Bead on a rotating hoop: equilibrium positions

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  • Опубликовано: 11 окт 2024
  • Finding the equilibrium positions of a bead constrained to move on a frictionless rotating hoop. We'll also use physical arguments to decide whether each equilibrium position is stable or not.
    About me: I studied Physics at the University of Cambridge, then stayed on to get a PhD in Astronomy. During my PhD, I also spent four years teaching Physics undergraduates at the university. Now, I'm working as a private tutor, teaching Physics & Maths up to A Level standard.
    My website: benyelverton.com/
    #physics #dynamics #mechanics #mathematics #maths #math #rotation #rotatingframes #centrifugal #force #fictitiousforces #weight #normalreaction #contactforce #equilibrium #frictionless #hoop #bead #constraint #constrainedmotion

Комментарии • 8

  • @drandrewsanchez
    @drandrewsanchez 3 года назад +5

    love this. I'm personally interested in the classical mechanics and love these examples

    • @DrBenYelverton
      @DrBenYelverton  3 года назад

      Excellent, I'll try to keep the examples coming!

  • @instantchanel9696
    @instantchanel9696 3 года назад +3

    Thank you so mach 😁 it really help my preparation for national olympiad

  • @nikosathanasopoulos5257
    @nikosathanasopoulos5257 Год назад

    Found that the angular frequency of small oscillations around the stable equilibrium points, when ω>sqrt(g/a) is ω0^2=(ω^4-ωc^4)/ω^2, where ωc^2=g/a. Not so sure but I'm open to any other other solutions.

  • @canopus4
    @canopus4 3 года назад

    Rotating hoop problem from David Morin's book

  • @danielpe8533
    @danielpe8533 2 года назад +1

    hi, thanks that was realy helpfull! I would just like to know, because that's something I didn't realy understand- why you shouldn't include N in the equation of newton's second law?

    • @DrBenYelverton
      @DrBenYelverton  2 года назад +1

      I'm glad it was helpful! The force N doesn't appear in the equation because we resolved in the tangential direction. It's a purely radial force, so doesn't have any component in the tangential direction.