How to Create a Histogram (Decimals) with Class Boundaries Example #2
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- Опубликовано: 21 авг 2024
- Class: 4.225 - 4.705 : Frequency = 8
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This is by far the most useful video on Histograms! Thank you
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There might be an error in the last class frequency: the correct frequency is: Class: 4.225 - 4.705 : Frequency = 8
thanks i thought i was the only one who saw it wrong
@@wallz7216 I saw that to need to check work so we are learning properly
Finally I understood that how to find class boundary of decimals 😍...
Thank u sir🙂
i think histogram need to have space at the early of the graph right?
I was looking for exactly same video, thank you
Glad I could help
If you where given a table with class boundaries and frequency in decimal , how could you find class interval? Thanks
this is also my problem in year 2023 pls
Thank you so much sir. This is very helpful.
You are very welcome!
Thank you
I finally understand it.
You are very welcome!
sir, if the class width is 2.0 and the data is continuous data (e.g. 5.45 3.45 9.58 3.22 6.77 ) , which number should I take after round up 2.1 or 2.01 ? thanks
How do you think? We need two decimal places.
@@helpyourmathstat i choose 2.01 first but I get something wrong in next step (chebyshev's) haha
Professor Luis there was an error in the frequency when you count the last one: 4.225-4.705 it is not 7, it is 8. otherwise the total doesn't match the amount of the data = 20
Thank you! It's a typo! :)
Thank you sir l now know how to draw a histogram
Thank you so much sir. found this great video and understood this topic clearly.
You are very welcome!
Thank you for this, Sir!
You are very welcome!
Thank you so much!!
How to find what value can we subtract
Great video. However, I don't get how u rounded up to 5 thousandth. Can you explain.
when we have a full integer (6) in the lower class limit then we do substract 0.5 to find the class boundary likewise if we have one decimal value in the lower class limit (6.1)then we will substract 0.05.The thumb rule is we will go one decimal point ahead always then the value of class limit.
@Mehrose Nasir, that's a very nice explanation of it!👍
@@mehrosenasir3966 Thanks. Ure a great teacher.
the value of the smallest place value of the data is hundredths ... so 0.01 divided by 2 is = 0.005; when the smallest place value of your data is a unit aka 1, as in 47, 5, 8, 10 ... you go 1 divided by 2 = 1/2 or 0.5 so that's how you arrive at the amount to use to construct class boundaries from class limits
Will the same methodology apply if the raw data were in %s? Thanks!
Do you have Continuse Data?
where he get the 2.30?
1.83 + class width (0.48) = 2.31, thanks.
Where can you get the value you add and subtract when you do boundaries?
Love form Pakistan
Thanks!
Sir , I think there’s a mistake in that
Please let us know where the mistake is. Thanks!
Hi brother I have question it's not solving
Can you solve my problem
@@dk-cz8gu Let me know the problem?