytimg.com/vi/zpBsAY8K89s/mqdefault.jpg)
You're the best. I was struggling trying to understand from my professor but you made everything much easier to understand- love the color coding!
So glad to hear that I helped you to understand! And I love the color coding, too! Glad you liked it!
This is the best explanation I have seen thank you!
You're very welcome!
Your videos get me through orgo! When I sent you my syllabus I didn’t know you would respond with a video so fast! Thank you sooooo much! 🙌🏻🙌🏻🙌🏻
You're very welcome! While I can't match everyone's schedule I do try to look for patterns of what students are on when sharing resources
Thank you very much! your short video helped me understand more than I could in my class's 1 hour lecture video.
You're very welcome! So glad to help!
Leah, I don’t know if you will see this but you are actually the best. I hated organic chemistry I , but I decided to start spending a lot of time reviewing for organic chemistry II. And your videos have helped TREMENDOUSLY. thank you for that. I love you.
I am seeing this!! And you're very welcome! I'm always glad to help!
Friendly tip for those who are solving with area: The area is a solved integral for under the peak of the graph. In order to find the number of hydrogens corresponding to that peak, just sum up the entire area of the graph, and then multiply by the integer for which you want to find out the number of hydrogens. Took me 6 hours and a lot of nerves of why i can't solve a simple H-NMR...
Great tip. Thanks for sharing.
can you please elaborate below line either with example
then multiply by the integer for which you want to find out the number of hydrogens
I took a electrodynamics physics course so this material came fast and
easy to me. If you understand resonance and the effect on a magnetic
field that a moving charge has in space, then the basic concept around
nmr is only a "real world' application to said theory. However, the
multiple examples that are present regarding functional groups and those
that go against normal intuition are needed to be studied. You managed
to put all those in a nice simple package. Thanks!
You're so welcome!
You are teaching awesome with very simple method. Anyone can catch it easily. And thanks
Thank you! That is my goal, glad it's helping you learn
so simply explained. Thankyou very much. I got it at once with no need to replay.
mind blown - its all coming together thank you
You're so welcome!
This is a clear explanation, I wish had know about these earlier.
I'm glad it helped you understand now!
Thanku Leah for clearing my doubts you're awesome 👌👌👍
You are very welcome Pranav
Thank you for helping me through ochem this semester!!
You're very welcome!
Make more spectroscopy videos for us professor!! And thanks for this video.
You're welcome and thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with this topic in the meantime, contact me through my website: leah4sci.com/contact
Thank you Leah. You made it very simple and concise
Glad it was helpful and you are so welcome!
1st comment. Leah is the best, your MCAT book is so informative and concise love it♥️
Thanks so much! So glad my online resources (videos + MCAT guide) are helping you on your journey to medical school :)
Spectacular tutorial. Really great!!!!
Glad you liked it! Thank you so much.
Thank you so much! I have watched all this playlist and found it extremely clear and helpful 😃 please make a playlist also on UV Vis, IR and other spectroscopic spectra😃
So glad it helped you! Regarding the playlist suggestion, thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with this topic in the meantime, contact me through my website: leah4sci.com/contact
Thank you your explanations are very clear, you made it easier
You are welcome, glad it helped!
This video helped me so much! Thank you!
You're so welcome! I'm glad it helped you!
Leah, you’re simply the best. Thank you so much !
You're so welcome!
you're such an amazing teacher..thank you
Thanks so much! I'm glad you liked the video. :)
you are literally the best. Thank you SO MUCH
Aww you're so welcome!
Quick and to the point! Thank you!
You're welcome!
This video taught me more than 3, 2 hour lectures.
Always happy to help!! Thanks for watching. :)
SO REAL
Thank you for making the video. A question: how do you know the 1H, 1H, 2H, 6H,3H at the beginning?
I believe that those are given in order to solve.
Yes they are
That is information given to us by the instrument itself. The area under any given signal (integration) is proportional to the number of hydrogens which that signal represents.
This was so helpful!
Glad you like it!
At 6:38 what is the 6th carbon being referenced?
The 6th carbon that I counted was represented by the signal farthest downfield on the spectrum. (You'll notice I was underlining the C's as I counted from right to left.) It is the CH carbon that ends up being directly bonded both to the oxygen and chlorine atoms in the final structure.
Bless up Ms.Leah
Thanks!
So helpful, thank you so much!
You're so welcome!
you are the best teacher
Thank you for the compliment!
