Practice drawing SN1 vs SN2 reaction mechanisms and products with more than 9 examples

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  • Опубликовано: 22 дек 2024

Комментарии • 25

  • @dijunwang4831
    @dijunwang4831 Год назад +1

    Another question I have is at 20:30, when we deal with the resonance structures, do we need to consider the matter of trans or cis for the double bond? For example, the chlorine leaves and the methyl group is on the plane. But can it form a cis (Z) in the double bond?
    Thank you :)

  • @rahaelj.3437
    @rahaelj.3437 2 года назад +1

    For the problem with the secondary allylic and the H20 at 18:28 I'm confused as to why the whole chlorine group doesn't leave...? Wouldn't the that whole bond attached to the chlorine leave as well?

    • @visuallearners1832
      @visuallearners1832  2 года назад +2

      It does. The remaining bond is actually methyl that was coming out of the page in the reactant. It becomes planar once carbocation is created.

    • @rahaelj.3437
      @rahaelj.3437 2 года назад

      @@visuallearners1832 OHHH okok I see what you mean! Thank you so much! This vid was really helpful :)

  • @russelwagner659
    @russelwagner659 2 года назад +2

    For the 6th problem (11:50), once the Cl leaves, why can't you shift the charge over from the adjacent methyl? Is it because it's an Sn2 reaction?

  • @dijunwang4831
    @dijunwang4831 Год назад

    Hi Sir. Thanks for your video. I have a question at 16:50. Why do we have to draw a flipped configuration at this point? It seems that we don't need to consider stereochemistry because chlorine is on the plane :)

    • @visuallearners1832
      @visuallearners1832  Год назад

      Since it is SN2 you will need to flip chirality. You can draw the product however you want as long as it has flipped chirality from the reactant.

    • @dijunwang4831
      @dijunwang4831 Год назад

      @@visuallearners1832 Thank you Sir!!! I think you explain a lot of important details that didn't appear in other ochem videos I've watched. Gratitude beyond words Sir!!

  • @ammar-c9u
    @ammar-c9u Год назад +1

    what software do you use bro?

  • @visuallearners1832
    @visuallearners1832  2 года назад +3

    You are correct. Since it uses acetone (Aprotic) as solvent it will do SN2. So no rearrangements and carbocation formation.

    • @russelwagner659
      @russelwagner659 2 года назад

      Ok, amazing video by the way. EXTREMELY helpful

  • @yeabsiradessalegn2181
    @yeabsiradessalegn2181 2 года назад +1

    Thank you so much 🙏

  • @hassaniqbal8009
    @hassaniqbal8009 2 года назад +1

    Very helpful thank you soo much

  • @mykateha0297
    @mykateha0297 Год назад

    Thank you so much, it helps a lot🙏

  • @mykateha0297
    @mykateha0297 Год назад

    22:05 it's 2° right? Can we make it to be 3°??

    • @visuallearners1832
      @visuallearners1832  Год назад

      It is secondary and benzylic. You cannot rearrange it to 3 as there is a benzene ring on the left side.

  • @herosr719
    @herosr719 Год назад

    Hey why is I replacing cl
    Cl is a bad leaving grp right

    • @visuallearners1832
      @visuallearners1832  Год назад

      Both Cl and I are good leaving group. Relatively, I is a better LG then Cl. However, the driving force of this reaction is solubility. NaCl and NaBr do not dissolve in acetone, whereas NaI does.

    • @herosr719
      @herosr719 Год назад

      @@visuallearners1832 oh

  • @lintamariajoseph5354
    @lintamariajoseph5354 6 месяцев назад

    Sorry i dont understand on 11.10, where the chirality, like its attached to 2 methyl groups, its the same

  • @MadiaZab
    @MadiaZab 2 года назад

    Thank you for a very helpful video. For the very last example with SN1 reaction, how is that a chiral center after Br leaves?

    • @visuallearners1832
      @visuallearners1832  2 года назад +1

      It will eventually make a chiral center once nucleophile attack. So you should treat as such once carbocation created in order to get correct stereochemistry.

  • @atdr-q9z
    @atdr-q9z Месяц назад

    pls upload a pdf of thiss