Concentration Changes Over Time - AP Chem Unit 5, Topic 3
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- Опубликовано: 14 окт 2024
- In this video, Mr. Krug shows how to determine the order of a reaction with respect to a reactant graphically. He also introduces integrated rate laws and works several examples with these important equations. He introduces and derives the first-order half-life equation and shows how this equation can be used.
![VENEZUELA vs. ARGENTINA [1-1] | RESUMEN | ELIMINATORIAS SUDAMERICANAS | FECHA 9](http://i.ytimg.com/vi/SJfoPdeOPCQ/mqdefault.jpg)
The fact i can understand this guy’s vids better than the AP Videos says a LOT.
I try to make my videos easy to understand for everybody. Thanks for watching!
AP classroom went down the day before my unit 5 test. This is a lifesaver!
I'm glad you were able to use my videos even though AP classroom went down. I hope your Unit 5 test went well!
jeremy krug, the newlyfound goat of ahs
A big shoutout to everybody in AP Chem at AHS. Thanks for watching!
Thank you so much. Your explanation really helped clear the confusion.
I'm very glad to hear that. Kinetics can be tough, but you can do this!
My son is currently going through AP Chemistry and these videos are super helpful for him! Thank you for all of the help!😊
You're very welcome. I'm glad to hear your son is able to use my videos to help him in class. Best wishes as he gets ready for the AP Exam!
I have a question: Where did the graphs of 0th, 1st, and 2nd order come from? How were they derived? What are the reasons why the graphs are assigned to their orders? Also, what does an order for a reaction mean? What is its definition? Thanks!
It's because that how the graphs of their respective functions look like
Btw guys for the formula: ln[A]t - ln[A]0 = -kt , you can replace the square brackets with normal brackets “()” so that your calculator doesn’t give you a syntax error.
Good idea, thanks for sharing!
Good job sir,mor grace
Thanks for watching!
In your video, at time 14:00, how did you get the units to be s^-1? Since the question asks for seconds, would you just completely ignore the concentration unit?
Good question. When you take the natural log on the left side of the equation, you end up with a 'unitless' value. Therefore, we need the same on the right side. The time unit (seconds) needs to cancel out with the reciprocal of time (s^-1). Thanks for watching!
You are an absolute lifesaver, thank you so much!
So glad you’re finding my videos helpful. Thanks for watching!
Wait hang on how did you get 0.051 from -2.973? 😅
Take the negative anti-natural log of -2.973. On your calculator, evaluate e^-(-2.973).