Hey Eddie, a typical uncommon problem that tends to be asked in binomial probability is, "What is the most likely number of defective shirts?". Just a thought that comes to mind. You should make some videos on harder 4u probability. Anyways keep up the good work! :p
Hi Eddie, I got a question. Is this a problem with replacement or without replacement? Because logically when we pick up a shirt, we do not put back and repick right? shouldnt it be without replacement and thus binomial cant be used?
I tried to add it up and i got 0.0127 Are you meant to multiply to the power of the dfects/good shirts where ever it is written? Why didnt you finish the problem?!
Hello Eddie! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?
wait.... the probability of greater than or equal to 2 defects and then they made the complement that included the probability of two defects? shouldn't it be the complement of P(0)+ P(1)?
The 4/125 comes from the calculation of P(any shirt being defective). As he said, this is = P(JD)+P(FD). Earlier we calculated that P(JD) is 0.02*(20/50), which equals 0.008. P(FD) is 0.04*(30/50), which is 0.024. So if we sub those two calculated values into the equation, we get P(any shirts being defective) = 0.008+0.024, which equals 0.032. OK, so now you need to change the 0.032 from a decimal into a fraction, so it is 32/1000. Then you want to reduce that fraction to lowest form (I think there are other videos on how to do that). Turns out, if you divide the numerator and the denominator both by 8, that gives you the fraction of 4/125. So that is where he got that fraction that represents the P(any shirt being defective). I am pretty sure, anyway. Hope that is helpful in the long term.
I can't believe this quality of math lesson just exists on RUclips free of charge
8:41 sounds like minecraft spider noise
Hey Eddie, a typical uncommon problem that tends to be asked in binomial probability is, "What is the most likely number of defective shirts?". Just a thought that comes to mind. You should make some videos on harder 4u probability. Anyways keep up the good work! :p
Hi Eddie, I got a question. Is this a problem with replacement or without replacement? Because logically when we pick up a shirt, we do not put back and repick right? shouldnt it be without replacement and thus binomial cant be used?
Hold up u were on Ted talk huh?
I tried to add it up and i got 0.0127
Are you meant to multiply to the power of the dfects/good shirts where ever it is written?
Why didnt you finish the problem?!
Hello Eddie! kind help me here: In batch of 100 screws, a maximum of 3 can be defective. A random sample of 20 screws are taken. How many defective parts are allowed in this sample considering all scenarios probabilities less than or equal to 90%?
wait.... the probability of greater than or equal to 2 defects and then they made the complement that included the probability of two defects? shouldn't it be the complement of P(0)+ P(1)?
Wow❤
"you sent me 4 bad shits, this is rubbish you must be joking.... its a joke" i dont get it... someone explain please?
Joe King... Fay King.... those are the siblings and they are known for making terrible shirts!
i cant believe how he worked fast past his defect answer, because a student MAYBE might of ask how you got it? Not from the answer key I hope
Can anyone tell me how the 125 shirts was found in 6:40?
The 4/125 comes from the calculation of P(any shirt being defective). As he said, this is = P(JD)+P(FD). Earlier we calculated that P(JD) is 0.02*(20/50), which equals 0.008. P(FD) is 0.04*(30/50), which is 0.024. So if we sub those two calculated values into the equation, we get P(any shirts being defective) = 0.008+0.024, which equals 0.032. OK, so now you need to change the 0.032 from a decimal into a fraction, so it is 32/1000. Then you want to reduce that fraction to lowest form (I think there are other videos on how to do that). Turns out, if you divide the numerator and the denominator both by 8, that gives you the fraction of 4/125. So that is where he got that fraction that represents the P(any shirt being defective). I am pretty sure, anyway. Hope that is helpful in the long term.
@@ebellyfish4256 I really appreciate taking time to explain this to me. Thank you!!
@@ebellyfish4256 thanks for doing the math and explaining it for us.
Blackpa