Equation of motion in a rotating frame: deriving the fictitious force terms

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  • Опубликовано: 2 мар 2021
  • Here's how to use the operator relation for time derivatives in a rotating frame to show how fictitious force terms (centrifugal, Coriolis and Euler) arise. It may be helpful to watch my previous video first: • Time derivatives in a ...
    About me: I studied Physics at the University of Cambridge, then stayed on to get a PhD in Astronomy. During my PhD, I also spent four years teaching Physics undergraduates at the university.
    My website: benyelverton.com
    #physics #maths #math #mechanics #dynamics #fictitiousforces #coriolis #centrifugal #euler #forces #rotation #rotatingframes #inertialframes #calculus #vectors #differentiation #operators #particle #motion #circularmotion

Комментарии • 23

  • @r2k314
    @r2k314 Год назад +2

    Thank you for that derivation of all the fictitious forces, it was very elegant I thought.

  • @starstuff11
    @starstuff11 Год назад +2

    I find it much simpler to solve for such rotational frames with Lagrangian mechanics.

    • @DrBenYelverton
      @DrBenYelverton  Год назад +1

      Fair enough, perhaps a topic for a future video!

  • @alonkritkumar5548
    @alonkritkumar5548 5 дней назад

    Notations are beautiful

  • @Electromowls
    @Electromowls 3 года назад +2

    I am electrical engineer, enjoying these videos alot 😍.

  • @peterpoli2839
    @peterpoli2839 3 года назад +2

    I'm also studying physics at cambridge, this is really helpful

    • @DrBenYelverton
      @DrBenYelverton  3 года назад

      Great to hear - good luck with the course!

    • @peterpoli2839
      @peterpoli2839 3 года назад

      @@DrBenYelverton I’m currently preparing for IB physics exams rn, the lectures are shockingly terrible. You think this channel would be a good substitute?

    • @DrBenYelverton
      @DrBenYelverton  3 года назад +1

      @@peterpoli2839 I have a couple of videos that are relevant to the IB course, but as a relatively new channel I don’t have anywhere near enough content yet for this to be a viable alternative to lectures. The best advice I can give for exam prep is just to do as many past papers as you can. I know it’s annoying that there are no mark schemes (even when I was supervising I didn’t have access to such things) but you can often get a good sense of whether you’ve answered a question correctly (e.g. many questions are “show that”; you can also check things like dimensions and whether the order of magnitude of your result is sensible). The way I always did things was just to try exam questions and look things up in the lecture notes when I didn’t know something, rather than try to learn all the theory first and then test myself. While the lectures are not always great, the lecture notes are generally pretty good and contain everything you need to know.

    • @moneyheist_-
      @moneyheist_- 6 месяцев назад

      ​@@DrBenYelvertonWhat evidence is there against the geocentric model called the Neo-Tychonic model in which the planets revolve around the sun, but the sun revolves around the earth in the center?

    • @samlewis2985
      @samlewis2985 3 месяца назад

      @@moneyheist_- so much 😂

  • @r2k314
    @r2k314 Год назад +1

    I just read for the first time: The same result could also have been obtained with the Euler-Lagrange
    equations for L in the rotating coordinates:
    L = m/2(r˙ + ω× r )^2 − V .!

    • @DrBenYelverton
      @DrBenYelverton  Год назад +2

      Indeed, I've been meaning to do a video on this for a while!

    • @r2k314
      @r2k314 Год назад +1

      @@DrBenYelverton looking forward to it!

  • @amanbajracharya7403
    @amanbajracharya7403 Год назад +1

    Lovely❤

  • @adibakarlen
    @adibakarlen 2 года назад

    no matter how many video, i dont get it. it confuse me

    • @DrBenYelverton
      @DrBenYelverton  2 года назад +1

      It is certainly not an easy thing to understand at first! Ultimately the key idea is that in a rotating frame, the rate of change of a vector quantity is different from what we might expect, because the basis vectors themselves are changing over time. See this video for the details: ruclips.net/video/Vautr1lDJ78/видео.html

  • @peterpoli2839
    @peterpoli2839 2 года назад

    Coming back to this video, your frame notation on the derivative seems to be a bit confusing.... A time derivative operator will always be the same no matter what frame (leaving special relativity out of this).

    • @DrBenYelverton
      @DrBenYelverton  2 года назад +1

      Yes, according to the formal definition the d/dt (S) operator is the "true" time derivative. Personally I do find the d/dt (S') notation to be helpful for conceptual understanding because it's the operator that gives the rate of change that would be observed in S'. But looking at it from a strictly mathematical point of view I can see how it might cause confusion.