May God bless you!
Thank you!
Very useful video, thank you so much!!!
You're very welcome!
Very very thanks for your teaching🙏🙏
It's my pleasure!
this was so helpful, thank you
You're very welcome! Glad it helped
Hey this may seem like a silly question but how can u figure out how many H corresponds to each peak? e.g. 6H, 3H
This is given by the integration value of the peek. Usually in a test or problem this will be given.
Mitch W is correct on this one. To find the number of hydrogens for each peak, you need to integrate under the curve. The intensity of the signal is directly proportional to the number of hydrogens that create the peak. Usually, this information is provided by your professor and not something you would find or calculate.
Thank you very much, you are really doing a lot😘
You're very welcome!
Please do videos on C-NMR as well
I plan to, soon
Fantastic work
Thank you!
LIFE SAVER!!
Thanks, so happy to help!
Hi Leah! Could you also do H-NMR together with IR data when predicting molecular structure? Thank you!
Alas that would take way too long. However I do cover that in the orgo study hall leah4sci.com/join
Thank you so much ma'am. For this video.
You're welcome 😊
sorry i know this might be a dumb question, but its the only part im confused of.......the video at 5:13 says the only option is CH on one side and CH3 on the other because we dont see another CH2, so lets suppose if we dont have the H ratio here, then how are we suppose to know it have to be CH and CH3? thanks
Not a dumb question at all. Some professors will provide ratios, others will teach integration. In the case where you don't have either you have to use the clues within the peaks. For example if you know one carbon has 3 neighbors and the other has 2, if there is nothing else you assume they neighbor each other giving you a CH2 and CH3 (or CH4 and CH6 as a 2x ratio...)
How would you go about interpreting peaks if not given integral spaces or H atoms present and only given the formula of the molecule?
That's a more advanced question in which you first have to figure out the H ratio for each peak. (I don't currently have any videos on this)
By intergal height.
For example if we have carbon 1 and carbon 2 carbon 1 three hydrogens and carbon 2 has three hydrogens so the hydrogen of carbon 1 do not affect the splitting of hydrogen of carbon one which are another???
The splitting of any given peak on an HNMR spectrum is attributed to the number of ‘neighboring’ hydrogen atoms. In your scenario, it would be the three hydrogens on carbon 2 that would affect the splitting of the signal for carbon 1.
I luv this, helped so much
So happy to help!
Thank you for your services🫡 exam is in 1 hour and after watching so many videos, I finally get it!
Awesome! Hope it went well for you!
Hello Mrs , i just wanted to to tell you that you saved my exam I am certain that I will do really good on it . Actually listening to 16 carriages by beyonce , she so cool i would also like to meet JAY-Z he seems fire. To be totally honest I have no idea to what I would do for the rest of my life , but I am confident in myself . I will become an actor or something like this i know I will make it. But anyway I am actually writing those few lines in pittsburgh. i am just a FOB can I just live lol , life is so out pocket. When life gives you lemon make a Mojito out of it.
Sincerely Ismail Safy,
Futur Emmy and Oscar winner
I will make evryone proud AF.
Kisses n Love
So glad to hear that I could help you with your exam and your dreams!
Correct me if i am wrong...but OCH has a peak near 4-6 ...but u mention it to 3.1
The yellow peak is referring to the proton on the carbon that is directly bonded to both the oxygen AND the chlorine. That's why we see its chemical shift a little farther downfield. The purple peak around 3.1 is referring to the proton on the carbon of the isopropyl group that is also directly bonded to oxygen but NOT to chlorine.
Hi can u made a vedio on how we determine steroids biosynthetic pathway in plants it's technique in lab practically.. and how we make sample and check in NmR spectroscopy
Thanks for the recommendation. I post free videos as I have time and am always looking for suggestions. For more help with similar topics, contact me through my website: leah4sci.com/contact
Well...even my professor hasn't explained all of that, so thank you.
You're very welcome!
omg this video is so simple but so helpful I love u lol
You're welcome! Glad you liked it!!
I need IR spectroscopy video lecture!! Mam !!! Is there any video on IR if yes than share kindly
Thanks
It's on my list! Stay tuned
After like 20 problems of nmr I’m finally freaking doing it
YAY!!!
V nice discription... One thing I wanna ask is how to produce this screen... Have you opened it with paint and recorded it?
Glad you liked it!
amazing video. so helpful.. thank u
You're so welcome!
