ma'am, I'm not able to understand what is "i" and "n" in this video @10:50 Can you also elaborate a little on how you brought 2nd row elements in the video @10:44 Please help me ma'am.
This video is a continuation of earlier videos on the Jacobian Matrix, so It might help if you watch those first - notation like "i" and "n" are explained there. It's a little hard to figure out what videos go in what order in the youtube playlist, but if you go to my website robogrok.com and then click 'Go to Course' for 'Robotics 2', you will see the whole map laid out. You want to start at 'Jacobian Matrix' in the 'Kinematics' heading. I think that especially video 2 there will help you.
As long as you can represent the path with a parametric equation, it will work the same way. So, suppose you want to take a path that is an arc of a circle. You could use these equations: X=cx+r*cos((v/r)*t) and Y=cy+r*sin((v/r)*t) where v is the velocity of the end-effector, r is the radius of the circle, and cx and cy are the X and Y positions of the center of the circle. Now, take the time derivative to get Xdot and Ydot, and the rest of the calculations and coding is the same.
ma'am, I'm not able to understand what is "i" and "n" in this video @10:50 Can you also elaborate a little on how you brought 2nd row elements in the video @10:44 Please help me ma'am.
This video is a continuation of earlier videos on the Jacobian Matrix, so It might help if you watch those first - notation like "i" and "n" are explained there. It's a little hard to figure out what videos go in what order in the youtube playlist, but if you go to my website robogrok.com and then click 'Go to Course' for 'Robotics 2', you will see the whole map laid out. You want to start at 'Jacobian Matrix' in the 'Kinematics' heading. I think that especially video 2 there will help you.
@@asodemann3 Thankyou alot ma'am, these videos are really helpful!
could you tell me where do you get the method to simplified the matrix? I feel confused.
i mean the references
could someone tell me how to calculate the anglular velocites wx, wy and wz in the jacobian? i have verything working but that
Do you still need help ?
Good video! What if the path we want to take is non linear?
As long as you can represent the path with a parametric equation, it will work the same way. So, suppose you want to take a path that is an arc of a circle. You could use these equations: X=cx+r*cos((v/r)*t) and
Y=cy+r*sin((v/r)*t) where v is the velocity of the end-effector, r is the radius of the circle, and cx and cy are the X and Y positions of the center of the circle. Now, take the time derivative to get Xdot and Ydot, and the rest of the calculations and coding is the same.