Kinetic Energy and Potential Energy

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  • Опубликовано: 7 мар 2017
  • You can put energy into an object. Wanna know how? No, you don't need a Harry Potter wand. Just lift it up above your head! By doing so, you bestow the object with more potential energy. Learn more about the energy of motion and the energy of location in this clip.
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Комментарии • 331

  • @mohamadjarrar8776
    @mohamadjarrar8776 3 года назад +142

    Here I am studying MSc in Engineering but watching this rather simple video I guess I needed something as simple and clear as this video after being lost in the details, something like this reminds you of the essence of these basic concepts.
    It's not a shame to go over these simple terms (other simple terms also) every once and a while as I get some sort of refreshness and a slight smile of how things were nice and simple.
    Great video, thank you.

  • @bebros2858
    @bebros2858 Год назад +69

    bro is the physics jesus

  • @sotl97
    @sotl97 4 года назад +73

    Professor Dave. You are frik'n smart man. Thank you for sharing this video on RUclips. You're the best!

  • @christospapaioannou928
    @christospapaioannou928 2 года назад +26

    I dont know if anyone has noticed but Professor Dave seems to know a lot about the science stuff. All jokes aside our videos are really helpful and I watch them every time we learn a new unit in physics.

  • @purplestacks
    @purplestacks 5 лет назад +38

    I use to hate ur intro and the way you explain things. Lately I've been realizing that you are proficient when it comes to concepts especially when it comes to physics. Keep this subscription forever and I hope you continue uploading videos. Thank you for helping an electronics engineering student who is so terrible at physics.

    • @YN-zv6ov
      @YN-zv6ov 3 года назад +1

      @Ashay Playz he said sorry. And what do u expect the world is full of hate

  • @heythere384
    @heythere384 5 лет назад +11

    Wow !
    You defined potential energy quite perfect .

  • @bilas2645
    @bilas2645 6 лет назад +267

    W= mad

  • @E-2.71
    @E-2.71 5 лет назад +4

    I enjoy Professor Dave's videos, helps me learn subject better!!

  • @dkwhattouseasusername1012
    @dkwhattouseasusername1012 9 месяцев назад +3

    Just discovered this channel but wow, really good, his explanations are simple and easy to understand

  • @kyuu2
    @kyuu2 3 года назад +6

    I feel so proud of myself actually getting the practice problem right lol. Thank you so much!

  • @ilyverse
    @ilyverse 3 года назад +3

    THANK YOU SO MUCH! I HAVE TO WRITE AN ESSAY ABOUT POTENTIAL AND KINETIC ENERGY AND THIS HAS HELPED ME A LOT :)

  • @arshilzia3842
    @arshilzia3842 7 лет назад +42

    I did it by other method
    First I found k.E
    1/2×50×11.2×11.2=3136J
    As it transfers 1539J to another body so 3136-1539=1597J
    So new kE is 1597J
    1/2mv^2=1597
    1/2×50×v^2=1597 ( as mass is given 50)
    25v^2=1597
    V^2=1597/25
    V^2=63.88
    V=7.99

    • @robertstewart3922
      @robertstewart3922 6 лет назад +8

      I did it the same way as you @cartoon stories. I don't completely understand Dave's way of working this out. Would be good if he could add an explanation to his calculations.

    • @arshilzia3842
      @arshilzia3842 6 лет назад +3

      robert stewart yes you're he should add more explanation/information about equations or calculation specially in physics

    • @kuiizoo
      @kuiizoo 4 года назад +1

      I'll... just watch the video, thanks. but great explanation. :)

    • @devikas.9088
      @devikas.9088 3 года назад +1

      yep i also did it this way

    • @sheikhamohammed5142
      @sheikhamohammed5142 2 года назад

      Can I ask how we got the 7.99 at the end

  • @seanfox121
    @seanfox121 4 года назад +3

    Thanks so much! This video was really helpful!

  • @clayton2117
    @clayton2117 4 года назад +4

    I remember when I was a kid jumping on my trampoline I’d take my mums keys and let them go as I was coming up or falling back down but what supprised me (besides the fact that the keys and I fell at the same speed) was that when I let them go as I was coming up they would go higher then me but then still fall at the same speed, back then I didn’t know what gravity was or that things fell at the same speed but it was so mesmerising letting go of the keys because they’d kind of just move in slow motion as they were faking

  • @myprofilepictureisbeberexha
    @myprofilepictureisbeberexha 3 года назад +2

    Thanks Professer my school teacher showed us the video and it helps me alot.

