Practice Problem: Pendulum Velocity

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  • Опубликовано: 8 сен 2024
  • Now you're really getting advanced with your building skills. Check out this pendulum. It's a good thing we know about potential energy and kinetic energy, because that will allow us to calculate the velocity of the pendulum at any instant. Give it a try!
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Комментарии • 74

  • @umario251
    @umario251 4 года назад +44

    It is 6:38 AM, this is due for today, I'm studying at uni, this problem sheet counts for my finals, you saved my life, thank you so f*cking much!!

  • @SealiosWasTakenSomehow
    @SealiosWasTakenSomehow 3 месяца назад +1

    Science 10 Exam in about 2 hours, I couldn't find any questions or help at ALL in my class history and online. Your video helped so SO much, thank you!

  • @jekerijekeri1230
    @jekerijekeri1230 5 лет назад +29

    OMYGASH! I LOVE YOU! I HAVE SPENT AN HOUR FINDING THE RIGHT EQUATION. THIS IS SO AWESOME. THANK YOU SO MUCH! ♥️

  • @senpainezvi9037
    @senpainezvi9037 7 лет назад +16

    Thank you, this kind of videos are great bcs you're clearing my "knowledge holes".
    I'm so thankfull, keep this typ of tutorials up

  • @arusakasai8126
    @arusakasai8126 Год назад +1

    I have struggled with physics bc the book and notes are so bare bones that I don't know all these rules apply. TY for your help

  • @JamesCandongo
    @JamesCandongo 4 месяца назад

    You save my grades in physics thanks prof❤

  • @DeadpoolPlayz
    @DeadpoolPlayz 2 года назад +1

    This will help me calculate my swinging when i finish my webshooters! Thank you!

  • @evergreensarahthethought1820
    @evergreensarahthethought1820 3 года назад +1

    Thanks a lot. Love from Bangladesh 🇧🇩🇧🇩

  • @MShazarul
    @MShazarul 3 года назад

    I completely forgotten this to solve for my max angular velocity. Great thanks!
    My module is solid mechanics and vibration.

  • @DaniFilth87
    @DaniFilth87 7 лет назад +2

    I did it differently (just a little bit). I didn't bother to calculate the amount of energy, but instead changed the formula Epot1 + Ekin1 = Epot2 + Ekin2 (with Ekin1 and Epot2 being both 0) all the way down to v=sqrt(2*g*h). It's basically the same, but a lot easier imo

    • @tarkhamknight209
      @tarkhamknight209 2 года назад

      just helped me out dude. thanks :)

    • @Soul-cu8zn
      @Soul-cu8zn Год назад

      Isn't this the formula or something

  • @borristhebrave7496
    @borristhebrave7496 Год назад

    Thanks for the digestible physics video. Love you for this

  • @ramratiram1152
    @ramratiram1152 7 лет назад +4

    Really an amazing tutorial...... Awesome

  • @fadlyahmad9363
    @fadlyahmad9363 3 года назад +1

    if you was creative,you can actually cut the mass because 1/2mv2=mgh,so you just can drop it

  • @trulluyt5814
    @trulluyt5814 2 месяца назад

    Let's say that at the release point, it is moving with some initial tangential velocity. So then you can calculate the total energy of the system by calculating the KE at that point and the PE. Now, we can convert all that to PE and find maximum height, and therefore angular displacement. Using that angular displacement, you can have the function: theta(t)=theta(max)sin(root(g/l)t). You differentiate the function and you take the coefficient as the maximum angular velocity. You multiply that with the length of the string to calculate linear velocity. This linear velocity will, for some reason, be different from the normal energy conservation method. Why does this happen? I genuinely don't know.

  • @deletedaccount4350
    @deletedaccount4350 2 года назад +1

    Awesome tutorial!!Thanks

  • @pasinduranawakage
    @pasinduranawakage 3 года назад +1

    Love it. Very practical 💞 easy to understand

  • @mst83d-kh32
    @mst83d-kh32 3 месяца назад

    Watching in 2024, thank you for your simple and amazing explanation, you saved me,...

  • @nickodemuskhaemba8447
    @nickodemuskhaemba8447 3 года назад

    thanks much professor you are my best teacher ever.

  • @jeff9959
    @jeff9959 3 месяца назад

    my savior.

  • @carlypowers1449
    @carlypowers1449 Год назад

    You should label the length of the string at the start of the video

  • @shabinrahman6007
    @shabinrahman6007 4 года назад +1

    It was amazing......! Thank you very much.........

  • @ahmedtcreations
    @ahmedtcreations 3 года назад

    . A pendulum is raised to a height of 10cm above its lowest position and released. Calculate its maximum velocity. (Take g = 9.8ms-2)

    • @carultch
      @carultch 2 года назад

      You don't even need to think about the fact that it is a pendulum to answer this question. It is a simple trade of GPE for KE, that allows you to derive the equation v=sqrt(2*g*h). That is the advantage of conservative forces, is that the work done by them is independent of path.

