Limiting reagent🔥| Mole Concept | Physical chemistry | Class11 IIT JEE & NEET | Anushka mam
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Al=n=2.7/27 =0.1moles
N2=n=2.8/28 =0.1 moles
Al=0.1/2=0.05
N2=0.1/1=0.1
Al is limiting reagent
Molecular weight of AIN =41
2moles of al gives 2 mole of ain
0.1 mole of al gives 0.1 mole of AIN
AIN formed =0.1×41
=4.1 grams
Bro why not we take 0.05 *41 ??
because limiting reagent is Al
@@devanshtyagi5868
@@devanshtyagi5868same ques?
Thank you very much brother
@@devanshtyagi5868it is done just to find the limiting reagent
2024 25 batch attendance 😂😊
Answer of last home work question is 4.1g and the limiting reagent is Al ❤️❤️
B.t.w great explanation mam
Can you send a pic / solution for he question
Answer 2×2.05 gram hoga
@@thestraightboy4549 nahi 4*1.025 hoga
Kya difference hai @@ShortEditZ69
4.1 gm AlN and limiting reagent is Al , you can take a feel using unitary method in reaction
2mol Al → 1mol N2
1mol Al → 0.5 mol N2
0.1 mol Al → 0.05 mol N2
But we have 0.1 mol N 2 so half of N2 will react and Al will end so limiting reagent is Al , now
2 mol Al → 2 mol AlN
1mol Al → 1mol AlN
0.1 mol Al → 0.1 mol AlN
0.1 × mass of AlN =
0.1 × 41= 4.1g .
Thank you mam ❤
Thnx 😢
I loved the starting example that mam gave to crystal clear the topic of L.R...❤Thanks a lot maam😊😊
Mam aap bahat achhe se explain karte hein jo doubt school me clear nahi ho pata wo aap kar dete hein. I am in class 10th icse course
Thankyou mam.....🙏☺️
Kya samjhati hai mam. Kisi ko bhi ekdam samjh aa jaega. So proud of you mam. We want all teachers in India like you.
No shit
no shit #2
no shit #3
No shit#4
From my initial days of this phase I didn't have crystal clear idea of Limiting reagent and now by your wonderful way I understood completely 😊.
The shortcut was also easy to remember
mam..I searched many vedios but...now my obstacles are clear about limiting reagent..thank u taught nicely with good example at first
You are welcome 😊
"Vedio"? "Obstacles"?
@@aadityavilassharma1802 🤣🤣
@@aadityavilassharma1802 The spelling of obstacles is correct tho lol
@@omgggwowow276 spelling of tha is incorrect....lol😂
In homework limiting reagent is Al and AlN is formed 4.1 gm.
H.W: 2.05 g of AIN will be formed
4.1g
Wrong
Bro I got same as 2.05g😊😊
this is the correct answer in all comment option my answer is also same
Thanks maam all the concepts are crystal clear 💕💕💕🥰
One of the best chemistry teacher on RUclips thanku so much mam
The answer to H.W's question is 4.1 grams... BTW, amazing explanation ma'am. All my doubts are cleared. Thanks..
How?? Mine was 4g
Mine also 4g!!!
How my answer is 0.82
Same.. 4.1 grams
My answer. 2 grams
Aluminium is Limiting reagent and 4.1 g of AlN is formed
mam 4.1 is the answer of homework question
u r teaching very nice
keep it up
2.05
Ans of homework: limiting reagent is Al and mass of AlN formed is 4.1gm
Mam answer is 2.05gm ir 4.1 gm
Same
Anushka mam is truly 🐐 🔥she is amazing teacher ❤️
AL is the limitting reagent......
And mass of ALN formed .....4.1 g💕
Thank you for making it easy 😇
Kesa aaya answer
Exactly and moles of AlN is 0.1 as. 0.1 moles of Al and then to find the mass of Aln we'll multiply 0.1 with 41=4.1g
Hello
@@farwakhan9155 can u pls tell me full on insta? Pls?
noh answer is 4.1g but limiting reagent is nitrogen
I am preparing for NEET in Aakash institute.But I can't understand this concept.This video is really very helpful for me.Thank you so much ❣️
Aapka AIATS hoga isliye aap ise dekh rhe ho
Same
Same
I am also preparing for NEET in Aakash Institute
In which branch are you studying in Aakash institute
The best explaination video of limiting reagent...i had not understand from any of the teacher the limiting reagents concept...but here i understood all the things
..thankyou so much MAM
👑THE CHEMISTRY QUEEN👑
The Answer is 4.1 gram of ALN....😊
Very good session mam.... CRYSTAL CLEAR 👍😘
4.1 aayega ya phir 8.2
@@adarsh_0724 8.2
8.2@@adarsh_0724
The way you taught this topic really awesome.