  • @honeybee2145
    @honeybee2145 4 года назад +8

    Concepts are very clearly and briefly explained. I like Prof. Dave's videos.

  • @MrMarkgyuro
    @MrMarkgyuro 4 года назад +6

    just understood, thank you Professor! I have realised it is called potential because it is potential.

  • @orb7828
    @orb7828 4 года назад +182

    im watching this in 2020 and this rlly helped me. I love ur intro!

    • @evan.5967
      @evan.5967 3 года назад +6

      I looked at your post date and it said "7 months ago" I was like are you sure it's 2020?!?!
      WTF it's been a loooong year :'(

    • @johnjavidwrencedelacruz6081
      @johnjavidwrencedelacruz6081 3 года назад

      Me too

    • @RJ-kb3qf
      @RJ-kb3qf 3 года назад +2

      Hey from the future haha can’t believe you wrote this a year ago

    • @wacotaco7884
      @wacotaco7884 3 года назад +3

      hey from the further future, I don't know why I am doing this.

    • @rogue4134
      @rogue4134 2 года назад +2

      Hey from further further future, i am doing this to ignore the work in front of me

  • @LinkFreak9999
    @LinkFreak9999 2 года назад

    Thanks once again! Love your videos.

  • @erasmith3511
    @erasmith3511 7 лет назад +3

    Very nice explanation

  • @studies9119
    @studies9119 Год назад +2

    Proffersor dave, thank you, I had a difficult time answering this question "in a frictionless enviroment, would an object of heavier mass have greater ke than a lighter mass?" until I watched this vid. Wish you the best in your future endeavours.

    • @davidmudry5622
      @davidmudry5622 Год назад

      As far as I'm concerned it's a lot easier to understand the truth of 9/11 when you realize Einstein's gravity, which Neil deGrasse Tyson says superseded Newton's gravity, does not accelerate objects down to the ground, and does not push objects down with a force. And when you do, you'll also realize objects need a support from below, where the one and only force that comes from below to give objects their weight, then you'll realize that nothing comes down unless that support underneath the object is first removed or weakened. And if that support below is weakened to the point where the object will become lighter, the object will then descend with the illusion of apparent acceleration.
      There are many, at least a dozen RUclips videos on Einstein. They all talk about Inertial Frames of reference, which both Newton and Einstein agree on, which it is when an object is not accelerating. They're both totally opposite as to when you would say an object, influenced by just gravity alone, is being accelerated. But we know it is a force of acceleration in ONE direction that is the explanation of why mass has weight in the OPPOSITE direction, like how you fall backwards when the bus takes off forwards...then you've figured it out who makes more sense about inertial frames of reference...Einstein was right, free fall is not acceleration, free fall is not kinetic energy, because free fall is weightless and is standing still.
      ruclips.net/video/E43-CfukEgs/видео.html

  • @kennyhuang7393
    @kennyhuang7393 2 года назад

    Have an exam tomorrow at 10:30 AM. Your videos are really helping me study last minute.

  • @michellekhoshaba4249
    @michellekhoshaba4249 5 лет назад +3

    You are a god sent, thank you!

  • @mareged9978
    @mareged9978 6 лет назад +6

    it would be so cool if you made versions of the videos with all the vector calculus involved

  • @Akira_drafts
    @Akira_drafts Год назад +12

    2022 and still helpfull !!! The content he teaches in under 5 mins is just awesome ! Loved it ❤

    • @nafyssacisse
      @nafyssacisse Год назад +1

      2023 and still helpful

    • @Nostlgiq
      @Nostlgiq 3 месяца назад

      @@nafyssacisse 2024 and still helpful

    • @vivitt4030
      @vivitt4030 3 месяца назад

      True

  • @rollinginthedeep6900
    @rollinginthedeep6900 Год назад

    Thank you for explaining this! I was wondering why it was necessary to ascribe an object at rest "potential energy" when it hasn't moved and isn't necessarily going to. I was wondering why we can't just say it has energy when it's actually in motion. But the pulled arrow on a bow and compressed spring examples illustrated the point, and then the clarification that potential energy exists due to an object's position in a *field*, and often when we say potential energy we are talking about gravitational potential energy. I hope I understood that but that was my take away! Thanks!

