Lesson 2.1 Frequency Table, Tally, Midpoint, Relative Frequency and Cumulative Frequency
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- Опубликовано: 8 сен 2019
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Dr. Jae Ki Lee
![Understand Frequency Tables, Cumulative & Relative Frequency in Statistics - [7-7-3]](http://i.ytimg.com/vi/Md2_E_hTvdQ/mqdefault.jpg)
its crazy how you managed to save our asses from failing in 10 minutes im gonna cry thank youuuuuuuuuuu
I am glad to see it helped you!! ^_^
Thank you so much, I’ve been searching for the right video and yours is perfect 👍
Thank you so much! I was struggling trying to comprehend until I came across your video. You explained this so well.
Thank you! I am glad it helped!
Thanks man this was a big help
you have to use this formula in order to get number of classes, Number of class / k / = 1+3.332log of n, n means number of observation Then k = 1+3.332 log 50 , log50= 1.698 .Therefore, k= 1+3.332 x 1.698= 1+5.65 = 6.65. Finally, round this decimal number which gives us 7. So, number of class is 7
Thanks it saved me
This formula is failed in some places
Thank you! I perfected my quiz because of your lecture!
You are very welcome!
btw, kumain naba sila?
Your video made my life easier, thanks!
You are welcome, please check our free website too, helpyourmath.com/150.5/mat150
Thank you man , you’re a life saver .
Happy to help
I love you sir...
Very helpful! Thank you so much!
Glad it was helpful!
Well done it's very informative video ap ne jo sikhaya us se bhot help mili, me b statistics ki classes Leta ho online
Thanks so much! This helped alot
Glad it helped!
great . I also appreciate you
You are welcome!
Perfect way of explaining
Glad you liked it
Thanks you so much sir!
You are welcome! Please visit our Free Statistics Class Website, helpyourmath.com/150.5/mat150
Thank you Man!
You are welcome!
Thank You So Much
You are welcome! Please check our free statistics course, helpyourmath.com/150.5/mat150
Thank you this video helps
You are welcome! :)
Thank you so much!!!
You are welcome!
Vry helpful👏👏
very good! thank you
You are welcome!
Thank you
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Omooo!!💜thank you so much😇
Wait am I the one here feel confused about the man speaking having a Korean accent of English??😁anyways good job really a life saver😇
Yes 😁
very helpful thank you sir
Happy to help
Yessss thankyou so simple quick and easy keep teaching ⭐️🫶
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Thank you it's very helpful
Glad it was helpful!
Thanks
You are welcome! Please check our free website, helpyourmath.com/150.5/mat150
Thank u its a big help 😍😍
You are very welcome!
What a explain and magic😍❤
Thank you! Please visit our free website, helpyourmath.com/150.5/mat150
Thanks very much🙏
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Thanks alot😊
Most welcome 😊
Thank you!!
You are welcome. Please check our new website: www.helpyourmath.com/freecourses/
Thank you Sir,
You are very welcome!
Thanks teacher, you really helped Thank you so much I am from Somalia🇸🇴 and I greet you with the most honor
You are welcome!
tnx a lot!
You are welcome!
THANK YOU SO MUCH!!! I'm just a little curious I'm not trying or intending on making fun but how many of you think his voice sounds like Kim Taehyung from BTS? (again I'm not trying to sound rude, I'm just curious)
It really sounds like taehyung! his voice is amazing!
I noticed it too😇😁😁
Omg thank you so much
You're welcome!
I want to know how did you got the number of classes (7) please 🙏
Thanks bro 👏
Welcome 👍
I had another question for the classes on the last part how did you find the high number. I did not understand that part.
I will help u the last part frequency 4+ 8 =12 in cumulative frequency 4+8+14=26 4+8+14+8=34
thankyou your teaching made me pass my exam lol
WoW, You are very welcome! Please check our free website, helpyourmath.com/150.5/mat150 We hope you get an A for your class!
thank you soo much sir👍👍👍
You are very welcome! 😃
thanks man
You are welcome, please check our new free course, www.helpyourmath.com/freecourses/
hi what if your numbers at the classes part are single values, how do you find the midpoint please
Then you can use a weight mean distribution. It means you organize each value with its frequency. In this case, you do not need to find a midpoint.
