Basics of Modular Arithmetic

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  • Опубликовано: 10 июл 2024
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    #NumberTheoryTopics #ModularArithmetic
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    ADDITIONAL TOPICS:
    Chinese Remainder Theorem
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    RESOURCES:
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Комментарии • 81

  • @pianoforte17xx48
    @pianoforte17xx48 3 года назад +8

    OMG just on time! I have been taking this lesson for a month and I can't wrap my head around it. Can't wait to finally understand it!

  • @aleksszukovskis2074
    @aleksszukovskis2074 3 года назад +4

    Yes! finally! I was searching for these!

  • @mathsandsciencechannel
    @mathsandsciencechannel 3 года назад +12

    I love this guy,always consistent,good explanation and good videos. Almost getting to 10k subscribers and he deserves it. Will get there someday bro.😍

    • @SyberMath
      @SyberMath  3 года назад +2

      I appreciate that! 💖

  • @sergeigrigorev2180
    @sergeigrigorev2180 3 года назад

    Really like this topic! I hope you will continue the Modular Arithmetics series

  • @LOL-gn7kv
    @LOL-gn7kv 3 года назад +13

    Modular makes everything so easy!
    Even if you don't know too much of it , it still useful like a congruent to b modulo n can be written as a = kn + b for some integer k and it just becomes a linear equation thereafter. Also syber make this a series ;)

  • @kubabartmanski7254
    @kubabartmanski7254 Год назад

    Very neat and elegant introduction to the topic!

  • @jakubwieliczko257
    @jakubwieliczko257 3 года назад +5

    Awesome video! I am preparing for the olympiad so it was fun to see another perspective on modular arithmetic. Great explanation. Greetings from Poland! ❤💕💖

    • @SyberMath
      @SyberMath  3 года назад

      Glad it was helpful! 💖

  • @aayushve426
    @aayushve426 3 месяца назад

    great video man ! keep up the work !

  • @242math
    @242math 3 года назад +2

    you are a great teacher bro, thanks for taking us through the basics of a topic that is so confusing to many students, great job, excellent tutorial

    • @SyberMath
      @SyberMath  3 года назад +1

      I appreciate that! 💖

  • @manojsurya1005
    @manojsurya1005 3 года назад +2

    This video reminds me of all the theorems and basics that I learned for modulo like fermat,Euler totient function,Wilson theorem,Chinese remainder theorem(for solving 3 congruent modulo).great video,u can make a video on each theorem briefly if u can

    • @haricharanbalasundaram3124
      @haricharanbalasundaram3124 3 года назад

      I think those would be unlike the videos in this channel, since I think videos are made to help in problem solving, not for teaching itself. There are some MIT OCW lectures on it though, they are great

  • @SimchaWaldman
    @SimchaWaldman 3 года назад

    One of my favorite topics. And its symbols... feast for my eyes!

  • @deratu5517
    @deratu5517 3 года назад

    Wow, I really do like this video! Hopefully there are many more topics that can be explained like this. Have a nice day

  • @coefficient1359
    @coefficient1359 3 года назад +1

    Great, bring more.

  • @diogenissiganos5036
    @diogenissiganos5036 3 года назад +12

    Modular arithmetic; one of the most important aspects of mathematics

    • @aashsyed1277
      @aashsyed1277 3 года назад

      IT COMES IN ABSTRACT ALGEBRA WHICH COMES IN PHYSICS, CHEMISTRY AND SO ON

    • @SyberMath
      @SyberMath  3 года назад +3

      That's right!

    • @aashsyed1277
      @aashsyed1277 3 года назад

      @@SyberMath ARE YOU REPLYING TO ME?

    • @aahaanchawla5393
      @aahaanchawla5393 3 года назад

      @@aashsyed1277 hey watch your caps

    • @leif1075
      @leif1075 3 года назад

      @@SyberMath At 6:39 it doesnt just jave 2 solutions in mod 7 but an infinte mumber because as you said you can add any multiple of 7 so 12 for e.g. is another solution since 12 squared plus 3 equals 147 which is a multiple of 7.

  • @shreyan1362
    @shreyan1362 3 года назад +3

    @Sybermath please continue this series.... this is really helpful 😊🤩

  • @haricharanbalasundaram3124
    @haricharanbalasundaram3124 3 года назад +3

    Modular arithmetic is great for finding the last digits of very large exponents... like 7^55, for example. 49 is congruent to -1 (mod 10), 7^4 is congruent to -1^2 = 1 (mod 10) . 55 is basically 13*4 + 3, so the last digit is the last digit of 7^3, which is 3.

  • @sakkiediereaper2076
    @sakkiediereaper2076 7 месяцев назад +1

    😂 the title should be, Modular Arithmetic: The cheat code to Mathematics!

  • @repsarklar9420
    @repsarklar9420 3 года назад +9

    *SYBERMATH LOVERS ...*
    👇

    • @SyberMath
      @SyberMath  3 года назад +3

      Thank you! 💖

    • @shreyan1362
      @shreyan1362 3 года назад +1

      @@SyberMath i thought you were bringing quadratic congruence as well :|

    • @aashsyed1277
      @aashsyed1277 3 года назад +1

      @@SyberMath yes!

    • @aashsyed1277
      @aashsyed1277 3 года назад +1

      @@SyberMath i love you!

    • @akolangto8225
      @akolangto8225 3 года назад

      Syber Math fan here from the Philippines

  • @rafiihsanalfathin9479
    @rafiihsanalfathin9479 3 года назад

    Can you do video like this a basic olympiad theorem and how to use it, but also longer and deep?, it would help me a lot!

    • @SyberMath
      @SyberMath  3 года назад

      Will try in the future

  • @sekarganesan902
    @sekarganesan902 3 года назад +1

    Good introduction to modulo.

