Lithium Aluminum Hydride LiAlH4 Reduction Reaction + Mechanism
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- Опубликовано: 25 фев 2016
- Leah4sci.com/redox presents: Carbonyl Reduction using LiAlH4 - Lithium Aluminum Hydride. Reaction, Mechanism and examples.
Need help with orgo? Download my free guide '10 Secrets to Acing Organic Chemistry' HERE: leah4sci.com/orgo-ebook/
This video breaks down the reducing agent LiAlH4 to help you understand its reactivity with carbonyl compounds including aldehydes, ketones, carboxylic acids, esters, and amides.
This is video 7 in the Organic Chemistry Oxidation/Reduction video series. Catch the entire series along with my redox practice quiz and cheat sheet on my website: leah4sci.com/redox
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I genuinely have no idea how your videos aren't more popular. SUPER HELPFUL! I love that I found someone who can explain orgo II topics well! Great job :)
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She's pretty popular now in 09/2020 with 162k subs. And it seems like she genuinely got all of hers subs with her well presented content and soothing voice that delivers the knowledge in a very understanding and well explained way. She's definitely helped me to understand it all better. 😃
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Excellent explanation.kindly upload more lecture.
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Super helpful! Thank you :)
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That is very important to my exam. thank you so much.
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@@Leah4sci can upload a video about oxidation toluene with cro3 in acetic anhydride to benzaldehyde
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Well explained and super clear thanks for your videos ! Huge thanks from 3rd year student in chemistry, your videos reasure me in my knowledge and help me in my exercices !
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4:32 Can we say that the mechanism is SNA/E?
Hey i have a question! Hiw does Alh2 combined with O makes it a good leaving group rather then simple O?
If you're referring to the negatively charged oxygen leaving the structure at 7:40 in the video, having that oxygen leave would make the central carbon unstable as it would become a carbocation with less than an octet of electrons.
The AlH2-O is a good leaving group because the oxygen is highly electronegative and is capable of holding that negative charge when apart in solution. Aluminum alone would not be happy leaving as a hydride either, as I explained in the video around this time.
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what if at the end we washup using a Base instead of an acid. My textbook uses a base but doesn't show the actual mechanism. just the final product which is the same as a washup with an acid.
I'm sorry, but I don't offer tutoring over social media. For help with questions like this and more, I recommend joining the organic chemistry study hall. Details: leah4sci.com/join or contact me through my website leah4sci.com/contact/
A video from Khan academy says that the reduction of carboxylic acids and esters follow the same mechanism unlike what you said ...Also the balanced equation in our textbook has no mention of hydrogen as a by product . There is only a water molecule.
Can anyone help with it ?
The goal of this video is to teach you the concept. If your resources don't match up focus on understanding why each step is as it is. This way you'll know which is correct regardless of what the resources tell you. Especially with biproducts not mentioned
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Perfect explanation . Can help me to make videos on Coordination Compound. And. Salt analysis. I fill difficulty in this chapters .Please help me . You are my path to achieve my goal.
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
Wish i could help you in promoting your videos.They are really helpful.God bless you
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jeez u have a video for everything
I do try :)
Hii..im basically a biochemist..your video looks interesting but my concern is once the reaction is over how to remove those reducing agents from the reaction mixture
krishnaswamy. V.K.D. Well we use anhydrous diethyl ether to remove lialh4 because it is very reactive in water
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
Thanks a lot for your videos. I think they are better than Khan's.
Thanks for the feedback and you're welcome! :)
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I'm sorry, but I don't offer tutoring through RUclips comments. For help with questions like this and more, I recommend you join the organic chemistry study hall. Details: leah4sci.com/join
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At 7:06 why there is no positive charge on Alh3
The formal charge on aluminum in AlH3 is zero. Notice that AlH4 carried a negative charge. When its hydride left and attacked the acidic hydrogen, it then lost that negative charge and became neutral.
@@Leah4sci thanks....
@@Leah4sci is it true that you can't predict what will be the product of chemical reaction in chemistry....is it that you do experiment with the reactants , then comes data ..and then based on that data we write a story that satisfy that resultant...
@7:30 what's the fate of O-AlH2
Agreed
Once kicked off it's left to wander in solution as a spectator ion
My professor showed us this rxn but didn't explain the mechanism which is kind of dumb
I hope the videos helped fill in the gaps
Yup. I finished Orgo 1 with an A in part thanks to your videos. Also I studied my ass off.
what is the fate of AlH2O
At which point in the video?
Leah4sci
in mechanism of reduction of carboxylic acids to esters, OAlH2 is kicked out as a good leaving group in the second step. then what about the fate of OAlH2
Nabh4 is not used for reduction of carboxylic acid
I agree. NaBH4 is a weak reducing agent and will only reduce ketones and aldehydes. Is there a point in the video where I say otherwise?
I. L .U
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