International Space Station (ISS) transits the Full Moon!

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  • Опубликовано: 20 май 2016
  • Last night I was lucky: I captured my first transit of the International Space Station in front of the (almost) full Moon. These events are rare - and I was double lucky since the weather was clear and I only had to go by car about 12 km to observe the event.
    Recorded with an 8 inch newtonian telescope at 2000 mm focal length on May 21st at 1 am in the morning Central European Time.
    Telescope: Skywatcher 1000/200
    Camera: Canon 6D
    Exposure: 1/3200 ISO 1600 25 fps
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Комментарии • 50

  • @decudescartesdeux
    @decudescartesdeux 7 лет назад +5

    Nice job ! Thanks for sharing !

  • @johnnyj540
    @johnnyj540 7 лет назад +7

    Made it look like the Moon has a zipper.

  • @warrenzevonsangryghost6055
    @warrenzevonsangryghost6055 5 лет назад +1

    Great job!!!

  • @willoughbykrenzteinburg
    @willoughbykrenzteinburg 4 месяца назад +1

    Seems it takes it about a second to transit the moon. I counted the ISS in the composite and got 30. Is it safe to assume this was recorded at 30 fps - nevermind, I see in your description its 25 fps.

  • @tony_r_pierce
    @tony_r_pierce 6 лет назад +5

    Could you say what blend technique (mode) you used to create the composite with multiple images of the ISS showing its flight path?

    • @pibyte
      @pibyte  6 лет назад +4

      Hello Tony. Sure, I put each frame on a seperate layer and then made a luminance mask out if it (increasing black and white contrast for a mask) and then use that to mask the station on every layer. On some frames I had to nudge the layer a little bit, because the seeing has moved the image (including the Moon surface in the bg) a little around.

    • @MakeScienceLM
      @MakeScienceLM 4 года назад

      @@pibyte Congratulation!! What software do you use to separate each frame for the final photo? thank you!

  • @99dlavall
    @99dlavall 6 лет назад +3

    @pibyte First of all: nice work! I am planning on something similar in my area of the world tonight, if weather permits. I'l be using a Celectron Neximage 5 on a 10" F5 newtonian (250mm Aperture, 1250mm focal length).
    Question: I thought the Skywatcher 200/1000 was 1000mm focal length; but you said you recorded this at 2000mm focal length. Did you use eyepiece projection for this project?
    Thanks for posting this!

    • @pibyte
      @pibyte  6 лет назад

      Hey David, I used a Barlow 2x lens to "double" the focus length. Good luck tonight ;)

  • @MartotheMartian
    @MartotheMartian 4 года назад

    This is great! I'm trying to figure out the next time this will happen in my area. How did you calculate it?

  • @diji5071
    @diji5071 5 лет назад

    Word

  • @christ4u2now
    @christ4u2now 6 лет назад

    Where was this filmed? Thanks!

    • @pibyte
      @pibyte  5 лет назад +1

      Berndorf, Austria

  • @jogmas12
    @jogmas12 6 лет назад

    I like how it transitions completely across The center of The moon, like by design, which It is!!

    • @Michael-dw9uj
      @Michael-dw9uj 6 лет назад +5

      transit-finder.com/

    • @adrianborinsky2989
      @adrianborinsky2989 6 лет назад +3

      I was about to write, there are sites that calculate everything for you and tell you where and when to go to watch it

  • @malchielrodriguez6718
    @malchielrodriguez6718 4 года назад +1

    I'm not completely sure if this can be possible, because ISS is always bright, I mean ISS reflects sun light, therefore after ISS passing through the moon, the ISS must be illuminated as a star.

    • @pibyte
      @pibyte  4 года назад +2

      "because ISS is always bright"
      No it isn't.

    • @malchielrodriguez6718
      @malchielrodriguez6718 4 года назад

      @@pibyte I mean the visual lapse. (e.g. webpage spot the station information from your location).

    • @pibyte
      @pibyte  4 года назад +7

      ​@@malchielrodriguez6718 It is really hard to tell from the comments if somebody is just pretending to be stupid or actually really does not get anything.
      When the Earth is between the Sun and the station there is no sunlight to reflect. It is black because it is a silhouette against the bright moon. Even my nephew understands this and he is 4.

    • @boptah7489
      @boptah7489 4 года назад

      @@pibyte you are not too smart are you. A full moon is when the Earth is between the Sun and the moon. And the moon is at its brightest. lol.

    • @sailorman8668
      @sailorman8668 3 года назад +2

      @@malchielrodriguez6718 When the station is in the earth's shadow, it's not going to be 'illuminated as a star' is it.
      Why have you not realised that in the footage, the ISS is passing through the earth's shadow?

  • @duolingo4899
    @duolingo4899 5 лет назад

    One time... I saw the moon yellow then an ISS transited and i was mind blown

  • @lombokdrives5721
    @lombokdrives5721 6 лет назад

    Speed of moon is faster than satelite, how come they do that?

    • @99dlavall
      @99dlavall 6 лет назад +15

      Because ISS is MUCH closer, its orbit takes about 90 minutes, whereas the Moon takes almost 28 days to orbit Earth. When we see them together in conjunction, we see the apparent speed relative to each other in arc length (degrees, radians, etc) per unit of time (seconds, minutes, etc).
      The angular speed of both objects from a position on Earth is roughly:
      Moon 360º per 28 days = 0.00893º/minute
      ISS 360º per 90 minutes = 4º/minute

    • @zanick2
      @zanick2 6 лет назад

      is the tesla car video passing the moon fake? its going way slower and should be further out in space too. thanks!

    • @ProcyonX
      @ProcyonX 6 лет назад +3

      Why do you think the moon is faster than the ISS? Orbital speed of the moon is roughly 1 km/s while the ISS is traveling at 8 km/s. Also it is much closer to earth therefore appears even faster as David already showed.

    • @svenzikobombardo
      @svenzikobombardo 5 лет назад

      @@99dlavall
      My calculations are, for an ISS orbit 400 km high:
      Orbital period: 92 minutes = 5500 seconds (roughly)
      Orbital length: (2*pi)*6800 = 43.000 km (roughly)
      ISS speed (declared): 27,600km/h = 7,7km/s (roughly)
      ISS angular speed (as calculated) = 360/5500 = 0,065 degrees/second
      Full Moon's angular dimension = roughly 1/2 degree
      My question is: if my calculations are right (and I'm not even sure, cause I'm not an astronomer, nor a flat-earther, just a simple mind at work), why is the transit happening so fast? It should have been roughly 8 seconds long.
      If anybody with more scientific knowledge could answer me, I'll surely be glad!

    • @99dlavall
      @99dlavall 5 лет назад +4

      @@svenzikobombardo The quick answer, without calculating it, is that the field of view (from the Earth's surface, from which we observe both: ISS and Moon) of the arc length that ISS travels in one second is not 0.065, that would be the field of view if a person could observe it from the center of the earth. Being on the surface of Earth we are 94% closer to ISS then the center of Earth, which is the origin or center of radius for the 0.065 degrees/s.
      Does that answer it for you? If not, I'd be happy to calculate what the FOV is for an observer on the surface of the Earth, of the length of arc that ISS travels in one second. I assure you, it is much greater than 0.065 degrees.
      By the way, you can use transit-finder.com/ to acttually view ISS transits from a location near you.