Swami, I just solved a puzzle using two hidden pairs two aics and several other techniques I've learned from your videos. I'm just learning this game and thanks to you I'm winning. Thank you so much!!!!!! Richard Vanderpool
Hidden Pair at 30:04 1. Examine this row. 2. These two squares are the only squares that can contain 1 and 2 in this row. Therefore, the other notes in these squares can be erased. Hidden Pair at 30:50 1. Examine this column. 2. These two squares are the only squares that can contain 1 and 6 in this column. Therefore, the other notes in these squares can be erased. Hidden Pair at 32:28 1. Examine this block. 2. These two squares are the only squares that can contain 7 and 9 in this block. Therefore, the other notes in these squares can be erased.
@Sudoku Swami, I wondered exactly what you had in mind when you commented (at about 26:45) that "sometimes two or three different solving techniques will produce the same result"? That comment really hit home for me at that point, since I find it so difficult to see hidden subsets that I never look for them - instead, I look for the complementary *naked* subset that must (by definition) also be present. In the example you were talking about at that point, I would have quickly noticed the naked quadruple (2, 3, 4, 5) in block 5 - or even the naked (2, 3, 5, 9) in row 6 - and used that to expose the locked pair (6, 7). By the way, very nice, clear explanations of everything! I'm watching your videos to try to learn how to recognize chains and other advanced techniques, but I greatly appreciate the way you make the simpler techniques very transparent and easy to understand, and I'll be recommending your videos to a friend who is just starting out in Sudoku.
You're right. A Hidden Pair or Triplet will ALWAYS also have a Naked Subset (usually of a larger size), in the same House. That's what I look for, when I am solving puzzles. If you can easily see Quads and Quints and Sixers, then there is no need to look for "Hidden" Subsets.
@@SudokuSwami I find naked Quads and Quints to be easier than even hidden Pairs. Sixers are probably harder than hidden pairs, but still easier than hidden Triples.
It looks like you live in literal paradise. With all this sheltering in place your videos are also giving me a sight for sore eyes... it's beautiful! What state is that?
The short answer is, "Yes." There are two ways to come upon a Naked Pair. 1.) All possible Candidates are filled in, and the presence of solved Cells around the puzzle preclude all but the same two Candidates in two Cells that lie in at least One House. 2.) You started with all the possible Candidates filled in, and then you have methodically eliminated Candidates using various solving techniques to a point where there are two Cells within a House that each contain ONLY the same two Candidates.
Dear Swami, why is it that Sudoku instructors such as yourself are unable to count from 1 to 100 IN ORDER? I just found your channel and Tutorial 9 quite by accident, have not been able to find #1, #2, etc. And what is the difference between tutorials and episodes ?? Thanks, Jim Straus
I am quite confident that I can hold my own in counting numerically from 1 to 100, and even further. Here is a link to the entire Playlist for my Complete Course in Sudoku. Please note that the Videos in this list appear in chronological order: ruclips.net/p/PLzg42yqvfiLKESOIrp-NlQ-lgvtuwO5JE
A Tutorial is a focused teaching session given by a tutor to a student, or group of students. An Episode, is an event occurring as a part of a larger sequence. My Videos are both tutorials and episodes.
Hey Jako, I got stumped on a very difficult puzzle in Hodoku, so I asked for a hint. The hint I got was a technique called "Remote Pair." I've never seen this before and can't find any videos you've made on it. If I missed it, can you please give me a pointer to it? I would like to understand the logic behind it.
@sudokuswami, at 26:07, is there not also a hidden pair in Row 4: 1 & 9? Also … in another puzzle at 27:57, isn’t there also a hidden pair of 5 & 9 in Column 9?
