Mole concept | Stoichiometry | Physical Chemistry | Class 11 | anushka mam | ATP STAR

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[@khushi7012]

Q1: mass of CaO?
If one mole of CaCO3 gives 1 mole of CaO
Then 1/4 mole of CaCO3 gives 1/4 mole of CaO
For mass, multiple mole and molar mass
Mole x molar mass
1/4 x 56
=14g ans
We can also calculate it by another method
Like we know that mass of CaCO3 and CO2 is 25g and 11g respectively.
So, mCaCO3 = mCaO +mCO2
25g = mCaO + 11g
25g - 11g = 14g CaO ans.

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Now fully satisfied to solve question related to stoichiometry 👍👌

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I am happy simple interesting solutions

[@Srabani-sr458.]

Thanks ma'am. 🎉🎉❤❤

[@mohanji1317]

Amazing mam thanku so much I really thinks it will helps me a lot😊
again Thanku mam😊

[@user-wx1iy1sn4u]

Such concept bahut mast hai thank you so much mamm

[@patil-b6o]

mam we can put two in H and in H2O we can add 2

[@Yoyo7bts]

Mam for Cao answer is 14g

[@SayaliNaik-le6ob]

Thanks mam😊

[@prp7]

Thanks a lot 😀

[@Anand-ih8vz]

Pls advise - why we don't check limiting reagent here ?

[@somanshkapoor7008]

Bro kyunki hame zaroorat hi nahi hai

[@The-S.J.QxEdits]

Limiting agent gets applied when both the the reactent have given a value

[@deepikajakhar9537]

Last me to sirf volume thi isliye direct volume se hogya ... Jo kam volume thi usse.. Aap limiting reagent bhi check kr skte ho

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[@neelampatel8754]

Given mole or given weight upon sciometric culculation (here which are less to be. Able to limiting agent)SIMPLE/////

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Thankful ❤

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Bhai ma'am ko dekhne aaya tha kya?😂😂

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Thank you so much mam

[@studystrategy174]

Mam it was an amazing lecture mam 😄👍🏻

[@DivyangChaudhari-rn8nz]

cao mass =14gram

[@user-bq3mm2du3w]

Want lecture of Graphical analysis and based numericals.. Those r given in arihant vol. 1

[@user-yaseen123]

Thanks madam

[@karanraut9666]

Cao Weight 14gm

[@sidrashamim4153]

❤

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Heyyy cute

[@yousafrehman1657]

If condition is not given at STP then how will be volume measured?

[@saniyadeokar10]

Nhi kr skte Kyunki gas ki volume fix nhi hoti

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Mam u help me lot mam to explain very
Detailedly this concept

[@bantykori6880]

Aaj tak try kar rahi h lekin aaj samajh me aaya thank you so much mam

[@user-ur8zo3te7j]

cao is 14 gram

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😂😂😂

[@satyamnayak2179]

Love you madam
❤

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Thanku mam ☺️

[@9eomkarrameshwavrewavre121]

44.8

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Yes You are my anushka mam😂

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Aapki video kab khatam ho gyi pata he nahi chalta

[@harshaa_x]

Concept acha laga kyu ki aap padha rahe the

[@mahnooryounas8203]

Good concepts

[@sakshirani5075]

14g cao ka

[@kubernagla8691]

17grams

[@shivamramusolanki6425]

Volume is 44.8

[@rbmusic9414]

Maja ageya mam

[@kushankurbanerjee]

mam how can o have 1/2 stoichiometric because molecules cannot be in fraction ??......also by putting 2H2 + 02-----> 2H2O

[@ajaymudhiraj8018]

It is another method in thst we can easily get answer 😅

[@Sari_ka2596]

Baat to same hi hai

[@user-px7cg8vb1l]

is mass mass relation ship also called mole mole relationship???????????
and what mole mass relationship is called ??????????
and also mass mass relation ship is called and mole mole ????????????????/

[@ambreennaeem1751]

14g of CaO will form

[@user-gc4dd7yt6w]

Mam constration of term ka lecture upload Karo in one shot

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Tip - Set your playback speed on 2x 😂😂😂😂

[@RiteshGupta-xx2wm]

Doubt*
jaise ki apne ise H2+O2-----H2O Aisa balance Kiya hai 1H2 + 1/2O2----2H2O toh hum ise aise bhi toh solve kar sakte hai na mam 2H2+O2-----2H2O

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Ha mene bhi yahi socha

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Yes ye bhi right hai

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[@SainathKadam-hd7uq]

14 gram

[@samarthshri29]

Thankyou so much ma'am

[@SunehaVerma-zq6mm]

14g

[@Okiedokieyes]

Ma'am next please equivalent plz plz and redox titration

[@atpstarphysics]

Yes we will cover that

[@amitadevi6694]

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[@9eomkarrameshwavrewavre121]

14agaya

[@aniketgamerff4938]

Cao ka hoga 4/56= 14g

[@MRashidSolangi]

Hi

[@cookwithshreemahalaxmishar7367]

Ma'am mein sachme bas ghabra rahi hoon baaki easy bohot hai ....

[@Pawankumarsharma-fb1jk]

Hay

[@AnkitKumar.0]

Mam aap yaha kaise

[@ahmedfaraz6421]

Mam 14 g

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Thanks from Pakistan 🇵🇰

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hello ma'am i am in class 9 but i wat to crack neet so i am prepairing for it from now by studying some portions of class 11th and so plz can you suggest me a study plan so that i can handle both my 9th and 11th class terms

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Nice

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the thumbnail is not matching to the video

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14g of cao

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Mole concept full lecture

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Kirrush hai mam❤😂😂

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5:00 Hume balance Krna aata h mam🙃

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Mam please reactions karna bata do

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Hii

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Sweet and lovely teacher

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Thank you! 😃

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🥳awesome🥳🥳

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Thanks & stay connected 🤩

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Thanks 👍

[@AnkitBabu995.]

why you tell us wrong mamm because stp= 22.7 l understood

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[@tejaschaudhary6469]

Cao mass = 14gram

[@anshjaat123]

Volume at STP =22400 lete h hum to

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Bro wo mL me lete ho aap

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No mam samaj nai aya

[@shivamramusolanki6425]

Mass of CAO is 14 gram

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Mam kuchh samajh me nahi aaya

[@kiranjitsheron2330]

Mujhe bhi nhi aa rha 😔😔🥺smj nhi aa rha kaise kru

[@Okiedokieyes]

14gm

[@Okiedokieyes]

14gm of CaO

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Kuch smjh nhi aaya

[@arshadiyi9991]

Can't understand

[@vashchoudhary]

Ma'am 14 gram hoga

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jee wale bache title nhi thumbnail pr mam ko dekh kr aaye h😅😅

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14 gram

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❤

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14g

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14 gram