  • @swagdork2584
    @swagdork2584 2 года назад +3

    the intro was like a primary school teacher and then he starts bamboozling my brain

  • @youngsaxena2641
    @youngsaxena2641 6 лет назад +7

    you are great sir . thanks a lot.

  • @luveeii
    @luveeii 3 года назад +1

    Thanks this is really helping me I have an exam tomorrow and this will help thanks

  • @patriciaanders1332
    @patriciaanders1332 5 лет назад +11

    This was a great helpful video when discussing with my middle school student! Thank you

    • @SanaKhan-zh9gw
      @SanaKhan-zh9gw 4 года назад +1

      Ur kid's in the wrong school if he learning potential energy in middle school

    • @harshitakaushik7771
      @harshitakaushik7771 3 года назад +1

      In which standard you are ?🤔

  • @jonaswhenry9371
    @jonaswhenry9371 3 года назад

    it really helped thank you so much

  • @physicskiawazbabitaparmar4846
    @physicskiawazbabitaparmar4846 3 года назад

    Great explanation

  • @freepointsgals609
    @freepointsgals609 4 года назад +3

    This is the equation I came up with to solve for vf in the comprehension section at the end of the video. (2((w)+1/2(m)(vi^2))/(m))^(1/2)=vf What's wrong with my algebra? I'm extremely frustrated.

  • @assafgreengames4947
    @assafgreengames4947 7 месяцев назад +2

    If I'll ever feel useless, I'll remember there's people who dislikes this video

  • @sarinayaghoobian
    @sarinayaghoobian Год назад +2

    This man taught me in 4 mins what my science teacher couldn’t teach me in 4 months

  • @trenek5943
    @trenek5943 3 года назад +5

    what a mad work :D

  • @hihowareyou0000
    @hihowareyou0000 2 года назад

    Great video 😀👍💖

  • @michaelgalario6655
    @michaelgalario6655 2 года назад +6

    @prof Dave,
    Just want to ask questions for clarification.
    According to the Kinetic Molecular Theory "particles of matter constantly move". Kinetic Energy by definition is often defined as the energy of an object due to its motion. At a macroscopic level, we identify and differentiate Kinetic energy and Potential energy based on the observable motion of an object. Simply, if it's moving there is KE (energy in motion). Otherwise, PE.(energy at rest). However, at the microscopic level, as per the KMT, particles that make up matter move constantly, and this is where my understanding of KE and PE becomes a bit fuzzy: 1. Considering KMT - particles of matter are always in motion, does Potential Energy form really exist?
    Hope you could give clarification on this.

    • @thecosmosian10
      @thecosmosian10 2 года назад +1

      On microscopic level all energies are either Kinetic or potential as they are either created due to motion or particle interaction.

  • @SuperShana97
    @SuperShana97 5 лет назад +4

    Your video was short and helpful compare to other videos. I kinda got the material gradually. When I do the problem, I almost got it except the negative signs.
    I wonder why is negative ?

    • @SuperCarbohydrate
      @SuperCarbohydrate Год назад

      same question

    • @SuperCarbohydrate
      @SuperCarbohydrate Год назад

      I want to know why as well:(

    • @watermeloneo
      @watermeloneo 5 месяцев назад

      5 years late but its negative because the question states "1539J of energy is transferred" implying that its work done BY the system which is always negative like professor dave said earlier in the video

  • @TheHalalCrack
    @TheHalalCrack 2 года назад

    awsome explanation

  • @Nostlgiq
    @Nostlgiq 3 месяца назад

    Dave just taught me Hour 1-2 of Physics 4a in just 5 minutes, that's insane!

  • @kimfigueroa2914
    @kimfigueroa2914 3 года назад +10

    Since the start of online classes, some teachers are not at all efficient in explaining this. ARIGATO GOZAIMASU DAVE SENSEI!!!!!!😄

  • @zohatariq1233
    @zohatariq1233 6 лет назад

    If work is done on the system then sign should be negative?

