The only one that worked met 2 conditions: a>b and both factors were even. By the way, in watching many of these kinds of videos where the most important understanding is of identities of difference of squares, difference of cubes and sum of cubes, anyone who watches enough of these videos should get an “aha” moment 😆 (an epiphany). They are good exercises also, in grasping the idea of systems of linear equations and the “brute force” method of checking factors.
@@cesarelainegative numbers are natural,fractions are not natural. Let's test & verify (-4)^2 - (-2)^2 = 12. So it's confirmed that -4 & -2 also possible.
bravo and thank you for sharing
The only one that worked met 2 conditions: a>b and both factors were even. By the way, in watching many of these kinds of videos where the most important understanding is of identities of difference of squares, difference of cubes and sum of cubes, anyone who watches enough of these videos should get an “aha” moment 😆 (an epiphany). They are good exercises also, in grasping the idea of systems of linear equations and the “brute force” method of checking factors.
The solutions x=4,y=2 or x=-4, y= -2 are very easy to see without calcutation.
Х=5, у=stem13
Ans x=4. &. y=2. (16--4)=12
(x,y) =( -4 ,-2) also possible
x=4and y=2.
4 and 2 or - 4 and - 2 😊
Negative numbers are not natural as required
@@cesarelainegative numbers are natural,fractions are not natural.
Let's test & verify (-4)^2 - (-2)^2 = 12.
So it's confirmed that -4 & -2 also possible.
It can be also (x,y) =(4,-2) or (-4,2)
So the exact answer is (x,y) = (+/-4 ,+/-2)
@@georgesunaryo5080No. Negative numbers are not natural numbers. So say Peano's assiomi: 0 Is not successor of any natural number.
XX - YY = 12, X,Y ?
*. 12 = 16 - 4
= (4x4) - (2x2)
= XX - YY
**. X = 4 , Y = 2 ./.
Actually (x,y) = (-4,-2) also possible
No need to calculation x=4 & y=2
x=-4,y=-2 also possible
Not intelligent . Give any value to x and you get 2 values for y that fit the relation in any case