Binomial Probability (2 of 2: Further Example & General Case)

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  • Опубликовано: 29 янв 2025

Комментарии • 8

  • @distorteddingo9230
    @distorteddingo9230 2 года назад +4

    You're the greatest Math teacher we've NEVER had but wished for, just someone to simplify it all. Thank you

  • @sparksfly5572
    @sparksfly5572 5 лет назад +9

    you r the best sir.
    Thank you so much for uploading these videos

  • @ranganathansriraman4983
    @ranganathansriraman4983 3 года назад +7

    Your explanations are fantastic. It kindles so much interest, very well done!!

  • @somanathdash8143
    @somanathdash8143 4 года назад +3

    Good video 😃

  • @rafiashraf2769
    @rafiashraf2769 7 лет назад +9

    4:43 what was that yelling?

  • @JerGol
    @JerGol 3 года назад +1

    Lightbulbs going on over here. Thanks Eddie.

  • @beyond_hannah7167
    @beyond_hannah7167 3 года назад

    hey, can this be one of your examples?
    Considering the composition of a group of 5, imagine three members were to be drawn at random to represent your group for a presentation. The member chosen can either pass or fail the presentation. However, for your group to pass, at least one member should pass the presentation. The members can be chosen with or without replacement. (Hint: Use probability tree) i. Under each situation, obtain the probability distribution of passing