Art of Problem Solving: 2015 AMC 10 A #25 / AMC 12 A #23

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  • Опубликовано: 24 окт 2024

Комментарии • 23

  • @anticorncob6
    @anticorncob6 9 лет назад +3

    I am unofficially taking the test soon (so I won't watch this video until after that) and was surprised the problems page wasn't posted on the website, then found these videos and realized they were literally uploaded like 10 - 20 minutes ago. I hope to see the complete list of problems to print and take.

  • @chuyanwang1072
    @chuyanwang1072 5 лет назад

    Learned a lot from your videos! I am going to take the test in just a few days, thanks!

  • @wontpower
    @wontpower 7 лет назад +7

    This solution is actually pretty intuitive

  • @CodeWizard808
    @CodeWizard808 9 лет назад +16

    I was wondering why you don't make the videos for the AMC 10B or 12B anymore - my school only offers the B and even though I know that the solutions are on the website, I'd like to see you explain them in these videos - and by the way, these are great. I only got 2 out of the last 5, and I want to see in detail how to do the others so I can better prepare for the test next year :)

    • @rajpanchal9226
      @rajpanchal9226 8 лет назад

      hey what is the difference between A and B?

    • @neelmondal9027
      @neelmondal9027 8 лет назад +7

      The 10A and the 10B (or the 12A and the 12B) are given 2-3 weeks apart. Although the questions are different, the B tests are designed to be the same difficulty as their A counterpart. Both tests are actually made in advance, and a coin flip determines which one is used as the A test. MAA gives an A and a B test since some people may have a conflict on the A testing date.

    • @rajpanchal9226
      @rajpanchal9226 8 лет назад

      Thanks:) Neel Mondal

    • @jingranmo7398
      @jingranmo7398 6 лет назад

      That year A was way harder than B tho

  • @eugenewong2617
    @eugenewong2617 9 лет назад +4

    This made me hurt more than the test itself

  • @coolcowusacosolutions744
    @coolcowusacosolutions744 5 лет назад +2

    Most amazing solution... :)

  • @rajpanchal9226
    @rajpanchal9226 8 лет назад +2

    I wonder why someone disliked it?

  • @JohnSmith-vq8ho
    @JohnSmith-vq8ho 7 лет назад

    In the second part of the question, adjacent sides, why is the region less than 1/2 a quarter circle but not a right triangle?

    • @newkid9807
      @newkid9807 5 лет назад

      x^2 + y^2 = 1/4 will be circle since all of the x's and y's will have the 1/2 being circleu

  • @miamininja2338
    @miamininja2338 9 лет назад

    This is a great solution!

  • @AntonioMac3301
    @AntonioMac3301 5 лет назад

    bro this is amazing

  • @edgarwang4659
    @edgarwang4659 9 лет назад +2

    beautiful

  • @shreyjha1974
    @shreyjha1974 3 года назад

    For case 2 why is there a quarter circle?

  • @Wondermultiverse
    @Wondermultiverse 9 лет назад +3

    Please tell me how this my thinking is wrong:
    Place a point randomly on the perimeter. The next point, will be out of the 1/2 range if it lands away from the 1 diameter of the original point. Hence the probability must would be 3/4.

    • @moraigna66
      @moraigna66 9 лет назад

      It's not a random point you're talking about, it looks more like a point directly on the middle of a side.

    • @moraigna66
      @moraigna66 9 лет назад +1

      Yes my bad: corner or middle of a side, but not ANY point.

  • @M_Chen333
    @M_Chen333 6 лет назад +7

    This video has the saddest squares I've ever seen xD