  • @kellangemaehlich7944
    @kellangemaehlich7944 3 года назад +1

    your good i hope you get 1 million subs

  • @user-qq5es3se6s
    @user-qq5es3se6s 6 месяцев назад +1

    Thanks ❤prof dave

  • @EMH-ov8hq
    @EMH-ov8hq 3 года назад

    Professor why put negative sign in 1539J .plz can you explain me.Thank you Sir

  • @johnnieltoncanonoy9129
    @johnnieltoncanonoy9129 3 года назад +1

    Thx for this content it helps me to understand and I finish my module in science I'm grade 7 from Philippines

  • @jessicagaffney4085
    @jessicagaffney4085 5 лет назад +2

    Thank you!! very helpful!

  • @niceguy4801
    @niceguy4801 3 года назад

    Thankyou sir!

  • @gemmaleigh6051
    @gemmaleigh6051 7 лет назад +52

    Our school played this for Science! :)

  • @dash_board2026
    @dash_board2026 3 года назад +1

    Intro ... That's a great way to start a video

  • @mimidoomiraclegreatmiraclo2298
    @mimidoomiraclegreatmiraclo2298 2 года назад

    Plz sir I so grateful for ur lesson and love it, it's more understandable. But plz sir can u illustrate ur calculation, I am finding it difficult to... Plz 🙏🙏🙏

  • @buscadores6657
    @buscadores6657 4 года назад

    excuse me teacher how can you answer this question if you dont have all the values? where is the mass of the pasive object? are you just flattering or just Mad? now id like to see how to calculate 1.539 jules hitting an object with high mass lets say it hits a masive truck with no wheels. its an old and rusty truck with 45weight tns its just like a 45tons rock. whats the new velocity after the event?

  • @stormingsharks
    @stormingsharks 2 года назад +1

    I'm thinking that the reason for W being negative is for a similar reason that exothermic reactions in chemistry are negative. They transfer or "release" energy into their surroundings, which is represented by a - sign. Idk if this is a proper way of thinking about it, or if it's even correct, but it worked for me so I'm kk with it.

    • @SuperCarbohydrate
      @SuperCarbohydrate Год назад

      I have the same question as well.
      I cannot understand why it is a negative W

  • @SailorJenova
    @SailorJenova 7 лет назад +56

    I wish I knew about you when I had to take Intro to Physics like 2 years ago. I would've gotten an A NOT a B! :( Oh, well ....understanding it is more important than a grade.

    • @sayandkr4333
      @sayandkr4333 4 года назад +1

      Grades follow

    • @dhruvverma6460
      @dhruvverma6460 4 года назад +6

      @@sayandkr4333 grades relegates. It's just a number after-all

    • @FieldMarshalYT
      @FieldMarshalYT 4 года назад +12

      Imagine being upset about a B.

    • @hunzalashahid4000
      @hunzalashahid4000 4 года назад +6

      @@FieldMarshalYT imagine being super relieved cuz you passed the subject with a D XD.

    • @FieldMarshalYT
      @FieldMarshalYT 4 года назад +1

      @@hunzalashahid4000 I can relate

  • @elangop8357
    @elangop8357 Год назад

    thank you so much sir !! your videos are short and clear. initially I hated physics but after seeing your videos I got clarity about concepts . Your doing great job.

  • @leoyanshianliao6706
    @leoyanshianliao6706 Год назад

    Professor I think you forget to mention the relation of work with potential energy, I wonder if it’s work= change in potential energy

  • @albertocruz8992
    @albertocruz8992 4 года назад +2

    I have a question. In the part of the work-kinetic energy theorem, you said that when the work is negative, the system is doing a work, but in my opinion, the force is doing a work that makes that the kinetic energy of the particle decreases, and this work can be computed as the subtraction between final kinetic energy and initial kinetic energy of the system.
    What do you think?

    • @carultch
      @carultch 2 года назад

      When net work is negative, this means work is leaving the kinetic energy of the object we are studying, and the object decreases its speed. This could mean energy is being stored in the form of potential energy, or it could mean a non-conservative force such as kinetic friction is converting the energy into heat and taking energy out of the mechanical domain.
      Potential energy is a shortcut to calculate the work done by conservative forces, because it is a state function instead of a path function. It only depends on initial and final states, rather than the details of the path. When we exclude forces associated with a potential energy, and only study the non-conservative forces, the work-energy theorem changes from "KEfinal = W + KEinitial" to "KEfinal + PEfinal = KEinitial + PEinitial + Wnc". The sum total of PE+KE is what we call the mechanical energy; i.e. the energy we can exchange reversibly through the mechanical actions of the system. Wnc is the work of non-conservative forces. Such as work done by human forces to initiate the energy of the system, or work dissipated as heat by frictional forces, or work done on a human as human forces guide the system to rest. Any force that can add or subtract energy to an object in motion, for which we don't track a potential energy.