    • @ahmedtcreations
      @ahmedtcreations 2 года назад

      @@carultch yesss thanku

  • @mirzahamizan25
    @mirzahamizan25 2 года назад

    thank very much for your video

  • @mykilpee
    @mykilpee 5 лет назад +1

    This made me purchase a graphing calculator so I didn't have to write a program every time I wanted to do some equations. That being said, I put it all into 1 equation and simplify to make it easy. I just wanted to make sure I had the equations right. It's been over 10 years, and I still got it. But I still need a cheat sheet to reference. :-(
    Where to get those now...

  • @KapilSharma-tm9sz
    @KapilSharma-tm9sz 3 года назад +1

    Hii sir I have seen your explanation of this question. We can solve it also by using Newton's Equation of Motion, but I am unable to solve it by Newton's EOM. Can you please provide me the solution w.r.t Newtons EOM?

  • @BigDaddyDexter
    @BigDaddyDexter 2 года назад +1

    so how do we get the distance?

  • @claribelperez4355
    @claribelperez4355 2 года назад

    but the height is 2 m - (2 m(1-cos(35)), You opposite side is the half of the amplitude and the adjacent is the relaxed length.

  • @AtaurRahman-wg6pt
    @AtaurRahman-wg6pt 4 года назад +1

    How Can we calculate angular velocity using angle and time? Plz help

  • @vaedkamat484
    @vaedkamat484 2 года назад

    how I do I find the height of the pendulum from the bottom if you don't give me the length of the string

  • @rodericksibelius8472
    @rodericksibelius8472 2 года назад

    What is the Formula for the time, t, when the Pendulum has practically stopped?, so many explanations of the basics but there is no discussion of the real world engineering physics of the pendulum accounting some given parameters, air viscosity, drag, tension, diameter, weight of the string and density of the air... etc. I have been trying to figure this out as an engineering technician with a limited calculus background of the damping effects as explained presented in those formulas of 'differential equations'. t, stopped = ???????????????. does anybody know the derivation of the Formula?... Thank You.

  • @HadiAlAzawi
    @HadiAlAzawi 4 года назад

    Thank you

  • @amdventurellc6043
    @amdventurellc6043 4 года назад

    i have a question about pendulums. There is a math question that says that there is a pendulum makes a initial swing of 15 inches (arc). each successive swing travels 95% of its preceding swing and it swings forever. What it the total distance traveled by the ball? My question is when that pendulum was initially let loose to swing its arc of 15 inches (left to right) when it goes that first right to left, does it do the full 15 inch arc or even on the 1st return it only does 95% of the 15 inches?

    • @carultch
      @carultch 2 года назад

      The question is il-defined, about what counts as a "swing" and how the 15 inches of the first swing is measured. It isn't obvious to me whether a full cycle is a swing, or just from turning point to turning point.
      In any case, you would solve this with an infinite series of an exponential decay.
      Swing 1 is 15 inches
      Swing 2 is 15 inches * 0.95
      Swing 3 is 15 inches * 0.95^2
      Swing K is 15 inches * 0.95^(K-1)
      Add up
      15*0.95^(K-1), from K equals 1 to infinity. There are formulas for infinite series when each summed term is an exponential function of the index variable K.

    • @billieswig8658
      @billieswig8658 2 года назад +1

      @@carultch Carl you were two years too late 💀

  • @dilrubalipi9254
    @dilrubalipi9254 4 года назад

    At the lowest point velocity is maximum.. So can I use the formula... Velocity= omega × amplitude

  • @norarodriguez9842
    @norarodriguez9842 5 лет назад

    you're amazing

  • @vmededucation
    @vmededucation 7 лет назад

    Thanks sir

  • @echonuim
    @echonuim 4 года назад

    what happens if you cut the pendulum at its maximum displacement position

  • @pranavdeosant4492
    @pranavdeosant4492 5 лет назад +2

    which software you used for animation

  • @binyammamo707
    @binyammamo707 3 года назад

    how about the angular velocity? How can I calculate it?

  • @nihil32
    @nihil32 Год назад +1

    Could someone explain why there is no potential energy at the lowest point? I have physics exam and my teacher wont accept it if I simply say the potential energy there is 0. I would be grateful.

    • @bkk28200
      @bkk28200 5 месяцев назад +2

      Potential energy is theoretical energy 😅 Just how much work you can do!
      eg: at the height of 2m above the ground, a body of 40kg has the potential to have 800 N kinetic energy. But at the ground you cannot do anymore. Because you've changed all your mechanical energy into thermal, sonic,..... Energies 😅
      Btw, depending on the situation your reference can be your table or any other thing.

