But you can solve it utilising ratio , no? The way I did it (to work out how much 1 part is) , I multiplied the coefficients in (11C+3T=756) by their respective part of the ratio ( 11*3+3*7 parts = 756 -> 54 parts = 756 -> 1 part =14 ) and then once you know how much 1 part is you can obviously work out how much 1 kg of each is by doing 3*14=42 and 7*14=98
Nice method :) just a small note that writing 11*3+3*7 = 756 is a little inaccurate. It shouldn’t matter but try to avoid using the equality symbol in that way. Also I shouldn’t have implied there was only one way to solve the problem!
But you can solve it utilising ratio , no? The way I did it (to work out how much 1 part is) , I multiplied the coefficients in (11C+3T=756) by their respective part of the ratio ( 11*3+3*7 parts = 756 -> 54 parts = 756 -> 1 part =14 ) and then once you know how much 1 part is you can obviously work out how much 1 kg of each is by doing 3*14=42 and 7*14=98
Nice method :) just a small note that writing 11*3+3*7 = 756 is a little inaccurate. It shouldn’t matter but try to avoid using the equality symbol in that way. Also I shouldn’t have implied there was only one way to solve the problem!
HI where do you find these problems. I would like to solve them. :D