Sir you saved me. today is my exam. And i was scared bcs I was learning these concepts from so long but couldn't do it. and i was helpless. I am so happy I found your video 🥺 thanku so much🥺
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Thnku sir ...bda dar lgta tha is chi square test se ..bda hi complex topic lgta tha ye ...but thnx again sir ..u make it very easy for understanding purpose 🙏🙏
Everything is just so good , but if you could just hear a request sir . Kindly keep a check on the clarity of the board , sometimes things are not visible .Thanks
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sir i have a doubt, what will happen if more than 1 expected value is less than 5, (r-1)(c-1)-n? will we do this to find the degree of freedom, please do reply sir.
Thank you for this video this really helped😊 but I just have one clarification , why aren't rounding off the numbers for example at 15: 01 , 1600/60 = 26.666 why aren't we rounding off to 26.7 ?
sir can you please explain why you took null hypothesis as : techniques are not significantly different. Why not "The techniques are different(independence of attribute)". I saw the video several times but couldnot understand. Thank you sir
Whenever we have to set null hypothesis it is always equal to type. It is asked in questions see at 18.49 Hope this will help you Download our app Gourav Manjrekar Academy from playstore. It's free
Nice one but brother if we get expected values below 5 three time i.e Fe having numbers 23,23,3,4,2,20 like than degree of freedom will be (2-1)*(4-1) - 3 like that .
It will be accepted. Its just a rule that in chi square test the expected frequencies must be at least 5. It have no relation with the degree of freedom.
Dear Sir, Time 26:00 4 divided by 31 =0.129 But your value is different. So, this also affects our ans. Please sir. Make us sure that which one is correct?? 🤔
I have a doubt, how can we decide that Ho will not be "Two methods are significantly different" why we took Ho as "They are not significantly different" Can someone please help me... i am really confused.
When any expected frequency is less than 5 then to make it more than 5 we pooled expected frequency. That why we lost 1 degree of freedom more. So we have original df as ( r-1) (c-1) = 3 . Now we pooled expected frequency then we have 3-1 = 2 df 👆👆
in the second ques why did we take the null hypothesis as they do not differ why didn't we took they significantly differ please someone clarify my doubt
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There is no better channel for statistics than your channel. Great work. Grateful for your efforts.
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@Gourav Manjrekar I will not share your channel with my friends, because if they found you they will score better marks than me
@@ramgupta4535 then you are not a good friend
Amazing lecture. You saved my day and regained my confidence level. Thank you tonns!!
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Sir you saved me. today is my exam. And i was scared bcs I was learning these concepts from so long but couldn't do it. and i was helpless. I am so happy I found your video 🥺 thanku so much🥺
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very helpful video sir😍
take love from Bangladesh 🇧🇩🇧🇩
Wow sir ap kitna sequence mai likhte hai...may God bless u sir
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Thnku sir ...bda dar lgta tha is chi square test se ..bda hi complex topic lgta tha ye ...but thnx again sir ..u make it very easy for understanding purpose 🙏🙏
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Thank you sir for making learning stats so easy. Tomorrow i have my exam and I feel confident after watching your videos ☺️
Amazing explanation, watching one day before exam and understood the concept.
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Amazing lecture sir! I'll be very grateful to you if upload video on sign test, median test , mann-whitney- wilcoxon test :)
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Everything is just so good , but if you could just hear a request sir . Kindly keep a check on the clarity of the board , sometimes things are not visible .Thanks
Great teaching, great content, thank you sir 🙏
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Thank u sir
Ur explanation is super I learnt very easily chi square with ur calculation
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Thankyou so much sir, its because of you I am able to understand statistic so clearly...
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Thank u so much sir you are really doing great work
Thanks and welcome
Thanks sir for your awesome teaching 😊
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It's very useful lecture for me 🙏thank you sir 👍
Most welcome
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Amazing lecture sir.....!
Definitely your efforts help us....
Thank you very much...sir 🙏🙏🙏🙏
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Thank u sir... Its really informative
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Why null hypothesis was not taken as both the sampling techniques are different ?
In ques 2!!
Very helpful 🎉
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Sir pls make video on ordinary lest square method
Amazing explanation 🙏👍
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sir i have a doubt, what will happen if more than 1 expected value is less than 5, (r-1)(c-1)-n? will we do this to find the degree of freedom, please do reply sir.
