I solved it by looking at the last digit in the number. In the sequence, I kept seeing 56, 114, 232, ....., 948, 1906. Here, the last digit was decrementing each time by 2. So from 6, to 4, to 2 to 0. Since we can't have negative numbers, we start from 10 and decrement again, which gives you the 8 in 948 and the 6 in the 1906. From this I got B. 3824. Idk if my method is very weird but that's a pattern that I noticed
For the question saying, "how many rectangles?" The one you counted as 9th looks to be more of square than rectangle. And, the fact that the question is to test our analytical skill makes it look like - ignoring the last square is as if passing the second layer to the solution.
I solved that totally different and came to the same conclusion, wow. doubled the number in each circle and added increasing multiples of two to get the next number. 56 x 2 + 2 = 114 x 2 + 4 = 232 x 2 + 6….
I solved it by looking at the last digit in the number. In the sequence, I kept seeing 56, 114, 232, ....., 948, 1906. Here, the last digit was decrementing each time by 2. So from 6, to 4, to 2 to 0. Since we can't have negative numbers, we start from 10 and decrement again, which gives you the 8 in 948 and the 6 in the 1906. From this I got B. 3824. Idk if my method is very weird but that's a pattern that I noticed
For question 1, the no. Of triangle in the last box should be 10 as same in the second box, because there is no more extra space in height of box to fit more than 10 triangle.
Your answer for the the question around the 12m mark is not necessarily true. We have one instance of the unfilled square appearing in the third image, but it does not follow that it must appear because it is in the third position in the sequence. You could equally reason that the unfilled square arises due to the filled square reaching the bottom right corner, or when both the bottom right square and the triangle are present. There is not enough information to conclude that either of those options are not true and thus it would be a hasty generalization to conclude that the unfilled square simply arises every third step in a sequence when there is only one instance of it happening, B is the only pattern that we can logically conclude by necessity of the continuous patterns.
Yes, I also got B, I would expect to see the larger unfilled square in the next box in sequence after B, following the pattern in the center, which looked to me like: no square, small square, big square, small square, no square, small square, big square, small square etc...
Mine goes like this: 56 x 2 = 112 + 2 = 114 (I increase 2 numbers in every sequence so from 2 to 4 until in 1906 it becomes 1906 x 2 = 3812 + 12 = 3824 :)
I think traingle sum gets answer as 0 becoz we are calculating edges we got 10 for 3 edges right and the midsing value is ? Write so whats the crt answer can anyone say
Practice Analytical Reasoning Test: www.howtoanalyzedata.net/analytical-reasoning-pre-employment-test-explained/
I solved it by looking at the last digit in the number. In the sequence, I kept seeing 56, 114, 232, ....., 948, 1906. Here, the last digit was decrementing each time by 2. So from 6, to 4, to 2 to 0. Since we can't have negative numbers, we start from 10 and decrement again, which gives you the 8 in 948 and the 6 in the 1906. From this I got B. 3824. Idk if my method is very weird but that's a pattern that I noticed
For the question saying, "how many rectangles?"
The one you counted as 9th looks to be more of square than rectangle. And, the fact that the question is to test our analytical skill makes it look like - ignoring the last square is as if passing the second layer to the solution.
I solved that totally different and came to the same conclusion, wow.
doubled the number in each circle and added increasing multiples of two to get the next number.
56 x 2 + 2 =
114 x 2 + 4 =
232 x 2 + 6….
Please delete this if it spoils anyone
Awesome job! Thanks for sharing your solution! All the best on your job interview and assessment test!
I solved it by looking at the last digit in the number. In the sequence, I kept seeing 56, 114, 232, ....., 948, 1906. Here, the last digit was decrementing each time by 2. So from 6, to 4, to 2 to 0. Since we can't have negative numbers, we start from 10 and decrement again, which gives you the 8 in 948 and the 6 in the 1906. From this I got B. 3824. Idk if my method is very weird but that's a pattern that I noticed
For question 1, the no. Of triangle in the last box should be 10 as same in the second box, because there is no more extra space in height of box to fit more than 10 triangle.
Your answer for the the question around the 12m mark is not necessarily true. We have one instance of the unfilled square appearing in the third image, but it does not follow that it must appear because it is in the third position in the sequence. You could equally reason that the unfilled square arises due to the filled square reaching the bottom right corner, or when both the bottom right square and the triangle are present. There is not enough information to conclude that either of those options are not true and thus it would be a hasty generalization to conclude that the unfilled square simply arises every third step in a sequence when there is only one instance of it happening, B is the only pattern that we can logically conclude by necessity of the continuous patterns.
Yes, I also got B, I would expect to see the larger unfilled square in the next box in sequence after B, following the pattern in the center, which looked to me like: no square, small square, big square, small square, no square, small square, big square, small square etc...
Mine goes like this: 56 x 2 = 112 + 2 = 114 (I increase 2 numbers in every sequence so from 2 to 4 until in 1906 it becomes 1906 x 2 = 3812 + 12 = 3824 :)
Same bro/sis
I have identified the circle questions as last as even number .so easily identified 2.answer is 3824
Great tq so much sir❤❤❤
thank you!🙌🏼
The pattern was I didn't agree it should be the square at the bottom right corner?
I think traingle sum gets answer as 0 becoz we are calculating edges we got 10 for 3 edges right and the midsing value is ? Write so whats the crt answer can anyone say
Amazing
isnt it supposed to be 16 O.o u didnt count the smallest middle square like you did from the start the most outer square?
Done sir
Please upload eagle view iq questions
16
12
It’s -1
0-1=-1
Thank you sir❤️
🎉
I found it boring😪....sooo easy
i have a different solution for question #2 lmao
😂😂😂🎉🎉🎉🎉🎉😢😢😮😮