    • @ryankuykendall8303
      @ryankuykendall8303 2 года назад

      @@carultch Great explanation. I know you're responding to someone else but that's still very helpful for me, thanks xD!

    • @carultch
      @carultch 2 года назад

      @@ryankuykendall8303 Always happy to help.

    • @michdawnespera9578
      @michdawnespera9578 2 года назад

      @@carultch so does that explain why 1539 is negative because it is leaving the Kinetic Energy of the object?

    • @carultch
      @carultch 2 года назад

      @@michdawnespera9578 Yes. If kinetic energy is decreasing, that means the net work being done on the object is negative. Is there a specific issue I could help clarify, that I'm not seeing in your question?

  • @EpicSelenium34
    @EpicSelenium34 6 лет назад

    I watched a video that proposed that potential energy is not stored within an object, but instead is directly associated with the system that the object inhabits. Since energy is not really a "thing" in the physical sense of the word (it is an intangible capacity), both perspectives seem equally valid. Which one is right?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад +1

      i guess if we get super technical, the latter sounds more rigorous of a definition to me, but sometimes it's easiest to just speak colloquially and bestow objects with potential energy and things like that. a physicist would probably offer better insight!

  • @angeladoll2768
    @angeladoll2768 4 года назад

    Can someone please tell me that do all objects have potential energy?? I'm in 6th grade and it's an assignment which we've to submit the next week? Kindly help me! I'll be highly thankful!!

  • @lilosnitch3247
    @lilosnitch3247 4 года назад +1

    Can i ask u something? Im doing some research and phycis say that increase in potential energy will increase kinetic energy.A bow and arrow for example or even throwing a ball.....but in fighting like boxing and muay thai, winding up(pulling your arms back) and developing power that way is actually ineffective and very discouraged. Can u explain how in this senario it becomes different please??

    • @carultch
      @carultch 2 года назад

      "Increase in potential energy will increase kinetic energy"
      The opposite is true. Energy comes out of the potential form and converts to the kinetic form. Or vice-versa. This is what happens when no non-conservative forces come in to play. It is a trading of kinetic and potential energy.
      Human forces are not conservative forces, so the concept of potential energy doesn't apply to them. There may be parts of the concept that will apply.

  • @jeffwilken7241
    @jeffwilken7241 4 года назад +9

    Delivery is quite stiff, but I love your format and exceptionally clear writing. Thanks for making this!

    • @kelvinthehuman
      @kelvinthehuman 2 года назад

      He sticks to rigor and he's fun yet which is rather a rare combination. Only someone gifted can do something similar. Saludos desde la República Domincana!

  • @zainulhassan-pk2nz
    @zainulhassan-pk2nz 4 года назад

    Wow man you are great

  • @smitshah8074
    @smitshah8074 3 года назад

    thank you

  • @hazimahmed8713
    @hazimahmed8713 3 месяца назад

    As velocity is frame dependent, is kinetic energy also frame dependent?

  • @iftakherwazid
    @iftakherwazid 11 месяцев назад

    Is there any chance that Kinetic energy and Potential energy are equal at a height?

  • @sumeetgupta169
    @sumeetgupta169 6 лет назад

    professor dave i should tell u this but u should had explain that kinectic energy as u did with potential energy . You explained the potential well but i ma bit confused in kinetic.

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад +1

      it's the energy an object possesses by virtue of its motion, just like i explain here! you can email if you have a specific question.

  • @captainlabu
    @captainlabu 28 дней назад

    I am doing masters in theoretical physics . i was studying about electrons EPE in a experiment but suddenly forgot about PE . i guess more knowledge you gain it gets all sort of messed up in head , it needs to be cleared out time to time 😂.

  • @shanmugamv8815
    @shanmugamv8815 3 года назад +2

    What if the other object's mass is greater

  • @monirferdouskhan3346
    @monirferdouskhan3346 2 месяца назад

    Would someone please explain the difference in 'work done on a system' and work done by the system'??

