Didn't do any math until the end. 3^4 is 81 way to high. Is x is 0 then 4 becomes 1 but 2^3 wouldn't be enough. So it has to be between 0 and 1 and 1/2 or square root makes sense
While (x^n)^m = x^(n*m), that's not the case for x^(n^m). I'd say the given problem is meant to be 2^(3^(4^x)) Not ((2^3)^4)^x Then, 1/2 is correct. In the latter case, tho, you'd indeed be correct.
While (x^n)^m = x^(n*m), that's not the case for x^(n^m). I'd say the given problem is meant to be 2^(3^(4^x)) Not ((2^3)^4)^x In the latter case, tho, you'd indeed be correct.
While (x^n)^m = x^(n*m), that's not the case for x^(n^m). I'd say the given problem is meant to be 2^(3^(4^x)) Not ((2^3)^4)^x In the latter case, tho, you'd indeed be correct.
Exponents are multiplied, 12x as exponent , for value 1 for x it becomes 4096, the other side is 512, which is 2 to power of 9, thus x becomes 3/4 the correct answer.
@@cyruspersia3436 While (x^n)^m = x^(n*m), that's not the case for x^(n^m). I'd say the given problem is meant to be 2^(3^(4^x)) Not ((2^3)^4)^x Then, 1/2 is correct. In the latter case, tho, you'd indeed be correct.
quick but systematic method
2^3^4^x=512=2^9
3^4^x =9=3^2
4^x =2
x=1/2
x = 0.5 512 = 2^9. Pretty simple after that.
According to my simple common sense x=1/2
edit: I checked my answer it seems correct!
Yea. Root of 4 is 2, 3 squared is 9, 2 to the 9 is 512
x = 1/2.
Didn't do any math until the end. 3^4 is 81 way to high. Is x is 0 then 4 becomes 1 but 2^3 wouldn't be enough. So it has to be between 0 and 1 and 1/2 or square root makes sense
Which one was the impossible one? Hopefully not the first. I did it in like 10 seconds
2^3^2 = (2^3) * (2^3)= 2^(3+3) = 2^6 = 64
but
2^3^4^x = 2^(3*4*x) = 2^(12x) = 2^9 = 512
therefore x= 0.75, NOT 0.5
While (x^n)^m = x^(n*m), that's not the case for x^(n^m).
I'd say the given problem is meant to be
2^(3^(4^x))
Not
((2^3)^4)^x
Then, 1/2 is correct.
In the latter case, tho, you'd indeed be correct.
x = 3/4
2^12x = 512
12x = 9 => x = 3/4
While (x^n)^m = x^(n*m), that's not the case for x^(n^m).
I'd say the given problem is meant to be
2^(3^(4^x))
Not
((2^3)^4)^x
In the latter case, tho, you'd indeed be correct.
according to me 512 = 2^9 so 3*4*x = 9 therefore x = 9/3/4 = 0.75. Checking 2^(3*4*.75) = 2^9 = 512 QED
While (x^n)^m = x^(n*m), that's not the case for x^(n^m).
I'd say the given problem is meant to be
2^(3^(4^x))
Not
((2^3)^4)^x
In the latter case, tho, you'd indeed be correct.
Exponents are multiplied, 12x as exponent , for value 1 for x it becomes 4096, the other side is 512, which is 2 to power of 9, thus x becomes 3/4 the correct answer.
@@cyruspersia3436 While (x^n)^m = x^(n*m), that's not the case for x^(n^m).
I'd say the given problem is meant to be
2^(3^(4^x))
Not
((2^3)^4)^x
Then, 1/2 is correct.
In the latter case, tho, you'd indeed be correct.