What about the hetereocyclic fused aromatic rings that come with a low resolution nmr graph ? You got to make this closer to what we see in exams
I'm sorry, but I don't offer tutoring over social media. My free RUclips videos are shorter and less involved that what you'll find in my Study Hall. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
Amazing ❤
Thanks 😄
I have one question please , how do you know the number of H's above each peak?
The number of H's for each signal are given to us by the instrument integrating under each peak and creating ratios between the total area of each signal. Only with integration can we determine the number of H's. It's usually something that will have to be given to you, and not something you're expected to find on your own.
Thank you madam from India
You're very welcome!
I really like this one
Glad to hear it!
Im crying, finally understand this part
Aww, so glad I helped clear it up for you!
You said all the carbons are a counted for but where is the 6th you didn’t mark anything at 6:37
There are two equivalent green carbons that are identified by the green peak in the spec. Make sure you count that peak as two carbons!
I luv u Leah~~~ U r truly amazing THX!!!
Awww, you're welcome!
what do the h3, h6 on top of the peaks mean?
They tell us the number of hydrogens in the molecule that are represented by those respective peaks. Those numbers are found by integration under the peak, and is information usually provided to you by your professor.
Thank you.
you're welcome!
Looking at something like 3-methyl-1-butanol, why do the read number of hydrogens not always match what's actually on the compound?
Great question! Unless the solvent protons are allowed to interfere, the number of hydrogens in the structure should match the number of hydrogens given by the integration of the peaks.
How do you know how much H each peak has for example the green pne has 6 H.
The integration (area under the curve) is a relative amount of how many H atoms are represented by a single peak. She just decided to give us the exact number in this case. Typically there would be a simpler graph showing the relative amount if the exact amount isnt given
This is often given at the undergraduate level. The other option is to learn and study integration heights
WOW ! Thanks a lot
You are welcome!
Tomorrow is my exam and this video taught me what my teacher forgot to teach.
So glad to hear I helped fill in the gaps for you!
why is the green peaks 6H? don't even understand this from the start.
That's given information from the chart. You don't have to figure out that that doublet has 6H. You just need to know where those H's go, and that it has one neighboring H group.
Exactly! I have a couple of videos here on this topic that take you back to the beginning
Hello! What happened to the ch2 next to the red ch3
Thanks for your question!
The hydrogens in the -CH2- group are depicted by another peak on the spectrum, the blue one right under 2 ppm. Remember, the splitting of the peak helps us identify how many neighboring hydrogens each group of equivalent hydrogens will have. Since the red peak was a triplet, we knew it would have 2 neighboring hydrogens.
thank you mis
You're so welcome!
took a momment to get it, but I appreciate the ghost carbons shown!
You're welcome!
mam would you help me in solving mcqs related to nmr ?
I'm sorry, but I don't offer tutoring through RUclips comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
What about 13C-NMR?
I haven't done videos on that yet
@@Leah4sci I already passed my MCAT 🥳
Ok this isnt jiving with your previous hnmr videos. You taught in your previous videos a double has 1 neighbor so why does green section have 2 carbons with 3 hydrogens each meaning 6 neighbors
The green peak is representative of the 6 equivalent hydrogens that are also drawn in green. (Yes, those hydrogens are bonded to two separate carbons as CH3 groups. However, they are still equivalent.) Then, those 6 hydrogens in green have only 1 neighboring hydrogen, and you can see that drawn in gray as -CH.
Why does the green one has 6 H???
The number of hydrogens written at the top of each peak tells us how many hydrogens are represented by that signal. The green peak represents the six hydrogens at the terminal end of the isopropyl group, and they split into a doublet as a result of having only a single hydrogen neighbor.
Please explain C-NMR
I'm sorry, but I don't offer tutoring over social media . For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
My prof told us to not watch your video because he said you are wrong in the H NMR spectroscopy topic haha but I am doing it anyways lmao
Oh? What does your professor not like from my videos?
I have a doubt
I have many...
@@Leah4sci nice one
Mam we need questions to solve please add quiz
Check my syllabus guide for more resources: leah4sci.com/syllabus
👍
Mam i need your help... Reply me
I don't offer tutoring over social media. For help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
you're missing the DBE
Thanks for pointing it out. At which part of the video?
🎉🎉🎉
❤❤❤
thank you!
❤️
:)
I’m still confused asl
I'm so sorry! For additional help with topics like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
👍👌💐
:)
Sooo tough explanation
What specific parts of the explanation were tough?