  • @sudiptachatterjee1610
    @sudiptachatterjee1610 Месяц назад

    Can anyone tell me from where the 0.5 comes? I struggled to understand😢 4:10

  • @johnnyrottenpiss
    @johnnyrottenpiss 3 года назад

    Cool jingle, dude.

  • @davidkatuin4527
    @davidkatuin4527 3 года назад +1

    I have an interest in kinetic energy and I am looking for a definition as we as an example. I also think it should be broken down and simplify. I know that a ball sitting on the ground still has kinetic energy.

    • @carultch
      @carultch 2 года назад

      A ball sitting on the ground has zero macroscopic kinetic energy in the reference frame of the ground. If you look at it from a different reference frame, like the center of Earth, it will have kinetic energy as a consequence of moving with its immediate environment. It also has internal kinetic energy at the molecular level, as this is how objects store their thermal energy. Every object that isn't at absolute zero has internal kinetic energy.

  • @MonCarlo
    @MonCarlo 6 лет назад

    does this mean that an object with a greater mass has more PE? if the object is at rest why must we still consider the mass of an object?

  • @jeremycelis7489
    @jeremycelis7489 5 лет назад

    Why was the other mass canceled out??

  • @derekanderson7854
    @derekanderson7854 Год назад

    I don't understand how the gravitational potential energy can depend on height in this simple way. Suppose you take an object and increase its height by 100,000,000 kilometers; does such an object have more potential energy or less than an object at 10 meters above the ground? The object at 10m will experience much greater acceleration because the object at 100,000,000 km is so far away and thus experiences a much weaker gravitational field. Does the definition assume a uniform gravitational field throughout space?

  • @narayanidhar7899
    @narayanidhar7899 4 года назад +2

    Professor Dave sir can you please describe the problem

  • @Crescendo_theGreat
    @Crescendo_theGreat Год назад +1

    this guy has saved us from at least 1 exam

  • @edrozario5491
    @edrozario5491 6 лет назад +6

    Why is the work in the comprehension in negative value?

    • @kiahmedallo9788
      @kiahmedallo9788 5 лет назад +2

      "transfers" 1539 J energy to another object as work, so work is done "by" the system. Therefore, work has a negative value.

    • @jonah5908
      @jonah5908 4 года назад

      Can someone provide a more in depth explanation? I made the same mistake, I input the value for W as a positive integer. Please explain?

  • @ianjaypaullo1284
    @ianjaypaullo1284 3 года назад

    Finally know the right answer now😊

  • @Deeeeeeeeeeeeeeeeeeeeeeeeez
    @Deeeeeeeeeeeeeeeeeeeeeeeeez 4 года назад +6

    I wasn't careful enough so didn't take into consideration that W has to be negative. Just by the change of a sign I got my results = 13.674m/s. So just by the change of a sign I gained more energy after the impact x'D

  • @syedanaveera1871
    @syedanaveera1871 11 месяцев назад

    As object go downwards the potential energy decreases, when it reaches the ground does it have potential energy? I mean there's no height covered left so p.e will be zero. Right?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  11 месяцев назад +2

      Yes, because we assign the ground as having zero potential energy. We set the axes ourselves.

  • @nybaddies
    @nybaddies 3 года назад +3

    lol not my school showing this video for science-

  • @paulhughes1549
    @paulhughes1549 6 лет назад

    I understand this except for the math at the end. I get why those values plug into the equation the way they do, and I know that joules is kg m^2 / s^2 in SI base units. After that I'm stuck - I can't see how the equation has been simplified and rearranged. Help please Prof. Dave! Loving your videos btw

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад +1

      so first we just multiply 50 kg by 0.5 in both terms on the right side to get 25 kg, and then we factor 25 kg out of the binomial to get 25 kg times that reduced binomial then when we divide both sides by 25 kg we lose kg on the left, ending up with m^2/s^2, we add the other m^2/s^2 term from the right side, and when we take the square root its m/s! if this is still tricky, i suggest watching lots of my math tutorials!

    • @paulhughes1549
      @paulhughes1549 6 лет назад +1

      +Professor Dave Explains Thanks Professor Dave. It's a long time since I studied maths at school so I'm a bit rusty, so yeah I will have to watch some of your maths videos. (Yes "maths" with an s - that's how we say it here in the UK :) )

  • @VanityNutrition
    @VanityNutrition 6 лет назад

    I'm a bit lost as to how you got rid of the kg value from Joules. Don't the +50.0 kg and -50.0 kg cancel each other out, leaving no kg to cancel the one from Joules?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад

      I multiplied both by the one half to get 25, and then I factored that 25 out of the difference so that it operates on that other term in brackets!

