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U saved my life bro 😭😭😭

10Q i have some concept

How do u solve this equation....(2y+3)to the power of two=25

learnt more from this 10 minute video than my actual teacher

❤the simplicity

Who else is watching this in august 2024

Hello! Thank you for your very clear explanation, i have a question: this proofs seem true only when alfa and beta are acute angles. How to prove that they hold for any alpha and beta (even negative or 188 degrees or 520 degree or any other angle)?

Thanks 🙏

why does your base number the same I thought it had to be added?

Pakia😊

I love you

Can you do more of this please

I'm writing a math exam like tomorrow, pressure 😅😅😅

Thanks... This was very helpful.

im so tapped

I have a test tomorrow, like ok Imma fail but at least I understand what I'm about to fail😊😊welp I'll fail mostly if it's fractions

😂😂

I'm just bad at math I'm 😮 still lost

I have an exm in an hour and I am here. I AM SO DEAD TOADY ! Update: I think I'll pass

Thank you

on the last question you did not confirm how you got 3p, but overall it was a good video

is this substitution

cool

Thank you so much, this helped a lot!

I think this trigonometric eq could be solved another way: if we multiply both sides by sin(x), and use the identity 2sin(u)cos(u)=sin(2u) twice, we reach this equation: sin(4x)cos(3x)=sin(x) Now, using the identity sin(p)cos(q)=1/2(sin(p+q)+sin(p-q)), we reach 1/2((sin(7x)+sin(x))=sinx or equivalently, sin(7x)=sin(x) which results in 7x=2kpi+x and 7x=(2k+1)pi-x which leads to two general answers: x=k(pi/3) and x=(2k+1)pi/8 Since k*pi which is the zero-making roots of the multiplying factor, sin(x), and is not the root of the original equation, we have to put this limitation on k: k can be any integer number but the coefficients of 3. For the 2nd general answer, we don't have such a problem insomuch as 2k+1 would never be equal to any integer coefficient of 8 and this form of answer is valid for any k.

literally thank you so much i owe you my grades omd

So helpful

Thanks so much bro I’ve learned more in a 7 minute video than 10 months of gcse

Thanks 😊 much sir

3 days until my maths paper 1 mock god help me

Exam tmrw but how come you can’t use ven diagram for question 4 a??

My teacher is the best in the world and I'm watching this just because it's part of my syllabus

Thanks sir your are the person I have found who have clarified my doubts with easy formulas which made me understand easier

sos hermoso, explicas mejor que la peroncha de la profe de matematica!!

you explain so well omg

It might take me a few looks at the tutorial in order for me to figure out the equations

Watching this the day of exam

Im a year 8 and i got a big test tmrw so im just trying to atleast get 70 😢

you saved my life

You could have done Q14 in an easier way We know that the ratio of tulips to roses is 6:5 so we can say 6/11 of the total number of flowers are tulips We also know that the ratio of red tulips to yellow tulips is 3:4 so we can say 3/7 of the total number of tulips are red So out of our total number tulips (6/11) 3/7 of them are red So we do 6/11 x 3/7 which will give us 18/77 And the video was great! Thanks for the help!

I like the video

This was genuinely a life saver here in 2024 I don’t think my math teacher could compare

I have a test today, I will update if I failed or not, if so how bad I failed

😍😍😍

I don't understand either

Watching a day before my exam, thanks so much 😂

isent the hypotenus always the longest angle ?

Who else here for get 100 percent in summer assessment 😭😭🖤

thanks!

You’re the best