I think for the last question we can equate them first to test if we can find the root that can makes them equal. So in this case 1/(x+1) = x/2 has 2 roots -2 and 1. Because -2 is still
Hi, GRE Ninja. Firstly, Big fan of your content. Keep up the honest work. But Correct me if I am wrong... Regarding Question #2: Although calculating range of values helps us eliminate 3 options, that itself isn't sufficient to ascertain that all the values within range are possible. This is because a & b are integers. We have to factorize the remaining two options to make sure they comply to the limitations of both a & b. For example, there are primes within the range which don't comply with the restrictions of a>60 & b
Thank you so much! We hired Adam Sandler's brother to do these videos. He's funny, but not nearly as funny as he thinks he is. ;) Have fun studying, Amanda!
For the average question you don't need to do all that algebra, right? The means are equal which means sum A/5 = sum B/4. Because sum B is only divided by 4 and 4A
We can say that because the sum of the items in list A divided by 5 is equal to the sum of the items in list B divided by 4, the sum of the items in list A is greater than the sum of the items in list B. The sum of the items in list A is 9 + 5m + n and the sum of the items in list B is 9 + 4n, so we can say 9 + 5m + n > 9 + 4n, which simplifies to m + n > 0. From this, we can't say whether n is greater than 4. It's possible that m is -5, so n needs to be greater than 4 to make m + n > 0 work. However, it's also possible that m could be 5, so n could be less than 4 and we still satisfy m + n > 0. All this shows that the algebra that Charles used in the video explanation is, sadly, necessary to reach the answer to this question. I hope that helps!
Yes, definitely! The "new" GRE isn't all that different from the old one -- it's just shorter, but the quant content is completely identical. So all of our quant videos apply equally to the old and new versions of the exam. I hope that helps a bit, and have fun studying!
Oh wow, I see that you had the same experience with two of our videos. I'm answering on this particular video ("Episode 0") because it makes me wonder if you're struggling with carelessness more than anything else -- maybe you get complacent on the easier ones, but do a much better job of focusing when the questions start to feel difficult? If that's the case... well, the processes I babble about in this video might be more important for you than for many test-takers. Adaptive tests are annoying in that sense: if you slip up on questions that aren't actually hard for you, the test will punish you disproportionately. I might be way off here -- it's hard to diagnose test-takers using just a couple of brief comments. But if I'm barking up the right tree, hopefully this gives you some good food for thought. Have fun studying, and thank you for watching!
![FNAF Into the Pit has A LOT of Unused Graphics | LOST BITS [TetraBitGaming]](http://i.ytimg.com/vi/6YhZCRdipl4/mqdefault.jpg)
Your videos are gem
Thank you so much, Garv! Have fun studying.
i was really confused about the math section and oh my god i have Just watched this video and already a fan❤
Thank you so much! ❤️❤️❤️
I think for the last question we can equate them first to test if we can find the root that can makes them equal.
So in this case 1/(x+1) = x/2 has 2 roots -2 and 1. Because -2 is still
Hi, GRE Ninja. Firstly, Big fan of your content. Keep up the honest work.
But Correct me if I am wrong...
Regarding Question #2: Although calculating range of values helps us eliminate 3 options, that itself isn't sufficient to ascertain that all the values within range are possible. This is because a & b are integers. We have to factorize the remaining two options to make sure they comply to the limitations of both a & b. For example, there are primes within the range which don't comply with the restrictions of a>60 & b
Thank you for this!!
Thank you so much for watching!
This guy is hilarious. Thanks for your videos.
Thank you so much! We hired Adam Sandler's brother to do these videos. He's funny, but not nearly as funny as he thinks he is. ;)
Have fun studying, Amanda!
Really Good Tutorial. I enjoyed it
Thank you, Joseph!
@@GRENinjaTutoring sir please tell the answer of 2th question its option C or D
@@LioPaul-qp7ks The question says Select "All" which is correct/applicable. And for this question, there are two answers.
Thanks ❤
Thank you so much for watching and for being so positive!
For the average question you don't need to do all that algebra, right? The means are equal which means sum A/5 = sum B/4. Because sum B is only divided by 4 and 4A
We can say that because the sum of the items in list A divided by 5 is equal to the sum of the items in list B divided by 4, the sum of the items in list A is greater than the sum of the items in list B.
The sum of the items in list A is 9 + 5m + n and the sum of the items in list B is 9 + 4n, so we can say 9 + 5m + n > 9 + 4n, which simplifies to m + n > 0.
From this, we can't say whether n is greater than 4. It's possible that m is -5, so n needs to be greater than 4 to make m + n > 0 work. However, it's also possible that m could be 5, so n could be less than 4 and we still satisfy m + n > 0.
All this shows that the algebra that Charles used in the video explanation is, sadly, necessary to reach the answer to this question.
I hope that helps!
4 out 4 - But I guessed and moved on the one w/ the average. Lol.
Haha! Hey, guessing is a skill. I'll take it. ;)
Have fun studying, Joe! And please keep us posted on your progress.
- Charles
Great stuff! Are the contents of these videos applicable to the new GRE equally?
Yes, definitely! The "new" GRE isn't all that different from the old one -- it's just shorter, but the quant content is completely identical. So all of our quant videos apply equally to the old and new versions of the exam.
I hope that helps a bit, and have fun studying!
Hlo sir, I completed vocab words but I am finding hard in solving vocab questions. So pls do suggest a way to crack
Then there's me....
I got the last one correct and the easy ones incorrect....
Oh wow, I see that you had the same experience with two of our videos. I'm answering on this particular video ("Episode 0") because it makes me wonder if you're struggling with carelessness more than anything else -- maybe you get complacent on the easier ones, but do a much better job of focusing when the questions start to feel difficult?
If that's the case... well, the processes I babble about in this video might be more important for you than for many test-takers. Adaptive tests are annoying in that sense: if you slip up on questions that aren't actually hard for you, the test will punish you disproportionately.
I might be way off here -- it's hard to diagnose test-takers using just a couple of brief comments. But if I'm barking up the right tree, hopefully this gives you some good food for thought.
Have fun studying, and thank you for watching!