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Your explanations are way better than @aryanc's. Thank you for making such good explanatory videos. Keep it up!
dp[i][1] = ( 1 + (n - 1) * (n - 1) ) * dp[i - 1] [1]can you explain why you are adding + 1 there. that part is already cover na?
No (n-1)(n-1) is for choosing anything other than the current j, and 1 when getting (j,j)Please like, share and subscribe if it's helpful
@@soumyabhattacharjee1051 subscribed sir
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Your explanations are way better than @aryanc's. Thank you for making such good explanatory videos. Keep it up!
dp[i][1] = ( 1 + (n - 1) * (n - 1) ) * dp[i - 1] [1]
can you explain why you are adding + 1 there. that part is already cover na?
No (n-1)(n-1) is for choosing anything other than the current j, and 1 when getting (j,j)
Please like, share and subscribe if it's helpful
@@soumyabhattacharjee1051 subscribed sir