  • @manavaggarwal2714
    @manavaggarwal2714 3 года назад

    Are you coming up with a course on number theory or is it just a randomly posted topic🤔.

    • @SyberMath
      @SyberMath  3 года назад

      After the mod equation video, there's been some requests. No plan on making a course

  • @mainaccount0411
    @mainaccount0411 6 месяцев назад

    Sir, how do you make your videos, what software do you use to write on?

    • @SyberMath
      @SyberMath  6 месяцев назад

      Microphone: Blue Yeti USB Microphone
      Device: iPad and apple pencil
      Apps and Web Tools: Notability, Google Docs, Canva, Desmos

  • @aashsyed1277
    @aashsyed1277 3 года назад +1

    DAMN YOU ARE SO AWESOME....

  • @adityadarade4533
    @adityadarade4533 Год назад

    Love you bro thanks

  • @clovissimard3099
    @clovissimard3099 28 дней назад

    TEMPS-HASARD MODULO 3
    Pour en revenir au sujet qui nous occupe, dans le monde subatomique, il se pourrait que les phénomènes ne suivent pas une ligne de temps unique, ce qui est conforme à la théorie de la gravité quantique et de la « non-existence » temporelle.

  • @tonyhaddad1394
    @tonyhaddad1394 3 года назад +1

    Broo i like modular so much beacaus we can tested in real life and make life easier !!! ofcorse now we computers but it so intersting when we challenge our brain 😍😍

  • @Qermaq
    @Qermaq 3 года назад

    2:42 would 2 and 3 be valid answers? I agree that 11 is congruent to 5 mod 6, but mod 2 would be 1, and mod 3 would be 2, properly. I suppose one can say that 11 is congruent to 5 mod 3 in the same way you can say it's -1 mod 3, as basically in mod n we can add or subtract kn where k is an integer. Is that the right direction?

    • @SyberMath
      @SyberMath  3 года назад +1

      Yes. 11≡1 (mod 2) and 5≡1 (mod 2) so they are congruent
      Similarly, 11≡2 (mod 3) and 5≡2 (mod 3) so they are congruent

  • @Neemakukreti5421
    @Neemakukreti5421 Год назад +1

    couldnt understand the first example (x^2 +3_=0(mod7)after the whole adding 7 to both sides thing. To be specific, you equaled 7 to 0,which has been defined as 7's remainder and which is not the number itself... So how can one just add ita remainder to one side, and the dividend to the other..? A reply would be much appreciated

    • @SyberMath
      @SyberMath  Год назад

      Adding 7 and 0 are equivalent because 7 is congruent to 0 mod 7. You can also think of it this way: all numbers in the form 7k where k is an integer are congruent mod 7. 7 and 0 are in the same group in that sense. All integers can be grouped into 7 groups mod 7 like 7k 7k+1 7k+2 7k+3 7k+4 7k+5 and 7k+6. Any integer can be represented in one of these forms. I hope this helps.

    • @SyberMath
      @SyberMath  Год назад

      -3 and 4 are congruent mod 7 because they can both be written as 7k+4. Basically they are in the same group (referring to groups I mentioned in my previous reply)

    • @srividhyamoorthy761
      @srividhyamoorthy761 Год назад

      @SyberMath can k be 0

    • @srividhyamoorthy761
      @srividhyamoorthy761 Год назад

      ​@@SyberMathcan k be 0

    • @srividhyamoorthy761
      @srividhyamoorthy761 Год назад

      After repeatedly watching this i am able to understand so basically if u see for eg 28 is a multiple of 7 so remainder is 0 it can be written as 28 congruent to 0 (mod7 )now if you're to add 7 to 28 it becomes 35 since we're not even into the quotient when we write in modular form 35 also is congruent to mod7 you see so the remainder is 0 so if you are to add add 7 to rhs it still should give the same remainder of -3 that's it .

  • @MathElite
    @MathElite 3 года назад +1

    First, sooo close to 10k subscribers!
    Great video

  • @aashsyed1277
    @aashsyed1277 3 года назад

    9.8 K SUBS LIKE REALLY!

  • @MangoLassiYT
    @MangoLassiYT 6 месяцев назад

    at 8:38 why are we squaring residues of 4 to check if sol exists or not. I did it using even no as : 2k and Odd no as :2k+1 taking modulo of these two I concluded solution doesn't exists but i don't understand how did you do it usig residues of 4

    • @SyberMath
      @SyberMath  6 месяцев назад

      To find out which number squared leaves a remainder of 2 upon division by 4, we need to check the remainders for all possible numbers which are represented by 4 numbers: 0,1,2,3. Any number greater than these fall into one of these categories by the remainder they leave upon division by 4.

    • @MangoLassiYT
      @MangoLassiYT 6 месяцев назад

      oh so we are taking mod first of num and then squaring the remainder and again taking mod ? @@SyberMath

  • @zainlam9965
    @zainlam9965 Год назад

    another small thing is wilson's theorem

  • @srijanbhowmick9570
    @srijanbhowmick9570 3 года назад

    Hey SyberMath , how you doing ?

    • @SyberMath
      @SyberMath  3 года назад

      Pretty good! How are you? Long time no see! 😁

    • @srijanbhowmick9570
      @srijanbhowmick9570 3 года назад

      @@SyberMath Yeah exams and all that stuff
      Finally I am free and can comment as much as I want
      Thank you once again for keeping me entertained with your math problems during these tough times

  • @tushargupta986
    @tushargupta986 Год назад +1

    from India

  • @tonyhaddad1394
    @tonyhaddad1394 3 года назад

    We have *

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    @zstar8397 9 месяцев назад

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  • @aashsyed1277
    @aashsyed1277 3 года назад +2

    DAMN YOU ARE SO AWESOME......