Naked and Hidden PairsQuestion for Mr Swami (or anyone)Say we have 2 cells in a house which contain a Naked Pair eg..(2,3) and (2,3) no other 2's or 3's in the house or block.But in a different puzzle we have the same Naked Pair, but this time there is a rogue '6' in just one of the Naked Pair cells eg..(2,3) (2,3,6) with other 6's elsewhere in the house, Does this now constitute a Hidden Pair. Does every Hidden Pair become a Naked Pair after Other Cell Candidate elimination within the Hidden Pair cells...thankyou Rab
To your first question, Yes, but only if the 2 and the 3 do not appear anywhere else in the particular House. You would simply remove that rogue six, and be left with the Naked Pair. But remember a House can be a Row, Column or Block, and it is possible for the Pair to exist in a Row and a Block, or a Column and a Block, at the same time. And to your second question, Yes, of course. But by turning a Hidden Pair into a Naked Pair, there is nothing further you can do at that point, because there will already be no other instances of those two Candidates in the rest of that House.
If you have a house with a lot of bi-value cells in them, like a 3 and a 7, how did you know, you made the right choice by selecting those cells, as seen early on in the video? In theory, you could make the same conditional statement, about any other bi-value cell, (if they existed) Thanks.
Hello Cap'n. Your question is vague and not clearly stated. I do not understand what you are asking. There cannot be more than two Bi-Value Cells in any particular House that would contain a 3 and a 7, for instance,......(or any A and B).....because those Candidates CANNOT be True (possible) for any other Cells in that House. If I have not answered your question, please ask again, and try to be more scientific and precise. Thank you.
@@SudokuSwami Apologies for the confusion. Please look at the 10:21 mark in the video. Is the reason the 2-5 naked pair are selected ( R4C2 and R7C2) because they are the only cells in that column that have a naked pair? In other words, you can't choose, R3C2 because it's not a bi-value cell (like the colored cells in the video.) Is that right? I hope that is clearer.
A Bi-Value Cell is a Cell where there are only two possibilities left for that Cell. When you have TWO IDENTICAL Bi-Value Cells that lie in at least One House, then you can be certain that those two Cells must be solved for those two Candidates, one way or the other. This is a Naked Pair. And it means you can remove those two Candidates from all other Cells in that House. In the hand-drawn diagram at 10:21, Cells R4C2 and R7C2 contain ONLY 2 and 5. They are a Naked Pair. This means one of those Cells must be solved for 2 and the other must be solved for 5, even though we don't yet know which is which. But it means that 2 and 5 CANNOT be possibilities for any other Cells in Column 2.
This is a good question. First, the term "Locked" in Sudoku, can be used TWO different ways. Some people describe ANY Subset as being "Locked." In other words, even a Quintuplet can be deemed Locked, even though it is not contained within BOTH a Line (a Row or Column) and a Block. This usage is common when talking about Almost Locked Sets. The OTHER meaning of Locked is applied to the case where a Subset lies in TWO Houses at the same time, which can only be possible for Pairs and Triplets. Only Pairs and Triplets can be Locked into TWO Houses at the same time, because the intersection of a Line and a Block only has three Cells. So to answer your question, a Hidden Pair can turn out to be Locked (according to the second definition), but you will only know it, after you discover it, and remove the other Candidates from those two Cells.
@@SudokuSwami Thanks. I now also realize that it is actually not important because with hidden pairs the deletion of the candidates takes place in the cells where the pair is located.
Naked Pair at 20:06 1. Examine this block. 2. These two squares can only contain 3 and 7. 3. Therefore, no other square in this block can contain 3 or 7. Naked Pair at 20:54 1. Examine this column. 2. These two squares can only contain 5 and 9. 3. Therefore, no other square in this column can contain 5 or 9. Naked Pair at 21:19 1. Examine this row. 2. These two squares can only contain 4 and 5. 3. Therefore, no other square in this row can contain 4 or 5.
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the repetition of examples helps a lot, thanks
Swami, I just solved a puzzle using two hidden pairs two aics and several other techniques I've learned from your videos. I'm just learning this game and thanks to you I'm winning. Thank you so much!!!!!!
Richard Vanderpool
Glad to hear it. Well done.
If you enjoyed this Video, please don't forget to click the SUBSCRIBE button, and the Thumbs Up Icon. It will really help me out. Thank you!
Hidden Pair at 30:04
1. Examine this row.
2. These two squares are the only squares that can contain 1 and 2 in this row. Therefore, the other notes in these squares can be erased.
Hidden Pair at 30:50
1. Examine this column.
2. These two squares are the only squares that can contain 1 and 6 in this column. Therefore, the other notes in these squares can be erased.