Thanks for such kind of short video for single concept this helps a lot students like me.❤
Thnku so much ma'am now I get it very well☺️😍
Its limiting will be Aluminium and the mass of ALN is 4.1gm
There’s no other way that can be simple than this one......
You are the right teacher for chemistry ❤❤❤thank you
Her, "Rrrrrrightt" is so goood. Awesome lecture!
Superb superb superb explanation ma'am👏👏🤘🤘😃😃💗💗you explained this topic in a very interesting way😊😊😊😊😊😊
A very good session of physics, I wasn't distracted even for a second
it was chemistry friend.
@@sastikanandi1063 😂
It's chemistry.....😒
Keep Loving Btw it was chemistry 😁
@@atpstarphysics Oh, was it? Sorry I was lost in your eyes
The ans of the home work is.. 4 . 1
Th L.R. is Al in this question. ... & thank u so much madam... wonderful explanation. .. nw I've no doubt in this part...
I read in aakash kota mam waha se padha but aap unse kafi accha padhate ho.
For me , you are best chemistry ⚗️⚗️ teacher ♾️ forever'
This mam is my favourite mam and I like her teaching so much .
18:11 for the hw i am getting 5.5 as the 2 in 2AlN applies to both Al and N. does the 2 only apply to Al cuz all the comments say it is 4.1. Can anyone clarifyy…
Yes I also think so
I am fully confused why
Kahi se bhi prr lo.. jo dhyan se padta hai usko sab jagah samjh aa jaata hai..
Dhyan se padne se hi sab kuch samjh aata hai... Thank u mam for best explanation...
Keep watching
those who cant find the ans for the hw ques it is 4.1 g
Into 2 karna bhul gaye
Correct answer is 4.1 g
Thanks a lot ma'am for making our concept clear. Now I will struggle with the questions of limiting reagent
4.1 gm mass of ALN and AL is the limiting reagent
Good session mam♥️
True 🐦
Yes it's right
Thnkuu mam😄 I was finding this topic. Very difficult but it is very simple
Mine ans is 2.05 gm
Unitary method se 4.1 gm
Bro not 2.o5 g its 20.5 g 😂
Yaha Mam ki Good Explanation ke Regarding Comment Kr K hum ATP STAR Physics ke jale pr namak chidak rahe hai😂😂😂😂😅😅
Mujhe limiting reasent concept hi weak tha...vo bhi aapne pdaya to....strong bn gya..😍😍😍😘😘😘
Ma'am avogadro no of thanks to you for this nicee explanation 🚶♂️
🙂
Now..... new class,new josh , new teacher,new masti but old we 😅😅
Best of luck for every jee/neet aspirants 🌚
[18:11] is it *4.1g* ? 🙂
too helpful ty Anushka Ma’am!
Mam I searched many videos but now my obstacles are clear about limiting raegent thanks a taughty nice alay
Abey kya kya bole ja rha hai😅
When study and distraction comes together 😶😶
Oye ma'am kitna acha padhate hai
Aisa mat bol unki mehnat pAr bhi dhyan do
Home work question ka ans 4g AlN formed and Al is the limiting reagent
At 18:6 timeed
2.7÷27=0.1
2.8÷14=0.2
0.1÷2=0.05
0.2÷1=0.2 then LR is Al
27×2 =54
14×2 = 28
0.05×(54+28) = ans is 4.1 😅
HW ans-4.1g AlN
The ans for the hw question is 4.1g
Mass of AlN formed Is 4.1 g.
(Answer of the last question which was given in homework ).
Ma'am you are the best chemistry I have ever met bcs of u I have developed interest in chemistry i am a dropper hated chemistry but after watching u i am now studying chemistry 🧪.love you ma'am 😍😍
Phir drop lega tu
Abaye sale😄😂🤣
Limiting reagent is (Al) and mass of AlN is 4g
Mam the answer I am getting is 2.05 gram, coz I took stoichiometric coeffient =2, how everyone is getting 4.1 gm, why we need to took 1 value for SC,?? Can anyone explain pls?
Finding limiting reagent -
For Al 2.7/27×2= 0.05
For N2 2.8/28 = 0.1
Hence Al is limiting reagent.
If 2 moles of Al gives 2 moles of AlN than 0.1 moles will give 0.1 mole of AlN.
0.1 ×(41)=4.1
@@abhisheksangwan1066 tysm bro 🙏💯❤️
Understood
Mass of AIN is 4.1 gm
Same
Very Conceptual Example Great.
