If anyone wants to know the proof for the log idenity here is it Spolier: note: if log does not have a base then it is 10 consider log(B) when you rase it to the negative 1 power then it will be 1/log(B). using the fractional rule Log(B) can be expessed as LogB/log10. so log(B)=LogB/Log10 now raise both sides by the power of -1 now you have 1/Log(B)=Log(10)/Log(B) using the fractional for and turing it back into a log thing you get 1/Log(B)=Log(baseB) of 10
This makes no sense... First of all why are you using log base ten when the proof involves all possibe bases... And all you done was multiply by one wjen you busted out long10(10)
richard always makes a problem look so easy
Wow, he’s back with a vengeance!
Doing this without calculator is craz
MAN, you look like BATMAN! I mean Christian Bale.
If anyone wants to know the proof for the log idenity here is it
Spolier:
note: if log does not have a base then it is 10
consider log(B) when you rase it to the negative 1 power then it will be 1/log(B).
using the fractional rule Log(B) can be expessed as LogB/log10.
so log(B)=LogB/Log10
now raise both sides by the power of -1
now you have
1/Log(B)=Log(10)/Log(B)
using the fractional for and turing it back into a log thing you get
1/Log(B)=Log(baseB) of 10
This makes no sense... First of all why are you using log base ten when the proof involves all possibe bases... And all you done was multiply by one wjen you busted out long10(10)
It doesn't have be log base 10 but I said log base 10 @@jimpim6454 😓
@@RR-bs9mr it's actually not clear at all what you done I'm sorry the last sentence I cannot make sense of
I do agree it pretty difficult to read@@jimpim6454
I probabaly will edit to make more sense