Yes, Where n = number of time you pooled expected frequency
@@GouravManjrekar Thankyou so much for the reply sir.
Nice one... Bless u
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Great explanation sir
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Best videos....😊
Thank you for this video this really helped😊 but I just have one clarification , why aren't rounding off the numbers for example at 15: 01 , 1600/60 = 26.666 why aren't we rounding off to 26.7 ?
Thank you sir..🙏🏻
Good explanation
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sir can you please explain why you took null hypothesis as : techniques are not significantly different. Why not "The techniques are different(independence of attribute)". I saw the video several times but couldnot understand. Thank you sir
Whenever we have to set null hypothesis it is always equal to type.
It is asked in questions see at 18.49
Hope this will help you
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@@GouravManjrekar Thank you very much sir
@@GouravManjrekar Sir in that case, in 1st math why didnt we take null hypothesis as "there is association"
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@@mehedipial9116 bz it's is test of independence which means no association
Nice one but brother if we get expected values below 5 three time i.e Fe having numbers 23,23,3,4,2,20 like than degree of freedom will be (2-1)*(4-1) - 3 like that .
Yesss
Same doubt
It will be accepted. Its just a rule that in chi square test the expected frequencies must be at least 5. It have no relation with the degree of freedom.
Sir u r so good
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So nice Sir ji
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Bahut achcha
Sir what will happen if we don't merge the last two values 25,2
Is our answer will be same
sir H0 is there is no association between rows and columns implies techniques adopted by 2 researchers are different . But you wrote contrary to this.
See video again I have told meaning also
Thank you sir so much
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Sir agar chi square ki valu table value se kam ho to null hypothesis reject nhi hoga?
Null hypothesis should be there is no association between quinine and fever
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Hello sir,
can you cover ANOVA topic in your upcoming videos?
Yes of course ....
Keep watching videos on every Monday Wednesday and Friday at 8:00AM on our Channel about Statistics.
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ruclips.net/video/8DaOIjuF4BY/видео.html ANOVA
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Hello sir
Mujhe koi book ka na bta do jis mein practical question kyuki concept to clear hai bs practise krni hai example ke sath
Mathematical statistics by sc gupta , Kapoor,
Fundamental of statistics by DN Elhance
Dear Sir,
Time 26:00
4 divided by 31 =0.129
But your value is different.
So, this also affects our ans.
Please sir.
Make us sure that which one is correct?? 🤔
By mistake we write 4/31 as .012 but correct value is .129
Final answer has no effect by this value.
Also 4 divided by 84 =0.0476 24:45
if the summation of original frequency and expected frequency are not the same then in that case how to solve it?
What If the expected frequency is exactly equal to 5 ?
It will be accepted. Its just a rule that in chi square test the expected frequencies must be at least 5.
@@scubeap Okay thank you 😊
Nice
I have a doubt, how can we decide that Ho will not be "Two methods are significantly different"
why we took Ho as "They are not significantly different"
Can someone please help me... i am really confused.
thankyou sir
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Sir what to do if frequency is less than 50 in total
Second question me d.f( r-1)(c-1)= 3 hoga sir aapne 2 kyu liya
When we pooled expected frequency then we love one more degree of freedom
Hope this will help you
@@GouravManjrekar sir I understood what you did in that problem but can u explain one more time why you subtracted 1 one from 3
When any expected frequency is less than 5 then to make it more than 5 we pooled expected frequency.
That why we lost 1 degree of freedom more.
So we have original df as ( r-1) (c-1) = 3 .
Now we pooled expected frequency then we have 3-1 = 2 df 👆👆
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App kaun se book se question lete hai wo batae please
Mere college me bhi yehi questions dete hai par book ka naam nahi pata
SC Gupta and VK kapoor
in the second ques why did we take the null hypothesis as they do not differ why didn't we took they significantly differ
please someone clarify my doubt
how to calculate tabulated value 3.84
See χ2 table for v=1
Sir, total chi value is 0.923 not 0.911
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Ty bro sir
bhai tu bhagwan hai!!!
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why we use chi square for independence of attributes?
See video 2 of below playlist
Chi Square Distribution and Chi Square Test: ruclips.net/p/PLRNL7AjA6rjxVTlKSB4TNFY8y5qKF-mQa
Clear nhi h show ho rha
Sir
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