Hidden Pair at 32:28
1. Examine this block.
2. These two squares are the only squares that can contain 7 and 9 in this block. Therefore, the other notes in these squares can be erased.
@Sudoku Swami, I wondered exactly what you had in mind when you commented (at about 26:45) that "sometimes two or three different solving techniques will produce the same result"? That comment really hit home for me at that point, since I find it so difficult to see hidden subsets that I never look for them - instead, I look for the complementary *naked* subset that must (by definition) also be present. In the example you were talking about at that point, I would have quickly noticed the naked quadruple (2, 3, 4, 5) in block 5 - or even the naked (2, 3, 5, 9) in row 6 - and used that to expose the locked pair (6, 7). By the way, very nice, clear explanations of everything! I'm watching your videos to try to learn how to recognize chains and other advanced techniques, but I greatly appreciate the way you make the simpler techniques very transparent and easy to understand, and I'll be recommending your videos to a friend who is just starting out in Sudoku.
You're right. A Hidden Pair or Triplet will ALWAYS also have a Naked Subset (usually of a larger size), in the same House. That's what I look for, when I am solving puzzles. If you can easily see Quads and Quints and Sixers, then there is no need to look for "Hidden" Subsets.
@@SudokuSwami I find naked Quads and Quints to be easier than even hidden Pairs. Sixers are probably harder than hidden pairs, but still easier than hidden Triples.
Thanks for making intermediate soduko understandable like no one else.
Hello Brianja. Glad to hear you find my Lessons useful. If you ever have any questions, please let me know. :-))
you helped me understand claiming thanks i will try to learn other more advanced techniques from you
Thank you!!!
Great explanation and demonstration. Thank you!
Merci
It looks like you live in literal paradise. With all this sheltering in place your videos are also giving me a sight for sore eyes... it's beautiful! What state is that?
Not in the USA........
I watched several different tutorials and didn't get the pairs thing. Now I understand thank you your explanation was great.
Awesome! Glad to hear it. :-))
And when in doubt, AIC Type II is quite useful, lol.
Does the house containing the naked pair have to have all possible candidates notated before deciding if the pair is naked?
The short answer is, "Yes." There are two ways to come upon a Naked Pair. 1.) All possible Candidates are filled in, and the presence of solved Cells around the puzzle preclude all but the same two Candidates in two Cells that lie in at least One House. 2.) You started with all the possible Candidates filled in, and then you have methodically eliminated Candidates using various solving techniques to a point where there are two Cells within a House that each contain ONLY the same two Candidates.
@@SudokuSwami Thanks for your prompt and clear reply! I've watched several other tutorials that were helpful in general but not as clear as yours.
best!! by far
Dear Swami, why is it that Sudoku instructors such as yourself are unable to count from 1 to 100 IN ORDER? I just found your channel and Tutorial 9 quite by accident, have not been able to find #1, #2, etc. And what is the difference between tutorials and episodes ??
Thanks, Jim Straus
I am quite confident that I can hold my own in counting numerically from 1 to 100, and even further. Here is a link to the entire Playlist for my Complete Course in Sudoku. Please note that the Videos in this list appear in chronological order: ruclips.net/p/PLzg42yqvfiLKESOIrp-NlQ-lgvtuwO5JE
A Tutorial is a focused teaching session given by a tutor to a student, or group of students. An Episode, is an event occurring as a part of a larger sequence. My Videos are both tutorials and episodes.
Hey Jako, I got stumped on a very difficult puzzle in Hodoku, so I asked for a hint. The hint I got was a technique called "Remote Pair." I've never seen this before and can't find any videos you've made on it. If I missed it, can you please give me a pointer to it? I would like to understand the logic behind it.
Never mind... I found it.
@sudokuswami, at 26:07, is there not also a hidden pair in Row 4: 1 & 9?
Also … in another puzzle at 27:57, isn’t there also a hidden pair of 5 & 9 in Column 9?
Yes, and yes.
