I just did a chi square test on my data and I'm following it up with a z test. I believe the biggest difference is that the chi square can test many variables at once, whereas the z test only compares two populations. In my case, I used the chi square to see if pollen grain structure was related to the pollination method. That test told me there's a significant relation, but not which structures are related to pollination method. So I looked at which structure types appear correlated with pollination method, and I'm going to do the z test for each of those to see if animal-pollinated species and wind-pollinated species have a difference in the frequency of, say, spiky pollen.
Hi, Thanks for the video. I'm trying to use this test in an academic write up, and have come across two questions. Firstly, does this have a specific name or has it been used by any researchers that you can remember so I can include that in my academic paper? Secondly, do you know how to do this on SPSS? Thanks for your help, Harry
It's called a two proportion Z test. And I was just looking into doing with with SPSS, and apparently it cannot be done without a third-party tool. If you have graduated by now, congratulations.
Thanks a lot lad, I passed cuz of you. So helpful during the final moments. Excellently explained
When you calculated Z you had a Z of 2.869 however I believe you meant to say that you had a Z of -2.869.
clear and straight to the point, thanks!
What happens if there is no common denominator?
What is the difference between z-test for proportions and chi square test?
I just did a chi square test on my data and I'm following it up with a z test. I believe the biggest difference is that the chi square can test many variables at once, whereas the z test only compares two populations. In my case, I used the chi square to see if pollen grain structure was related to the pollination method. That test told me there's a significant relation, but not which structures are related to pollination method. So I looked at which structure types appear correlated with pollination method, and I'm going to do the z test for each of those to see if animal-pollinated species and wind-pollinated species have a difference in the frequency of, say, spiky pollen.
How would you incorporate a finite population correction into this formula?
How did you get 0.9750 as the area in the body? what is the formula?
1-0.025=0.975
Hi,
Thanks for the video. I'm trying to use this test in an academic write up, and have come across two questions.
Firstly, does this have a specific name or has it been used by any researchers that you can remember so I can include that in my academic paper?
Secondly, do you know how to do this on SPSS?
Thanks for your help,
Harry
It's called a two proportion Z test. And I was just looking into doing with with SPSS, and apparently it cannot be done without a third-party tool.
If you have graduated by now, congratulations.
Well explained video. Thumbs up.
Thank you so much!
Nice work :)
Awesome thanks
am I the only one here who is confused with the spelling on alternative hypothesis?