    • @thorpedo8540
      @thorpedo8540 4 месяца назад +2

      Man did the exam 1 year ago 😂

  • @cayanlamanna
    @cayanlamanna 2 года назад

    for some reason my physics books tells me im wrong when solving this way. It says I should solve with “v=AW”

  • @robbiedahal3977
    @robbiedahal3977 6 лет назад +1

    But what is the acceleration of pendulum at maximum height? I am confused, either zero or it is maximum. Plz help me

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад +1

      acceleration is constant! it's the acceleration due to earth's gravity.

    • @carultch
      @carultch 2 года назад

      Acceleration of a pendulum is not constant, because the tension force varies throughout its swing, and only the component of gravity that is tangent to the path causes a change in speed. Acceleration of a pendulum is complicated, because both centripetal and tangential acceleration come in to play. Tangential acceleration is simple, and follows approximately the same trend as a mass/spring oscillator, where it is maximum at its extreme positions, and zero at the "equilibrium" position at the bottom.
      I put the word "equilibrium" in quotes, because the pendulum is not in static equilibrium at the bottom of its swing, but we still call it that anyway. There is centripetal acceleration that also comes in to play, that is primarily caused by the tension in the connecting rod or cord. The tension both opposes the radially outward component of gravity, and provides the inward centripetal acceleration. Other than the trivial case of a pendulum that remains indefinitely at rest at the equilibrium position, there is no position in a pendulum's swing where the acceleration equals zero.
      Here is an animation showing how acceleration varies throughout the swing:
      en.wikipedia.org/wiki/Pendulum_(mechanics)#/media/File:Oscillating_pendulum.gif
      For a simple pendulum, there is a critical amplitude of 53.13 degrees where the centripetal acceleration at the bottom equals the tangential acceleration at the turning point in magnitude. The total acceleration isn't constant in this special case. For smaller amplitudes than this, the turning point tangential acceleration is where acceleration is greatest. For amplitudes larger than this, the centripetal acceleration at the bottom is the greatest.

  • @bo-shianchen5712
    @bo-shianchen5712 4 года назад

    The opening is fun lol

  • @ScopeSource
    @ScopeSource 3 года назад +1

    "If a pendulum is 40m and attached at a 45-degree angle, how far will the pendulum fall at its lowest point?"

    • @rm.2876
      @rm.2876 3 года назад +1

      That's from Spider-Man Ps4, anyways answer is 11.72m

    • @ScopeSource
      @ScopeSource 3 года назад +1

      @@rm.2876 haha! You got the reference 😪

  • @waleedqureshi6551
    @waleedqureshi6551 3 года назад

    What do you do when you are not given the mass in the problem?

    • @CoreTorque
      @CoreTorque 3 года назад +1

      The Time (the Period of the Pendulum) is independent of mass and amplitude ie: T = 2π * √(L/g)
      Hope this helps

  • @Brooklynair14k
    @Brooklynair14k 5 лет назад

    how did you get 4.08?

  • @ma.donalinetablante8609
    @ma.donalinetablante8609 3 года назад

    Can someone explain to me how sin35°=x/2.0m went to 1.15 meters 😣 because when i input sin35°(2) the answer is -0.856365339
    Where did i went wrong? 😅😅

  • @leenns1196
    @leenns1196 2 года назад

    Is this conserved mechanical energy?

  • @aaronbeverly976
    @aaronbeverly976 Год назад

    @3:40 why did you multiply 4.17J by 2?

  • @Redsky973
    @Redsky973 7 месяцев назад

    I mean i used Vmax=A*w but yeah i still got 4m/s

  • @saketkumar4972
    @saketkumar4972 4 года назад

    i understand your process, but with my process i get a diff answer, which is frustating me,fuck

  • @MM-vi9kh
    @MM-vi9kh 3 года назад

    In 2:57
    Sin(35)*2=0.85 not 1.15
    How is it come?

  • @Jan-sf7xv
    @Jan-sf7xv 4 года назад

    thanks, i had a similar problem in my homework. Even though it was from a schoolbook i was beginning to think it's actually impossible to solve. A bit arrogant from me lol.

  • @crawfordclive
    @crawfordclive 6 лет назад

    GREAT TUTORIAL.......... BUT WHAT HAPPEN TO CONSERVATION OF ENERGY IF THE WEIGHT KEEPS SWINGING? AFTER FIRST CYCLE ALL CYCLES MUST BE OVER UNITY UNTIL THE WEIGHT COMES TO A COMPLETE STAND STILL......

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад

      energy is transferred by collision to atmospheric particles, the friction is what brings it to a stop eventually.

  • @saketkumar4972
    @saketkumar4972 4 года назад

    fuck im getting mad

  • @lunam7249
    @lunam7249 Год назад

    my cat hates you now....

  • @jhosuacardona5890
    @jhosuacardona5890 2 года назад

    Thank u lord jesus😘