1. get a time machine 2. kidnap mr ruszcyk from the future 3. tell him he has to tell you all the answers or else you will make him do 100! by hand 4. get 150/150 flawless
@@vinh8022 a bit late here but with enough experience, you can quickly see that if the expression is in between two consecutive multiples of n, then they will all round down, thus creating a multiple of 3.
For a number with prime factorization x^a*y^b, to choose a factor, we can choose x^c where c=0, 1, 2,..., a and y^d where d=0, 1, 2, or..., b. There are a+1 choices for exponents for the X factor, and b+1 for the y factor. So, in total there are (a+1)*(b+1) factors. Hope that helps.
"i like throwing away fractions" - Richard Rusczyk(while wiggling eyebrows)
poor fractions what did they ever do
@@RedOctober_ They’re foul creatures that are annoying..
can you give me your eyebrows please :(
Nice Work Mr. Rusczyk!!
I am watching this in South Korea. Thanks.
Really enjoy your work. Rusczyk.
One day this going to be a chapter mathcounts CDR problem...
How am I suppose to get all of this during the test?
Ideally u shouldnt have to test to see such an obvious pattern
1. get a time machine
2. kidnap mr ruszcyk from the future
3. tell him he has to tell you all the answers or else you will make him do 100! by hand
4. get 150/150
flawless
@@yashuppot3214 well no, you have ample time to test a little then find the answer. That's what I did
@@yashuppot3214 What's the ideal method in your opinion?
@@vinh8022 a bit late here but with enough experience, you can quickly see that if the expression is in between two consecutive multiples of n, then they will all round down, thus creating a multiple of 3.
How many t-shirts does the grand mathematician have now?
Cool Solution, Rusczyk
Bro Rusczyk pls come back...
Love the videos!
Nice example of using inductive reasoning
So it seems that illegal contraband AMC 10As are out already. (Hasn't been 24 hours yet in my time)
It's AoPS. They're not going to post an AMC 10 related video until its discussion is allowed.
Anybody know what the cutoff will be?
google it.
@@alexwang982 pokyu
HI RICHARD U ARE THE BESTTTT
I didnt understand the end.
For a number with prime factorization x^a*y^b, to choose a factor, we can choose x^c where c=0, 1, 2,..., a and y^d where d=0, 1, 2, or..., b. There are a+1 choices for exponents for the X factor, and b+1 for the y factor. So, in total there are (a+1)*(b+1) factors. Hope that helps.
i wish he were my math teacher (the eyebrows are fire)
geeky captain america