@@SudokuSwami Thank you, sir! 🙏🏻
Naked and Hidden PairsQuestion for Mr Swami (or anyone)Say we have 2 cells in a house which contain a Naked Pair eg..(2,3) and (2,3) no other 2's or 3's in the house or block.But in a different puzzle we have the same Naked Pair, but this time there is a rogue '6' in just one of the Naked Pair cells eg..(2,3) (2,3,6) with other 6's elsewhere in the house, Does this now constitute a Hidden Pair. Does every Hidden Pair become a Naked Pair after Other Cell Candidate elimination within the Hidden Pair cells...thankyou Rab
To your first question, Yes, but only if the 2 and the 3 do not appear anywhere else in the particular House. You would simply remove that rogue six, and be left with the Naked Pair. But remember a House can be a Row, Column or Block, and it is possible for the Pair to exist in a Row and a Block, or a Column and a Block, at the same time. And to your second question, Yes, of course. But by turning a Hidden Pair into a Naked Pair, there is nothing further you can do at that point, because there will already be no other instances of those two Candidates in the rest of that House.
Be sure to visit sudokuswami.com for an Outline of the Entire Course, and news about upcoming Videos!
If you have a house with a lot of bi-value cells in them, like a 3 and a 7, how did you know, you made the right choice by selecting those cells, as seen early on in the video? In theory, you could make the same conditional statement, about any other bi-value cell, (if they existed) Thanks.
Hello Cap'n. Your question is vague and not clearly stated. I do not understand what you are asking. There cannot be more than two Bi-Value Cells in any particular House that would contain a 3 and a 7, for instance,......(or any A and B).....because those Candidates CANNOT be True (possible) for any other Cells in that House. If I have not answered your question, please ask again, and try to be more scientific and precise. Thank you.
@@SudokuSwami Apologies for the confusion. Please look at the 10:21 mark in the video. Is the reason the 2-5 naked pair are selected ( R4C2 and R7C2) because they are the only cells in that column that have a naked pair? In other words, you can't choose, R3C2 because it's not a bi-value cell (like the colored cells in the video.) Is that right?
I hope that is clearer.
A Bi-Value Cell is a Cell where there are only two possibilities left for that Cell. When you have TWO IDENTICAL Bi-Value Cells that lie in at least One House, then you can be certain that those two Cells must be solved for those two Candidates, one way or the other. This is a Naked Pair. And it means you can remove those two Candidates from all other Cells in that House. In the hand-drawn diagram at 10:21, Cells R4C2 and R7C2 contain ONLY 2 and 5. They are a Naked Pair. This means one of those Cells must be solved for 2 and the other must be solved for 5, even though we don't yet know which is which. But it means that 2 and 5 CANNOT be possibilities for any other Cells in Column 2.
@@SudokuSwami Thanks for clearing that up for me.
Can you also have a locked hidden pairs or are locked pairs always naked pairs?
This is a good question. First, the term "Locked" in Sudoku, can be used TWO different ways. Some people describe ANY Subset as being "Locked." In other words, even a Quintuplet can be deemed Locked, even though it is not contained within BOTH a Line (a Row or Column) and a Block. This usage is common when talking about Almost Locked Sets. The OTHER meaning of Locked is applied to the case where a Subset lies in TWO Houses at the same time, which can only be possible for Pairs and Triplets. Only Pairs and Triplets can be Locked into TWO Houses at the same time, because the intersection of a Line and a Block only has three Cells. So to answer your question, a Hidden Pair can turn out to be Locked (according to the second definition), but you will only know it, after you discover it, and remove the other Candidates from those two Cells.
@@SudokuSwami Thanks. I now also realize that it is actually not important because with hidden pairs the deletion of the candidates takes place in the cells where the pair is located.
You are correct, sir.
Naked Pair at 20:06
1. Examine this block.
2. These two squares can only contain 3 and 7.
3. Therefore, no other square in this block can contain 3 or 7.
Naked Pair at 20:54
1. Examine this column.
2. These two squares can only contain 5 and 9.
3. Therefore, no other square in this column can contain 5 or 9.
Naked Pair at 21:19
1. Examine this row.
2. These two squares can only contain 4 and 5.
3. Therefore, no other square in this row can contain 4 or 5.
Z
X
great!! thank you