Thank you very muchhhhh
You are welcome! Please check our Free Website: helpyourmath.com/150.5/mat150
thanks for your help
You are welcome!
one question, when your figuring out the last class do you add 12 or 11 to 76? You said add 12 to 76 but instead you added 11. Please explain.
@@footz975 Let's count our fingers from 1 to 10. There are TEN fingers, but 1 + 10 = 11. We need to count the number 76, therefore, we add 11 to count 11 more numbers. There are a total of 12 numbers. Enjoy the holidays! - Prof. Xin
@@helpyourmathstat thank you so much, you too.
where does the 50 under the frequency column comefrom?
loved the video :)
☝️
add all frequency =50
❤
How about the number of classes, where did you get it Sir?
It's either given or you can decide.
good job despite the pronunciation! thank you, sir!
How did you get that numbers on the top, my teacher only shown us class interval and frequency. Help!
It is from given data.
For the midpoint part you said the way you get the answer is you did 4+15 divided by 2 and when I insert that in the calculator it gives me 11.5 not 9.5.
Am I missing a step?
Please watch this video: ruclips.net/video/NxmgnmH2MYM/видео.html
I wonder how he counted by 12, some of people counted by 5 only how come he used highest number in Classes,plz someone explain ?🤧
How do we figure out that how many classes do we have to make if it's not mentioned in our question?
Please contact your teacher. You may need to set your own classes (5 to 20 classes, depending on your data set).
how does this work? Midpoint column you said 4+15 / 2 = 11.5 (not 9.5 as you have ) ?
(4 + 15) / 2 = 19/2 = 9.5, thanks!
Can a class midpoint be a decimal or whole number or both?
both
❤❤❤❤❤
You are very welcome! 😃
How do you round off 6.35 to the whole number?
Depending on the course
Statistics -7
Mathematics -6
wow Iam the statistics of student
How did u get the number of classes
Either given or you decide
very good and helpfu
l video
You are welcome!
how we can calculate 1+3.322log of n?
That’s the formula for getting the CI the n in the formula means count all the numbers giving together which is 50 . Put this 50 where the n is and look for the LOG of 50
E.g
1+3.322(log50)
1+3.322(1.698)
6.64 round it up
7,,
Here how to find tally l donot understand
Where did u get the 50?
That's the number of data
how is the min 4 how do it look like 4 anybody help
Among the data, 4 is the smallest data, so it is the min data.
Hello how did you get 15?
The second-class lower limit is 16. So, the first-class upper limit must be 15 so that no confliction for data
Off topic but can i ask why does your accent sound like Korean English accent ? Or just mind is still in SK.....
Hi, are you studying in the U.S?
@@helpyourmathstat No , India .
why is the number of classes not 6?
The question is asking for 7 classes.
Are u from south Korea
Yes!
why your counting 12 ?
classes:
4-15
I thought we count by 5 only ?
It depend on the number of classes you need. Not always 5.
By any chance, are you a Korean?
Dr. Jae Ki Lee is from Korea. Thanks!
I got one question why u have divided 7 its a stable nubmber to find out intervals i just confused? Thanks for replying i really wants to know that
It's just an example. Dr. Jae Ki Lee chose 7. You can choose any number from 5 to 20 (Suggested). However, homework problems may give you the number. Thanks!
Apprecaite it but donot u think it might it effects my intervals example u have chosen 7 but if i choose 9? Thank u for replying
@@imanomar1862 The intervals won't be the same. Therefore, instructors normally give the number, then all students will have the same answers.
Thank u so much
you have to use this formula in order to get number of classes, Number of class / k / = 1+3.332log of n, n means number of observation Then k = 1+3.332 log 50 , log50= 1.698 .Therefore, k= 1+3.332 x 1.698= 1+5.65 = 6.65. Finally, round this decimal number which gives us 7. So, number of class is 7
While calculating midpoint why aren't you are using class boundaries
Shouldn't it be the same? You get the same midpoints?
@@helpyourmathstat yeah we get the same but we were taught to do it with class boundaries.
@@vishalacharya5683 Follow your instructor. Please know that we can find midpoints without knowing the boundaries. Thanks! :)
Thanks
You are very welcome!
❤
Thank you!
But, why did you uses 7, as a number of classes 🤔? Did you just selected any random number?