  • @ngathjwokesther5880
    @ngathjwokesther5880 3 года назад

    I find it easy to watch your explanation than reading too much notes

  • @jievogarcia7206
    @jievogarcia7206 3 года назад

    Why is work negative in the end?

  • @jullianescubil3943
    @jullianescubil3943 3 года назад

    How is it when you distribute m it become become 1/2mv ?. Is it because m has and invisible 1 and the denominator is 2 therefore it becomes 1/2. ? What algebra did you exactly use for this question. To arrive at W=1/2mvf^2-1/2mv^2. I understand the how m is distributed its the denominator and 1/2 values that are really confusing to me?

    • @carultch
      @carultch 2 года назад

      The 1/2 and m are both constants, given the same object. We are interested in KE_final - KE_initial. We make two copies of the expression on the right side of the equation, KE=1/2*m*v^2, and we assign final and initial subscripts respectively.
      Since both terms have 1/2*m in common, and it is the same m in both cases (this is the salient point), we can factor that out in front, and just have (v_final^2 - v_initial^2) inside the parenthesis. Such that the expression becomes 1/2*m*(v_final^2 - v_initial^2). 1/2 obviously doesn't change between the two states, but m very well could change if there is a reason for it to change (like a rocket that loses mass after using its fuel)

  • @angelitapinto9712
    @angelitapinto9712 4 года назад +1

    i want this teacher to my school

  • @ashfaqmahmudshovon9097
    @ashfaqmahmudshovon9097 2 года назад

    As velocity is relative,Is kinetic energy relative?

  • @theunraveler
    @theunraveler 6 лет назад

    Hmm I got 6.83 m/s
    I took -1539 = 1/2(50)(v squared) - 1/2(50)(11.2 squared) which gives -4675 and I solve for the unknown v squared.
    What did I do wrong?

    • @theunraveler
      @theunraveler 6 лет назад

      Nevermind, I got it...I had forgotten to change the negative sign when I bring the numbers around....lol

  • @eviavlahos
    @eviavlahos 4 года назад

    ur a legend

  • @aloneandforlone
    @aloneandforlone 10 дней назад

    4:12 Why did we take work negative?

  • @elaafalmalek7401
    @elaafalmalek7401 3 года назад

    Why was the work negative?

  • @Thesaviorsway
    @Thesaviorsway 5 лет назад

    How do you know the second object is 50kg in mass also?

    • @manuelsalado-alvarado6121
      @manuelsalado-alvarado6121 5 лет назад

      this is probably a little late but, you are measuring the velocity of the first object after colliding. You don't have to know the mass of the second object, since you know how many joules were lost. I can go into depth if need be.

  • @frenchfried3731
    @frenchfried3731 4 года назад

    Ly man tysm

  • @habibaelhadad1000
    @habibaelhadad1000 3 года назад

    thank u

  • @kripashankarshukla4073
    @kripashankarshukla4073 6 лет назад +5

    Sir why GPE is always negative?

    • @ProfessorDaveExplains
      @ProfessorDaveExplains  6 лет назад +8

      because a negative amount of work is always done to bring an object closer to earth!

    • @gretawilliams8799
      @gretawilliams8799 6 лет назад +1

      Professor Dave Explains
      But if we lift a rock up then how does that - sign cancels out

    • @carultch
      @carultch 2 года назад

      Potential energy can be both positive and negative. It is arbitrary where we define potential energy to equal zero, although there usually is a convention for each type of force for where we define it to equal zero.
      For gravity in the uniform field approximation, we define a datum where elevation is zero, and GPE is measured relative to being zero at that datum. Negative GPE would just mean GPE that is less than the datum amount of GPE that is defined as zero.
      For universal gravitation, the convention is to define GPE to be zero, infinitely far away. In this convention, GPE will always be negative.

  • @mungkudyong4575
    @mungkudyong4575 Год назад

    Can anybody tell me why was 1539 in the solution is -1539?

  • @muhamedhameed5574
    @muhamedhameed5574 Год назад

    this may be a european problem, but does the comma in he problem depict a decimal number or is that a thousand? because i have been confused by the answer for 10 minutes