4.1 answer of AIN and also thanku mam
I am currently in class 11 and watching this video since tomorrow is my chemistry exam ❤❤❤❤❤😂😂😂🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉
Now I am getting why Anushka ma'am is famous 🎉
Hw ans( 4.1 g )
Best teacher ever. Got my concepts crystal clear. Thanks a lot
miss anushka you are the great one in the world for me watching from afghanistan 🇦🇫🇦🇫🇦🇫🇦🇫🇦🇫
Very good explanation 👏 thanku ma'am
Always welcome
Ma'am yrr tussi great ho.🥲khushi ke aasu. Apne Mera doubt clear kardiya
Nice teach mam I love u mam and love ur teaching tq so much mam for clarification all the subject clearly ❤️❤️❤️
It's my pleasure
homework limiting reagent is Al and AlN is formed 4gm
Simple trick -Limiting reagent is the one which has the least value of - no of moles÷stoichiometry coefficient
Tq so much ma'am our school teacher doesn't teach us well but after watching this video all my concepts are crystal clear
H.W ans = 4.1 gm
I am in 10th class and preparing for Olympiad....
Thanku mam
Perfect lecture for limiting reagent I understand this concept ❤️
AlN :- 41×0.1 = 4.1g ans
Ur smile makes more interesting to watch ur video 😊😅❤❤
Mam , 4.02 gm is the mass of AlN , is it correct??
Pls mam reply me
It's a humble request
And teaching style is awesome ,this topic is crystal clear to me
Thanks a lot 🤗🤗 🤗
No
4.1
4.2
2.05gm
Nhi, 4.1 hoga..because last mei 0.05 mole leke mass of AlN calculate nhi krna hai, 0.1 leke hi karna hai
Because 0.1/2 (for Al) to bss check krne ke liye liya tha, working ke time 0.1 leke hi kaam krna hai, bcoz hmare paas 0.1 mole of Al hai naki 0.05(limiting reagent ko pura use krna hai)
So, mass of AlN = no. of mole of AlN * molar mass of AlN
= no. of mole of limiting reagent (Al) * molar mass of AlN
= (0.1 * 41) g = 4.1 g
@@kenxi_editZ thanks for the explanation
Thanku mam
Beauty+brain 🧠 Mam's
😊
18:11 The answer is 5.5g AlN ?
4.1 g may be
4.1 absolutely right
4.1 g is the correct one
Thanks a lot Mam .... 😊😊
This mam is crystal clear thank you for explaining us
Mam can we use this trick in half yearly exam for class 11
yes Hema
Mam 16.12 min me jo question karaya aapne usme aaone thoda galti kiya hai 1/2 02 ka molecular mass 16 hoga jab ki aapne liye hai 32
Mine answer is 2.05g and think it's correct 👍
Yeah..
But most of the people in the comment section are saying that 4.1 is the correct answer
@VIRAT ERA CLUB ooh niceee..😇
I'm so confused...I can't find the solution 😕
Very nice explanation ❤❤
Mam is trick se mera ncert chapter 1 ka question 1.24 nahi solve ho rha plzz ap ek video bnao ncert ke sare question pe
8.2 g ans is right
I have seen too many videos regarding limiting reagents but my doubt got clear by seeing your video mam
Thanks a lot mam❤️
Most welcome 😊
Best teacher 👏❤️
Thank you! 😃
Mam u r so cute and you explanation is excellent ☺️☺️
Mam can u send ur no...
Answer of homework question is 4.1g 😊😊
Thank u for such a great concept
Thanks Maam ans:-4.1g of HW concept crystal cleared!
last Q. ans - mass of ALN is 4.1 g
mam i love your teaching method
🥰😍
Anyone pls explain... In other problems, we take no of moles of AL as 2 - as 2Al is given. But here we take this 2 as stoich.coeff. it is confusing...
Thank you so much ma'am ❤❤🙏🏻🙏🏻🙏🏻 it was amazing i understood properly now that limiting reagent is not a big topic that can stop us from completing our mole concept chapter😊😂
Thank you so much ma'am ❤️
Most welcome 😊
Homework question answer
4.1g
Ma'am lm science and fun ashuu sir student and I love you sooooooooooooooooooooooooooo muchhhhhhhhhh ma'am ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉 really mam ....anushka mam ❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤
Exam are near
Nothing is clear
Students is fear
I have not fear
Because...our chemistry queen is here ❤❤❤❤❤❤❤ANUSHKA MAM ❤❤❤❤❤❤❤❤❤❤❤❤❤
Shut up man